Notes on Relativity and Cosmology - Physics Department, UCSB
Notes on Relativity and Cosmology - Physics Department, UCSB
Notes on Relativity and Cosmology - Physics Department, UCSB
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3.5. TIME DILATION 71<br />
3) Suppose that (when they meet) blue plants a time bomb in red’s luggage<br />
<strong>and</strong> sets it to go off after 1sec. What times does blue find it to go off? The<br />
time bomb will go off after it experiences 1sec of time. In other words, it<br />
will go off at the point al<strong>on</strong>g its worldline which is 1sec of proper time later.<br />
Since red is traveling al<strong>on</strong>g the same worldline, this is 1sec later according<br />
to red <strong>and</strong> <strong>on</strong> red’s worldline. As a result, (3.3) tells us that this happens at<br />
t blue = 1/ √ 1 − (v/c) 2 .<br />
4) Suppose that (when they meet) red plants a time bomb in blue’s luggage<br />
<strong>and</strong> he wants it to go off at t red=1 . How much time delay should the bomb be<br />
given? This requires figuring out how much proper time will pass <strong>on</strong> blue’s<br />
worldline between red’s lines of simultaneity t red=0 <strong>and</strong> t red=1 . Since the<br />
events are <strong>on</strong> blue’s worldline, blue plays the role of the moving friend in<br />
(3.3). As a result, the time until the explosi<strong>on</strong> as measured by blue should<br />
be t blue = √ 1 − (v/c) 2 , <strong>and</strong> this is the delay to set.<br />
3.5.4 Why should you believe all of this?<br />
So far, we have just been working out c<strong>on</strong>sequences of Einstein’s idea. We have<br />
said little about whether you should actually believe that this represents reality.<br />
In particular, the idea that clocks in different reference frames measure different<br />
amounts of time to pass blatantly c<strong>on</strong>tradicts your experience, doesn’t it? Just<br />
because you go <strong>and</strong> fly around in an airplane does not mean that your watch<br />
becomes unsynchr<strong>on</strong>ized with the Carto<strong>on</strong> Network’s broadcast schedule, does<br />
it?<br />
Well, let’s start thinking about this by figuring out how big the time dilati<strong>on</strong><br />
effect would be in everyday life. Commercial airplanes move at about 4 300m/s.<br />
So, v/c ≈ 10 −6 for an airplane. Now 5 , √ 1 − (v/c) 2 ≈ 1 − 1 2 (v/c)2 + ... ≈<br />
1 − 5 × 10 −13 for the airplane. This is less than 1 part in a trilli<strong>on</strong>.<br />
Tiny, eh? You’d never notice this by checking your watch against the Carto<strong>on</strong><br />
Network. However, physics is a very precise science. It turns out that it is<br />
in fact possible to measure time to better than <strong>on</strong>e part in a trilli<strong>on</strong>. A nice<br />
form of this experiment was first d<strong>on</strong>e in the 1960’s. Some physicists got two<br />
identical atomic clocks, brought them together, <strong>and</strong> checked that they agreed to<br />
much better than 1 part in a trilli<strong>on</strong>. Then, they left <strong>on</strong>e in the lab <strong>and</strong> put the<br />
other <strong>on</strong> an airplane (such clocks were big, they bought a seat for the clock <strong>on</strong><br />
a commercial airplane flight) <strong>and</strong> flew around for awhile. When they brought<br />
the clocks back together at the end of the experiment, the moving clock had in<br />
fact ‘ticked’ less times, measuring less time to pass in precise accord with our<br />
calculati<strong>on</strong>s above <strong>and</strong> Einstein’s predicti<strong>on</strong>.<br />
⋆⋆ You should not underestimate the significance of what I have just said. Just<br />
a moment ago, we were merrily exploring Einstein’s crazy idea. While Einstein’s<br />
4 Those of you with physics background may recognize this as roughly the speed of sound<br />
in air. Travel faster than the speed of sound is difficult <strong>and</strong> therefore expensive, so most<br />
commercial planes lurk as just below sound speed.<br />
5 Note that I am using the expansi<strong>on</strong> from problem (2-2). It really is h<strong>and</strong>y.