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Physical Chemistry 3: — Chemical Kinetics — - Christian-Albrechts ...

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5.1 Hardspherecollisiontheory 96<br />

• mean speed of A and B:<br />

=<br />

=<br />

r r<br />

8 8<br />

=<br />

(5.4)<br />

<br />

r r <br />

8 8<br />

=<br />

(5.5)<br />

<br />

• mean relative speed (2 different molecules, i.e., A 6= B): 35<br />

=<br />

r 8 <br />

<br />

(5.9)<br />

with the reduced mass<br />

=<br />

<br />

+ <br />

(5.10)<br />

• mean relative speed (single type of molecules, i.e., A = B):<br />

y<br />

=<br />

<br />

+ <br />

= 1 2 (5.11)<br />

= √ 2 ×<br />

r<br />

8 <br />

<br />

(5.12)<br />

I<br />

Hard sphere gas kinetic collision frequency:<br />

• We want to determine the number of collisions of a single molecule A with<br />

molecules B in time . This is given by the product of the (volume that A has<br />

swept in ) × (number density of B):<br />

<strong>—</strong> volume of cylinder that A has swept in time :<br />

volume = cross section × (5.13)<br />

y<br />

2 × (5.14)<br />

35 The mean relative speed of two molecules with velocities u and u is found by looking at the<br />

square of the difference speed<br />

2 = |u − u | 2 = | | 2 + | | 2 − 2 | || | cos (5.6)<br />

The third term averaged over cos is 0, therefore<br />

Since and<br />

2 = | | 2 + | | 2 = 3 <br />

<br />

+ 3 <br />

= 3 ( + )<br />

= 3 <br />

<br />

³<br />

2´12 differ only by a constant factor, we also find that<br />

=<br />

s<br />

8 <br />

<br />

(5.7)<br />

(5.8)

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