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2.1 Ultrafast solid-state lasers - ETH - the Keller Group

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82 <strong>2.1</strong>.4 Loss modulation [Ref. p. 134<br />

R tot = F ∫<br />

out Iout (t)dt<br />

= ∫<br />

F in Iin (t)dt =1− 2 ∫<br />

F in<br />

q (t) I in (t)dt. (<strong>2.1</strong>.9)<br />

This determines <strong>the</strong> total absorber loss coefficient q p , which results from <strong>the</strong> fact that part of <strong>the</strong><br />

excitation pulse needs to be absorbed to saturate <strong>the</strong> absorber:<br />

R tot =e −2qp ≈ 1 − 2q p . (<strong>2.1</strong>.10)<br />

From (<strong>2.1</strong>.9) and (<strong>2.1</strong>.10) it <strong>the</strong>n follows<br />

q p = 1 ∫<br />

∫<br />

q (t) I in (t)dt = q (t) f (t)dt, (<strong>2.1</strong>.11)<br />

F in<br />

where<br />

f (t) ≡ I in (t)<br />

F in<br />

= P in (t)<br />

E p,in<br />

with<br />

∫<br />

f (t)dt = 1<br />

F in<br />

∫<br />

I in (t)dt =1. (<strong>2.1</strong>.12)<br />

We <strong>the</strong>n distinguish between two typical cases: a slow and a fast saturable absorber.<br />

<strong>2.1</strong>.4.<strong>2.1</strong> Slow saturable absorber<br />

In <strong>the</strong> case of a slow saturable absorber, we assume that <strong>the</strong> excitation pulse duration is much<br />

shorter than <strong>the</strong> recovery time of <strong>the</strong> absorber (i.e. τ p ≪ τ A ). Thus, we can neglect <strong>the</strong> recovery<br />

of <strong>the</strong> absorber during pulse excitation and (<strong>2.1</strong>.7) reduces to:<br />

dq (t)<br />

dt<br />

q (t) P (t)<br />

≈− . (<strong>2.1</strong>.13)<br />

E sat,A<br />

This differential equation can be solved and we obtain for <strong>the</strong> Self-Amplitude Modulation (SAM):<br />

⎡<br />

⎤<br />

q (t) =q 0 exp ⎣−<br />

E ∫t<br />

p<br />

f (t ′ )dt ′ ⎦ . (<strong>2.1</strong>.14)<br />

E sat,A<br />

0<br />

Equation (<strong>2.1</strong>.11) <strong>the</strong>n determines <strong>the</strong> total absorber loss coefficient for a given incident pulse<br />

fluence F p,A :<br />

∫<br />

F<br />

(<br />

)<br />

sat,A<br />

q p (F p,A )= q (t) f (t)dt = q 0 1 − e −Fp,A/Fsat,A . (<strong>2.1</strong>.15)<br />

F p,A<br />

It is not surprising that q p does not depend on any specific pulse form because τ p ≪ τ A .Itis<br />

useful to introduce a saturation parameter S ≡ F p,A /F sat,A . For strong saturation (S >3), we<br />

have q p (F p,A ) ≈ q 0 /S (<strong>2.1</strong>.15) and <strong>the</strong> absorbed pulse fluence is about F sat,A ΔR.<br />

<strong>2.1</strong>.4.2.2 Fast saturable absorber<br />

In <strong>the</strong> case of a fast saturable absorber, <strong>the</strong> absorber recovery time is much faster than <strong>the</strong> pulse<br />

duration (i.e. τ p ≫ τ A ). Thus, we can assume that <strong>the</strong> absorption instantaneously follows <strong>the</strong><br />

absorption of a certain power P (t) and (<strong>2.1</strong>.7) reduces to<br />

0=− q (t) − q 0<br />

τ A<br />

−<br />

q (t) P (t)<br />

E sat,A<br />

. (<strong>2.1</strong>.16)<br />

Landolt-Börnstein<br />

New Series VIII/1B1

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