Notes on Relativity and Cosmology - Physics Department, UCSB
Notes on Relativity and Cosmology - Physics Department, UCSB Notes on Relativity and Cosmology - Physics Department, UCSB
76 CHAPTER 3. EINSTEIN AND INERTIAL FRAMES that signals can only be sent at speed c or slower, the earliest possible time that the back of the train could discover the exit explosion is at the event marked D on the diagram. Note that, at event D, the back of the train does find itself inside the tunnel and also finds that event 1 has already occurred. The entrance is closed and the train cannot escape. There are two things that deserve more explanation. The first is the above comment about the shock wave. Normally we think of objects like trains as being perfectly stiff. However, this is not really so. Let’s think about what happens when I push on one end of a meter stick. I press on the atoms on the end, which press on the atoms next to them, which press on the atoms next to them ..... Also, it takes a (small but finite) amount of time for each atom to respond to the push it has been given on one side and to move over and begin to push the atom on the other side. The result is known as a “shock wave” that travels at finite speed down the object. Note that an important part of the shock wave are the electric forces that two atoms use to push each other around. Thus, the shock wave can certainly not propagate faster than an electromagnetic disturbance can. As a result, it must move at less than the speed of light. For the other point, let’s suppose that the people at the front of the train step on the brakes and stop immediately. Stopping the atoms at the front of the train will make them push on the atoms behind them, stopping them, etc. The shock wave results from the fact that atoms just behind the front slam into atoms right at the front; the whole system compresses a bit and then may try to reexpand, pushing some of the atoms farther back. ⋆⋆ What we saw above is that the shock wave cannot reach the back of the train until event D. Suppose that it does indeed stop the back of the train there. The train has now come to rest in the tunnel’s frame of reference. Thus, after event D, the proper length of the train is less than 100m!!!! In fact, suppose that we use the lines of simultaneity in the train’s original frame of reference (before it tries to stop) to measure the proper length of the train. Then, immediately after event 2 the front of the train changes its motion, but the back of the train keeps going. As a result, in this sense the proper length of the train starts to shrink immediately after event 2. This is how it manages to fit itself into a tunnel that, in this frame, is less than 100m long. What has happened? The answer is in the compression that generates the shock wave. The train really has been physically compressed by the wall of debris at the exit slamming into it at half the speed of light 6 ! This compression is of course accompanied by tearing of metal, shattering of glass, death screams of passengers, and the like, just as you would expect in a crash. The train is completely and utterly destroyed. The robbers will be lucky if the gold they wish to steal has not been completely vaporized in the carnage. Now, you might want to get one more perspective on this (trying to show some hidden inconsistency?) by analyzing the problem again in a frame of reference 6 Or the equivalent damage inflicted through the use of the train’s brakes.
3.8. HOMEWORK PROBLEMS 77 that moves with the train at all times, even slowing down and stopping as the train slows down and stops. However, we do not know enough to do this yet since such a frame is not inertial. We will get to accelerating reference frames in chapter 5. 3.8 Homework Problems 3-1. Use your knowledge of geometry (and/or trigonometry) to show that the angle α between the worldline of an inertial observer and the lightcone (drawn in an inertial frame using units in which light rays travel at 45 degrees) is the same as the angle β between that observer’s line of simultaneity and the lightcone. (Hint: Many people find it easier to use trigonometry to solve this problem than to use geometry.) x = 0 f x =0 us t = const f green line of simultaneity C Us α B β t us t =0 us =+1sec 3-2. Suppose that you and your friend are inertial observers (that is, that both reference frames are inertial). Suppose that two events, A and B, are simultaneous in your own reference frame. Draw two spacetime diagrams in your reference frame. Include your friend’s worldline in both. For the first, arrange the relative velocity of you and your friend so that event A occurs before event B in your friend’s reference frame. For the second, arrange it so that event B occurs first in your friend’s frame. In both cases, include one of your friend’s lines of simultaneity on the diagram. 3-3. Draw a spacetime diagram in an inertial reference frame. a) Mark any two spacelike related events on your diagram and label them both ‘S.’ b) Mark any two lightlike related events on your diagram and label them both ‘L.’
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76 CHAPTER 3. EINSTEIN AND INERTIAL FRAMES<br />
that signals can <strong>on</strong>ly be sent at speed c or slower, the earliest possible time that<br />
the back of the train could discover the exit explosi<strong>on</strong> is at the event marked<br />
D <strong>on</strong> the diagram. Note that, at event D, the back of the train does find itself<br />
inside the tunnel <strong>and</strong> also finds that event 1 has already occurred. The entrance<br />
is closed <strong>and</strong> the train cannot escape.<br />
There are two things that deserve more explanati<strong>on</strong>. The first is the above<br />
comment about the shock wave. Normally we think of objects like trains as<br />
being perfectly stiff. However, this is not really so. Let’s think about what<br />
happens when I push <strong>on</strong> <strong>on</strong>e end of a meter stick. I press <strong>on</strong> the atoms <strong>on</strong> the<br />
end, which press <strong>on</strong> the atoms next to them, which press <strong>on</strong> the atoms next<br />
to them ..... Also, it takes a (small but finite) amount of time for each atom<br />
to resp<strong>on</strong>d to the push it has been given <strong>on</strong> <strong>on</strong>e side <strong>and</strong> to move over <strong>and</strong><br />
begin to push the atom <strong>on</strong> the other side. The result is known as a “shock<br />
wave” that travels at finite speed down the object. Note that an important<br />
part of the shock wave are the electric forces that two atoms use to push each<br />
other around. Thus, the shock wave can certainly not propagate faster than<br />
an electromagnetic disturbance can. As a result, it must move at less than the<br />
speed of light.<br />
For the other point, let’s suppose that the people at the fr<strong>on</strong>t of the train step<br />
<strong>on</strong> the brakes <strong>and</strong> stop immediately. Stopping the atoms at the fr<strong>on</strong>t of the<br />
train will make them push <strong>on</strong> the atoms behind them, stopping them, etc. The<br />
shock wave results from the fact that atoms just behind the fr<strong>on</strong>t slam into<br />
atoms right at the fr<strong>on</strong>t; the whole system compresses a bit <strong>and</strong> then may try<br />
to reexp<strong>and</strong>, pushing some of the atoms farther back.<br />
⋆⋆ What we saw above is that the shock wave cannot reach the back of the train<br />
until event D. Suppose that it does indeed stop the back of the train there. The<br />
train has now come to rest in the tunnel’s frame of reference. Thus, after event<br />
D, the proper length of the train is less than 100m!!!!<br />
In fact, suppose that we use the lines of simultaneity in the train’s original frame<br />
of reference (before it tries to stop) to measure the proper length of the train.<br />
Then, immediately after event 2 the fr<strong>on</strong>t of the train changes its moti<strong>on</strong>, but<br />
the back of the train keeps going. As a result, in this sense the proper length<br />
of the train starts to shrink immediately after event 2. This is how it manages<br />
to fit itself into a tunnel that, in this frame, is less than 100m l<strong>on</strong>g.<br />
What has happened? The answer is in the compressi<strong>on</strong> that generates the shock<br />
wave. The train really has been physically compressed by the wall of debris at<br />
the exit slamming into it at half the speed of light 6 ! This compressi<strong>on</strong> is of<br />
course accompanied by tearing of metal, shattering of glass, death screams of<br />
passengers, <strong>and</strong> the like, just as you would expect in a crash. The train is<br />
completely <strong>and</strong> utterly destroyed. The robbers will be lucky if the gold they<br />
wish to steal has not been completely vaporized in the carnage.<br />
Now, you might want to get <strong>on</strong>e more perspective <strong>on</strong> this (trying to show some<br />
hidden inc<strong>on</strong>sistency?) by analyzing the problem again in a frame of reference<br />
6 Or the equivalent damage inflicted through the use of the train’s brakes.