Physical Chemistry 3: — Chemical Kinetics — - Christian-Albrechts ...

Physical Chemistry 3: — Chemical Kinetics — - Christian-Albrechts ... Physical Chemistry 3: — Chemical Kinetics — - Christian-Albrechts ...

21.10.2014 Views

5.2 Kinetic gas theory 109 I Correct derivation of the gas pressure and the ideal gas equation: • Likewise, we take the differential number of wall collisions for specific speeds(Eq. 5.83) to compute the momentum change ( ) in time ( )=2 | |×| | × ( ) ( ) ( ) (5.93) • Inserting again the 1D-Maxwell-Boltzmann distributions and integrating over all positive and all ,wefind the total momentum change in time : µ 32 = × 2× 2 Z ∞ Z ∞ Z ∞ µ 2 exp − 2 2 0 −∞ −∞ µ µ exp − 2 exp − 2 2 2 • Pressure for = µ 12 again using the substitution = 2 y y = = = µ 12 × 2 2 µ 1 12 2 2 Z ∞ 0 Z ∞ 0 (5.94) µ 2 exp − 2 (5.95) 2 2 −2 = (5.96) = (5.97) Thus, we have fixed our earlier simple derivations by appropriately integrating over the Maxwell-Boltzmann velocity distribution of the molecules.

5.3 Transport processes in gases 110 5.3 Transport processes in gases 5.3.1 The general transport equation I Definition of the flux −→ J of a quantity: We consider a generic transport property Γ (5.98) which differs in magnitude along the direction, i.e., has the gradient grad Γ (5.99) The flux of Γ throughanarea in time is defined as andcanbewrittenas −→ Γ = Γ (5.100) −→ Γ = − grad Γ (5.101) Kinetic gas theory allows us to derive a general equation for the proportionality constant . I Figure 5.8: Derivation of the general transport equation.

5.2 Kinetic gas theory 109<br />

I<br />

Correct derivation of the gas pressure and the ideal gas equation:<br />

• Likewise, we take the differential number of wall collisions for specific speeds(Eq.<br />

5.83) to compute the momentum change ( ) in time <br />

( )=2 | |×| | × ( ) ( ) ( ) <br />

(5.93)<br />

• Inserting again the 1D-Maxwell-Boltzmann distributions and integrating over all<br />

positive and all ,wefind the total momentum change in time :<br />

µ 32 <br />

= <br />

× 2×<br />

2 <br />

Z ∞ Z ∞ Z ∞ µ<br />

2 exp − 2 <br />

2 <br />

0 −∞ −∞<br />

µ µ <br />

exp − 2 <br />

exp − 2 <br />

<br />

2 2 <br />

• Pressure for = µ 12<br />

<br />

<br />

again using the substitution = <br />

2 <br />

y<br />

y<br />

= <br />

= <br />

<br />

= <br />

<br />

µ 12 <br />

× 2<br />

2 <br />

µ 1<br />

<br />

12<br />

2 2 <br />

<br />

Z ∞<br />

0<br />

Z ∞<br />

0<br />

(5.94)<br />

µ <br />

2 exp − 2 <br />

(5.95)<br />

2 <br />

2 −2 = <br />

(5.96)<br />

= (5.97)<br />

Thus, we have fixed our earlier simple derivations by appropriately integrating over the<br />

Maxwell-Boltzmann velocity distribution of the molecules.

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