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Physical Chemistry 3: — Chemical Kinetics — - Christian-Albrechts ...

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7.1 Foundations of transition state theory 151<br />

• −→ ‡ = −→ ‡ is the mean speed of the molecules crossing the DS in the forward<br />

direction.<br />

(6) We now use the equilibrium constant to determine ‡ via<br />

‡ = ‡ ABC<br />

A BC<br />

(7.18)<br />

y ‡ = ‡ ABC = ‡ A BC (7.19)<br />

y<br />

−→ −→<br />

‡ <br />

‡<br />

=<br />

‡ A BC = A BC (7.20)<br />

with<br />

−→<br />

<br />

‡<br />

=<br />

‡ (7.21)<br />

(7) From statistical thermodynamics (see Appendix G), we have the following expression<br />

for the equilibrium constant ‡ ( ) in terms of the molecular partition<br />

functions:<br />

‡ ( )=<br />

∗ <br />

=<br />

µ<br />

<br />

exp − ∆ <br />

0<br />

(7.22)<br />

<br />

• The ’s are the respective molecular partition functions (per unit volume).<br />

• ∗ is written with respect to the zero-point level of the reactants.<br />

• The exp (−∆ 0 ) factor arises subsequently, because we now express<br />

the value of partition function for the TS relative to the zero-point level of<br />

the TS ( ∗ = exp (−∆ 0 )).<br />

(8) Separating the motion along the reaction coordinate ‡ from the other degrees of<br />

freedom, we write<br />

= ‡ ‡ <br />

(7.23)<br />

where ‡ is the 1-D (translational) partition function describing the translational<br />

motion of the molecules along ‡ across the TS and ‡ <br />

is the partition function<br />

for all 3 − 7 other (rotational-vibrational-electronic) degrees of freedom.<br />

Here,<br />

• the 1-D translational partition function is<br />

‡ =<br />

µ 2 <br />

2 12<br />

× (7.24)<br />

• the mean speed along ‡ for crossing the DS in the forward direction is given<br />

by<br />

R<br />

−→ ∞<br />

‡ −2 2 µ <br />

<br />

12<br />

0<br />

= R ∞<br />

−∞ −2 2 = <br />

(7.25)<br />

2

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