27.09.2014 Views

Notes on Relativity and Cosmology - Physics Department, UCSB

Notes on Relativity and Cosmology - Physics Department, UCSB

Notes on Relativity and Cosmology - Physics Department, UCSB

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

9.4. STRETCHING AND SQUISHING 259<br />

is small. What we’re going to do is to take the limit as T <strong>and</strong> L go to zero <strong>and</strong><br />

turn this into a differential equati<strong>on</strong>. Technically, we will take T to zero faster<br />

that L so that T 2 /L 2 → 0. Note that we are really interested in how things<br />

change with positi<strong>on</strong> at t = 0, so that is is natural to take T to zero before<br />

taking L to zero.<br />

OK, so imagine not just two free fallers, but a whole set of them at every value<br />

of x. Each of these starts out with zero velocity, <strong>and</strong> each of them has an<br />

accompanying static observer. The free faller at x will have some accelerati<strong>on</strong><br />

a FF (x), <strong>and</strong> the static observer at x will have some accelerati<strong>on</strong> a s (x) relative<br />

to the corresp<strong>on</strong>ding free faller. If L is very small above, notice that a s2 −a s1 =<br />

L das<br />

dx + O(L2 ) <strong>and</strong> that (since a FF1 = 0), a FF2 = L daFF<br />

dx + O(L2 ).<br />

So, we can rewrite equati<strong>on</strong> (9.35) as:<br />

L da FF<br />

dx<br />

= −Lda s<br />

dx − La2 s/c 2 + O(T 2 /L) + O(L 2 ). (9.36)<br />

We can now divide by L <strong>and</strong> take the limit as T/L <strong>and</strong> L go to zero. The result<br />

is a lovely differential equati<strong>on</strong>:<br />

da FF<br />

dx<br />

= −da s<br />

dx − a2 s /c2 (9.37)<br />

By the way, the important point to remember about the above expressi<strong>on</strong> is<br />

that the coordinate x represents proper distance. (Sound familiar?)<br />

9.4.4 What does it all mean?<br />

One of the best ways to use this equati<strong>on</strong> is to undo part of the last step.<br />

Say that you have two free falling observers close together that have no initial<br />

velocity. Then, if their separati<strong>on</strong> L is small enough, their relative accelerati<strong>on</strong><br />

is L daFF<br />

dx<br />

or<br />

( ) das<br />

relative accelerati<strong>on</strong> = −L<br />

dx + a2 s /c2 . (9.38)<br />

Let’s take a simple example of this. Suppose that you are near a black hole<br />

<strong>and</strong> that your head <strong>and</strong> your feel are both freely falling objects. Then, this formula<br />

tells you at what accelerati<strong>on</strong> your head would separate from (or, perhaps,<br />

accelerate toward) your feet. Of course, your head <strong>and</strong> feet are not, in reality,<br />

separate freely falling objects. The rest of your body will pull <strong>and</strong> push <strong>on</strong> them<br />

to keep your head <strong>and</strong> feet roughly the same distance apart at all times. However,<br />

your head <strong>and</strong> feet will want to separate or come together, so depending<br />

<strong>on</strong> how big the relative accelerati<strong>on</strong> is, keeping your head <strong>and</strong> feet in the proper<br />

places will cause a lot of stress <strong>on</strong> your body.<br />

For example, suppose that the relative accelerati<strong>on</strong> is 10m/s 2 (1g) away from<br />

each other. In that case, the experience would feel much like what you feel if

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!