Notes on Relativity and Cosmology - Physics Department, UCSB

Notes on Relativity and Cosmology - Physics Department, UCSB Notes on Relativity and Cosmology - Physics Department, UCSB

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156 CHAPTER 6. DYNAMICS: ENERGY AND ... Furthermore, we see that this ‘size’ does not depend on the frame of reference and so does not depend on how fast the object is moving. However, for a rapidly moving object, both the time part (the energy) and the space part (the momentum) are large – it’s just that the Minkowskian notion of the size of a vector involves a minus sign, and these two parts largely cancel against each other. 6.4.3 How about an example? As with many topics, a concrete example is useful to understand certain details of what is going on. In this case, I would like to illustrate the point that while energy and momentum are both conserved, mass is not conserved. Let’s suppose we take two electrons and places them in a box. Suppose that both electrons are moving at 4/5c, but in opposite directions. If m e is the rest mass of an electron, each particle |p| = m e v √ 1 − v2 /c 2 = 4 3 m ec, (6.12) and an energy E = m e c 2 √ 1 − v2 /c 2 = 5 3 m ec 2 . (6.13) We also need to consider the box. For simplicity, let us suppose that the box also has mass m e . But the box is not moving, so it has p Box = 0 and E Box = m e c 2 . Now, what is the energy and momentum of the system as a whole? Well, the two electron momenta are of the same size, but they are in opposite directions. So, they cancel out. Since p Box = 0, the total momentum is also zero. However, the energies are all positive (energy doesn’t care about the direction of motion), so they add together. We find: So, what is the rest mass of the systemas a whole? p system = 0, E system = 13 3 m ec 2 . (6.14) E 2 − p 2 c 2 = 169 9 m2 e c4 . (6.15) So, the rest mass of the positronium system is given by dividing the right hand side by c 4 . The result is 13 3 m e, which is significantly greater than the rest mass of the Box plus twice the rest mass of the electron! Similarly, two massless particles can in fact combine to make an object with a finite non-zero mass. For example, placing photons in a box adds to the mass of the box. We’ll talk more about massless particles (and photons in particular) below.

6.5. ENERGY AND MOMENTUM FOR LIGHT 157 6.5 Energy and Momentum for Light At this point we have developed a good understanding of energy and momentum for objects. However, there has always been one other very important player in our discussions, which is of course light itself. In this section, we’ll take a moment to explore the energy and momentum of light waves and to see what it has to teach us. 6.5.1 Light speed and massless objects OK, let’s look one more time at the question: “What happens if we try to get an object moving at a speed greater than c?” Let’s look at the formulas for both energy and momentum. Notice that E = √ m0c2 becomes infinitely large as 1−v 2 /c2 v approaches the speed of light. Similarly, an object (with finite rest mass m 0 ) requires an infinite momentum to move at the speed of light. Again this tells us is that, much as with our uniformly accelerating rocket from last week, no finite effort will ever be able to make any object (with m 0 > 0) move at speed c. By the way, what happens if we try to talk about energy and momentum for light itself? Of course, many of our formulas (such as the one above) fail to make sense for v = c. However, some of them do. Consider, for example, pc E = v c . (6.16) Since light moves at speed c through a vacuum, this would lead us to expect that for light we have E = pc. In fact, one can compute the energy and momentum of a light wave using Maxwell’s equations. One finds that both the energy and the momentum of a light wave depend on several factors, like the wavelength and the size of the wave. However, in all cases the energy and momentum exactly satisfies the relation E = pc. As a result, we can consider a bit of light (a.k.a., a photon) with any energy E so long as we also assign it a corresponding momentum p = E/c. The energy and momentum of photons adds together in just the way that we saw in section 6.4.3 for massive particles. So, what is the rest mass of light? Well, if we compute m 2 0c 2 = E 2 − p 2 c 2 = 0, we find m 0 = 0. Thus, light has no mass. This to some extent shows how light can move at speed c and have finite energy. The zero rest mass ‘cancels’ against the infinite factor coming from 1 − v 2 /c 2 in our formulas above. By the way, note that this also goes the other way: if m 0 = 0 then E = ±pc and so v c = pc E = ±1. Such an object has no choice but to always move at the speed of light. 6.5.2 Another look at the Doppler effect Recall that, for a massive particle (i.e., with m 0 > 0), if we are in a frame that is moving rapidly toward the object, the object has a large energy and momentum

6.5. ENERGY AND MOMENTUM FOR LIGHT 157<br />

6.5 Energy <strong>and</strong> Momentum for Light<br />

At this point we have developed a good underst<strong>and</strong>ing of energy <strong>and</strong> momentum<br />

for objects. However, there has always been <strong>on</strong>e other very important player<br />

in our discussi<strong>on</strong>s, which is of course light itself. In this secti<strong>on</strong>, we’ll take a<br />

moment to explore the energy <strong>and</strong> momentum of light waves <strong>and</strong> to see what it<br />

has to teach us.<br />

6.5.1 Light speed <strong>and</strong> massless objects<br />

OK, let’s look <strong>on</strong>e more time at the questi<strong>on</strong>: “What happens if we try to get an<br />

object moving at a speed greater than c?” Let’s look at the formulas for both<br />

energy <strong>and</strong> momentum. Notice that E = √ m0c2<br />

becomes infinitely large as<br />

1−v 2 /c2 v approaches the speed of light. Similarly, an object (with finite rest mass m 0 )<br />

requires an infinite momentum to move at the speed of light. Again this tells<br />

us is that, much as with our uniformly accelerating rocket from last week, no<br />

finite effort will ever be able to make any object (with m 0 > 0) move at speed<br />

c.<br />

By the way, what happens if we try to talk about energy <strong>and</strong> momentum for<br />

light itself? Of course, many of our formulas (such as the <strong>on</strong>e above) fail to<br />

make sense for v = c. However, some of them do. C<strong>on</strong>sider, for example,<br />

pc<br />

E = v c . (6.16)<br />

Since light moves at speed c through a vacuum, this would lead us to expect that<br />

for light we have E = pc. In fact, <strong>on</strong>e can compute the energy <strong>and</strong> momentum<br />

of a light wave using Maxwell’s equati<strong>on</strong>s. One finds that both the energy <strong>and</strong><br />

the momentum of a light wave depend <strong>on</strong> several factors, like the wavelength<br />

<strong>and</strong> the size of the wave. However, in all cases the energy <strong>and</strong> momentum<br />

exactly satisfies the relati<strong>on</strong> E = pc. As a result, we can c<strong>on</strong>sider a bit of light<br />

(a.k.a., a phot<strong>on</strong>) with any energy E so l<strong>on</strong>g as we also assign it a corresp<strong>on</strong>ding<br />

momentum p = E/c. The energy <strong>and</strong> momentum of phot<strong>on</strong>s adds together in<br />

just the way that we saw in secti<strong>on</strong> 6.4.3 for massive particles.<br />

So, what is the rest mass of light? Well, if we compute m 2 0c 2 = E 2 − p 2 c 2 = 0,<br />

we find m 0 = 0. Thus, light has no mass. This to some extent shows how light<br />

can move at speed c <strong>and</strong> have finite energy. The zero rest mass ‘cancels’ against<br />

the infinite factor coming from 1 − v 2 /c 2 in our formulas above.<br />

By the way, note that this also goes the other way: if m 0 = 0 then E = ±pc<br />

<strong>and</strong> so v c = pc<br />

E<br />

= ±1. Such an object has no choice but to always move at the<br />

speed of light.<br />

6.5.2 Another look at the Doppler effect<br />

Recall that, for a massive particle (i.e., with m 0 > 0), if we are in a frame that is<br />

moving rapidly toward the object, the object has a large energy <strong>and</strong> momentum

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