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Physical Chemistry 3: — Chemical Kinetics — - Christian-Albrechts ...

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8.3 Generalized Lindemann-Hinshelwood mechanism 186<br />

I<br />

Answer: We are asking for the number of distinguishable possibilities to distribute <br />

quanta between oscillators, (). This is identical to the problem of distributing <br />

balls between boxes, for example for =11and =8:<br />

••• • • • •• • •• (8.45)<br />

That number is identical to the number of distinguishable permutations of balls ( • )<br />

and − 1 walls ( | ),<br />

( + − 1)!<br />

() = (8.46)<br />

!( − 1)!<br />

where ( + − 1)! is the total number of permutations, which is corrected by dividing<br />

through !( − 1)! to account for the number of indistinguishable permutations among<br />

the balls (!) andwalls(( − 1)!) among each other (which give indistinguishable results).<br />

I Answer: We make the following approximation for À : 49<br />

( + − 1)!<br />

!( − 1)!<br />

≈<br />

−1<br />

( − 1)!<br />

(8.49)<br />

I<br />

Question: How can we compute ()?<br />

I<br />

Answer:<br />

() =<br />

()<br />

<br />

(8.50)<br />

(1) We consider the energy interval<br />

∆ = (8.51)<br />

at the excitation energy<br />

= × (8.52)<br />

In this energy interval, we have the number of states<br />

∆() = () (8.53)<br />

y<br />

() =<br />

()<br />

<br />

∆ ()<br />

≈<br />

∆ = 1 ( + − 1)!<br />

!( − 1)!<br />

(8.54)<br />

49 The approximation<br />

( + − 1)!<br />

≈ −1 (8.47)<br />

!<br />

can be derived using Stirling’s formula (ln ! = ln − ) and the power series expansion of<br />

for || ¿1 (see homework assignment).<br />

ln (1 − ) ≈ (8.48)

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