Physical Chemistry 3: — Chemical Kinetics — - Christian-Albrechts ...
Physical Chemistry 3: — Chemical Kinetics — - Christian-Albrechts ... Physical Chemistry 3: — Chemical Kinetics — - Christian-Albrechts ...
5.2 Kinetic gas theory 109 I Correct derivation of the gas pressure and the ideal gas equation: • Likewise, we take the differential number of wall collisions for specific speeds(Eq. 5.83) to compute the momentum change ( ) in time ( )=2 | |×| | × ( ) ( ) ( ) (5.93) • Inserting again the 1D-Maxwell-Boltzmann distributions and integrating over all positive and all ,wefind the total momentum change in time : µ 32 = × 2× 2 Z ∞ Z ∞ Z ∞ µ 2 exp − 2 2 0 −∞ −∞ µ µ exp − 2 exp − 2 2 2 • Pressure for = µ 12 again using the substitution = 2 y y = = = µ 12 × 2 2 µ 1 12 2 2 Z ∞ 0 Z ∞ 0 (5.94) µ 2 exp − 2 (5.95) 2 2 −2 = (5.96) = (5.97) Thus, we have fixed our earlier simple derivations by appropriately integrating over the Maxwell-Boltzmann velocity distribution of the molecules.
5.3 Transport processes in gases 110 5.3 Transport processes in gases 5.3.1 The general transport equation I Definition of the flux −→ J of a quantity: We consider a generic transport property Γ (5.98) which differs in magnitude along the direction, i.e., has the gradient grad Γ (5.99) The flux of Γ throughanarea in time is defined as andcanbewrittenas −→ Γ = Γ (5.100) −→ Γ = − grad Γ (5.101) Kinetic gas theory allows us to derive a general equation for the proportionality constant . I Figure 5.8: Derivation of the general transport equation.
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5.2 Kinetic gas theory 109<br />
I<br />
Correct derivation of the gas pressure and the ideal gas equation:<br />
• Likewise, we take the differential number of wall collisions for specific speeds(Eq.<br />
5.83) to compute the momentum change ( ) in time <br />
( )=2 | |×| | × ( ) ( ) ( ) <br />
(5.93)<br />
• Inserting again the 1D-Maxwell-Boltzmann distributions and integrating over all<br />
positive and all ,wefind the total momentum change in time :<br />
µ 32 <br />
= <br />
× 2×<br />
2 <br />
Z ∞ Z ∞ Z ∞ µ<br />
2 exp − 2 <br />
2 <br />
0 −∞ −∞<br />
µ µ <br />
exp − 2 <br />
exp − 2 <br />
<br />
2 2 <br />
• Pressure for = µ 12<br />
<br />
<br />
again using the substitution = <br />
2 <br />
y<br />
y<br />
= <br />
= <br />
<br />
= <br />
<br />
µ 12 <br />
× 2<br />
2 <br />
µ 1<br />
<br />
12<br />
2 2 <br />
<br />
Z ∞<br />
0<br />
Z ∞<br />
0<br />
(5.94)<br />
µ <br />
2 exp − 2 <br />
(5.95)<br />
2 <br />
2 −2 = <br />
(5.96)<br />
= (5.97)<br />
Thus, we have fixed our earlier simple derivations by appropriately integrating over the<br />
Maxwell-Boltzmann velocity distribution of the molecules.