Physical Chemistry 3: — Chemical Kinetics — - Christian-Albrechts ...

5.2 Kinetic gas theory 108
• Result: 37
=
µ 12
×
2
µ 12 = ×
(5.88)
2
y
wall = µ 12
= ×
(5.89)
2
This can be rewritten using the mean molecular speed , because
With
we thus obtain the
wall = × 1 4
µ 16
2
=
12
= × 1 4
µ 8
• Final result for the gas kinetic collision frequency:
µ 8
12
(5.90)
12
(5.91)
wall = 1 4 (5.92)
I
Figure 5.7: On the derivation of the gas kinetic wall collision frequency.
µ 12
37 Notice that two of the three
factors in Eq. 5.84 above are compensated by the
2
µ 12
integrations over and ,onlyone
factor remains.
2