Download the entire Volume 3 Criteria Manual - Urban Drainage ...
Download the entire Volume 3 Criteria Manual - Urban Drainage ... Download the entire Volume 3 Criteria Manual - Urban Drainage ...
Calculating the WQCV and Volume Reduction Chapter 3 WQCV To quantify the benefits of disconnected impervious area and other BMPs on the WQCV, the WQCV is calculated using both the total imperviousness and effective imperviousness of each sub-basin. Calculations for Sub-basin A include the following: 3 43560 ft2 2 WQCV I Total = 0.91 ∙ I Total − 1.19 ∙ I Total + 0.78 ∙ I Total ∙ Total Area ∙ ac WQCV I Total = (0.91 ∙ 0.49 3 − 1.19 ∙ 0.49 2 43560 ft2 + 0.78 ∙ 0.49) ∙ 1.15 ac ∙ ac 1ft ∙ 12 in 1ft ∙ = 846 ft3 12 in Since the volume-based option is specified for Sub-basin A, by definition, the entire WQCV (846 ft 3 ) is to be provided. Therefore, there is no need to calculate WQCV I WQ for Sub-basin A. The spreadsheet returns the result "N/A." The effects of providing the WQCV for Sub-basin A lead to reductions in detention storage requirements for the 10- and 100-year events as demonstrated below. Calculations for Sub-basin E include the following: 3 43560 ft2 2 WQCV I Total = 0.91 ∙ I Total − 1.19 ∙ I Total + 0.78 ∙ I Total ∙ Total Area ∙ ac WQCV I Total = (0.91 ∙ 0.73 3 − 1.19 ∙ 0.73 2 43560 ft2 + 0.78 ∙ 0.73) ∙ 0.15 ac ∙ ac Next the WQCV associated with I WQ is calculated: 43560 ft2 3 2 WQCV I WQ = 0.91 ∙ I WQ − 1.19 ∙ I WQ + 0.78 ∙ I WQ ∙ Total Area ∙ ac WQCV I WQ = (0.91 ∙ 0.56 3 − 1.19 ∙ 0.56 2 43560 ft2 + 0.78 ∙ 0.56) ∙ 0.15 ac ∙ ac 1ft ∙ 12 in 1ft ∙ 12 in 1ft ∙ = 158 ft3 12 in 1ft ∙ = 122 ft3 12 in Therefore, the reduction in the required WQCV form the implementation of conveyance-based BMPs in Sub-basin E is approximately 158 ft 3 – 122 ft 3 = 36 ft 3 , or approximately 23% relative to the WQCV based on total imperviousness. 10-Year Event To evaluate effects of conveyance- and volume-based BMPs on 10-year detention storage volumes, the empirical equations from the Storage chapter of Volume 2 can be applied to the total impervious area and the effective imperviousness. The results of these calculations can be compared to determine the associated 10-year volume reduction. Calculations for Sub-basin A include the following: V 10 I Total = (0.95 ∙ I Total − 1.90) ∙ Total Area ∙ 43560 1000 (0.95 ∙ 49% − 1.90) V 10 I Total = ∙ 1.15 ac ∙ 43560 1000 ft 3 ac ∙ ft ft 3 = 2222 ft3 ac ∙ ft 3-28 Urban Drainage and Flood Control District August 2011 Urban Storm Drainage Criteria Manual Volume 3
Chapter 3 Calculating the WQCV and Volume Reduction The same calculation is then performed using the effective imperviousness for the 10-year event: V 10 I 10−yr Effective = 0.95 ∙ I 10−yr Effective − 1.90 ∙ Total Area ∙ 43560 1000 (0.95 ∙ 45% − 1.90) V 10 I Total = ∙ 1.15 ac ∙ 43560 1000 ft 3 = 2046 ft3 ac ∙ ft ft 3 ac ∙ ft The reduction in the 10-year storage volume as a result of the conveyance-based BMPs in Sub-basin A is, therefore, 2222 ft 3 – 2046 ft 3 = 176 ft 3 , or approximately 8% relative to the 10-year storage volume based on total imperviousness. Calculations for Sub-basin E include the following: V 10 I Total = (0.95 ∙ I Total − 1.90) 1000 ∙ Total Area ∙ 43560 (0.95 ∙ 73% − 1.90) V 10 I Total = ∙ 0.15 ac ∙ 43560 1000 ft 3 ac ∙ ft ft 3 = 443 ft3 ac ∙ ft The same calculation is then performed using the effective imperviousness for the 10-year event: V 10 I 10−yr Effective = 0.95 ∙ I 10−yr Effective − 1.90 ∙ Total Area ∙ 43560 1000 (0.95 ∙ 66% − 1.90) V 10 I 10−yr Effective = ∙ 0.15 ac ∙ 43560 1000 ft 3 = 395 ft3 ac ∙ ft ft 3 ac ∙ ft The reduction in the 10-year storage volume as a result of the conveyance-based BMPs in Sub-basin E is, therefore, 443 ft 3 – 395 ft 3 = 48 ft 3 , or approximately 11% relative to the 10-year storage volume based on total imperviousness. 100-Year Event To evaluate effects of conveyance- and volume-based BMPs on 100-year detention storage volumes, the empirical equations from the Storage chapter of Volume 2 can be applied to the total impervious area and the effective imperviousness. The results of these calculations can be compared to determine the associated 100-year volume reduction. Please note that there are two empirical equations for the 100-year detention storage volume in the Storage chapter, one for HSG A soils and the other for HSG B, C and D soils. The spreadsheet selects the appropriate equation based on the RPA infiltration rate that is input for the sub-basin. If the RPA infiltration rate is greater than or equal to 1 inch/hour, the HSG A equation is used. Otherwise, the HSG B, C and D equation is used. Calculations for Sub-basin A include the following: V 100 I Total = −0.00005501 ∙ I 2 Total + 0.030148 ∙ I Total − 0.12 ∙ Total Area ∙ 43560 12 V 100 I Total = (−0.00005501 ∙ 49%2 + 0.030148 ∙ 49% − 0.12) ∙ 1.15 ac ∙ 43560 12 = 5083 ft 3 ft 3 ac ∙ ft ft 3 ac ∙ ft August 2011 Urban Drainage and Flood Control District 3-29 Urban Storm Drainage Criteria Manual Volume 3
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Chapter 3<br />
Calculating <strong>the</strong> WQCV and <strong>Volume</strong> Reduction<br />
The same calculation is <strong>the</strong>n performed using <strong>the</strong> effective imperviousness for <strong>the</strong> 10-year event:<br />
V 10 I 10−yr Effective = 0.95 ∙ I 10−yr Effective − 1.90<br />
∙ Total Area ∙ 43560<br />
1000<br />
(0.95 ∙ 45% − 1.90)<br />
V 10 I Total = ∙ 1.15 ac ∙ 43560<br />
1000<br />
ft 3<br />
= 2046 ft3<br />
ac ∙ ft<br />
ft 3<br />
ac ∙ ft<br />
The reduction in <strong>the</strong> 10-year storage volume as a result of <strong>the</strong> conveyance-based BMPs in Sub-basin A is,<br />
<strong>the</strong>refore, 2222 ft 3 – 2046 ft 3 = 176 ft 3 , or approximately 8% relative to <strong>the</strong> 10-year storage volume based<br />
on total imperviousness.<br />
Calculations for Sub-basin E include <strong>the</strong> following:<br />
V 10 I Total = (0.95 ∙ I Total − 1.90)<br />
1000<br />
∙ Total Area ∙ 43560<br />
(0.95 ∙ 73% − 1.90)<br />
V 10 I Total = ∙ 0.15 ac ∙ 43560<br />
1000<br />
ft 3<br />
ac ∙ ft<br />
ft 3<br />
= 443 ft3<br />
ac ∙ ft<br />
The same calculation is <strong>the</strong>n performed using <strong>the</strong> effective imperviousness for <strong>the</strong> 10-year event:<br />
V 10 I 10−yr Effective = 0.95 ∙ I 10−yr Effective − 1.90<br />
∙ Total Area ∙ 43560<br />
1000<br />
(0.95 ∙ 66% − 1.90)<br />
V 10 I 10−yr Effective = ∙ 0.15 ac ∙ 43560<br />
1000<br />
ft 3<br />
= 395 ft3<br />
ac ∙ ft<br />
ft 3<br />
ac ∙ ft<br />
The reduction in <strong>the</strong> 10-year storage volume as a result of <strong>the</strong> conveyance-based BMPs in Sub-basin E is,<br />
<strong>the</strong>refore, 443 ft 3 – 395 ft 3 = 48 ft 3 , or approximately 11% relative to <strong>the</strong> 10-year storage volume based on<br />
total imperviousness.<br />
100-Year Event<br />
To evaluate effects of conveyance- and volume-based BMPs on 100-year detention storage volumes, <strong>the</strong><br />
empirical equations from <strong>the</strong> Storage chapter of <strong>Volume</strong> 2 can be applied to <strong>the</strong> total impervious area and<br />
<strong>the</strong> effective imperviousness. The results of <strong>the</strong>se calculations can be compared to determine <strong>the</strong><br />
associated 100-year volume reduction. Please note that <strong>the</strong>re are two empirical equations for <strong>the</strong> 100-year<br />
detention storage volume in <strong>the</strong> Storage chapter, one for HSG A soils and <strong>the</strong> o<strong>the</strong>r for HSG B, C and D<br />
soils. The spreadsheet selects <strong>the</strong> appropriate equation based on <strong>the</strong> RPA infiltration rate that is input for<br />
<strong>the</strong> sub-basin. If <strong>the</strong> RPA infiltration rate is greater than or equal to 1 inch/hour, <strong>the</strong> HSG A equation is<br />
used. O<strong>the</strong>rwise, <strong>the</strong> HSG B, C and D equation is used.<br />
Calculations for Sub-basin A include <strong>the</strong> following:<br />
V 100 I Total = −0.00005501 ∙ I 2<br />
Total + 0.030148 ∙ I Total − 0.12<br />
∙ Total Area ∙ 43560<br />
12<br />
V 100 I Total = (−0.00005501 ∙ 49%2 + 0.030148 ∙ 49% − 0.12)<br />
∙ 1.15 ac ∙ 43560<br />
12<br />
= 5083 ft 3<br />
ft 3<br />
ac ∙ ft<br />
ft 3<br />
ac ∙ ft<br />
August 2011 <strong>Urban</strong> <strong>Drainage</strong> and Flood Control District 3-29<br />
<strong>Urban</strong> Storm <strong>Drainage</strong> <strong>Criteria</strong> <strong>Manual</strong> <strong>Volume</strong> 3