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Physical Chemistry 3: — Chemical Kinetics — - Christian-Albrechts ...

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5.2 Kinetic gas theory 103<br />

I Velocity distribution in 3 dimensions: Since the velocities in direction are<br />

independent, the probability that a molecule has a velocity between and + ,<br />

and + ,and and + is given be the product of ( ) , ( ) ,<br />

and ( ) :<br />

( )<br />

<br />

= ( ) ( ) ( ) <br />

µ Ã<br />

32 <br />

=<br />

× exp − ¡ ¢ !<br />

2 + 2 + 2 <br />

(5.62)<br />

2 <br />

2 <br />

We are, however, not interested in the distribution of velocities pointing into a specific<br />

direction ( ), but in the probability that a molecule has a certain speed || in<br />

any direction, i.e., that the velocity vector ends somewhere on a sphere with radius<br />

q<br />

|| = 2 + 2 + 2 (5.63)<br />

To obtain this distribution, we must integrate over all polar angles and . This<br />

corresponds to replacing the volume element with the volume 4 2 of<br />

a spherical shell with radius and thickness y<br />

I The 3D Maxwell-Boltzmann speed distribution (Fig. 5.4):<br />

() =<br />

µ 32 <br />

<br />

× 4 2 × exp<br />

µ− 2 (5.64)<br />

2 <br />

2 <br />

Note that this distribution is also normalized for<br />

Z ∞<br />

() =1 We check this by<br />

substituting<br />

y<br />

Z ∞<br />

0<br />

r<br />

r<br />

µ 12 <br />

<br />

=<br />

2 y = 2 y = 2 <br />

<br />

<br />

(5.65)<br />

= 2 <br />

2 (5.66)<br />

2<br />

() =<br />

µ 32 <br />

× 4<br />

2 <br />

0<br />

Z ∞<br />

0<br />

0<br />

µ<br />

2 2 <br />

2 −2 <br />

12<br />

(5.67)<br />

µ 32 Z∞<br />

µ 32 1 1<br />

=4 × 2 −2 =4 × × 1 √ =1 (5.68)<br />

4

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