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stability of lightweight structural sandwich panels exposed to fire

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Second International Workshop « Structures in Fire » – Christchurch – March 2002<br />

so that<br />

∆= αTL 2<br />

1<br />

8d<br />

(A6)<br />

Annex B<br />

The classical text book equation for the horizontal restraint force H needed <strong>to</strong> support a<br />

catenary (cable-like structure) <strong>of</strong> span L carrying a uniformly distributed load w per unit<br />

length having a mid-span deflection D, Figure B1, is simply derived in the following way.<br />

For equilibrium ∑ M = 0 where M = moment. Taking moments about point A for the right<br />

hand half <strong>of</strong> the catenary,<br />

w LL = Hd + w LL from which<br />

22 24<br />

H<br />

wL 2<br />

=<br />

8D<br />

(B1)<br />

Note that H becomes infinite as D becomes small<br />

L<br />

17100<br />

H<br />

H<br />

2500<br />

D<br />

wL/2<br />

A<br />

4300 L/4<br />

wL/2<br />

wL/2<br />

Figure B1 Catenary force diagram<br />

Load per unit length, w<br />

Annex C<br />

The equation derived below relates the axial shortening ∆ L <strong>to</strong> the mid-span deflection ∆ N for<br />

a flexible member when the member bows in<strong>to</strong> a circular arc. Consider an initially straight<br />

member AB <strong>of</strong> length L, Figure C1, in which end A is position fixed. The member is slender<br />

so that the application <strong>of</strong> an axial compressive force P at end B causes negligible elastic<br />

compressive strain in the material but causes it <strong>to</strong> bow in<strong>to</strong> a circular arc ACD.<br />

From Figure C1<br />

378

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