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Notes on Relativity and Cosmology - Physics Department, UCSB

Notes on Relativity and Cosmology - Physics Department, UCSB

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5.1. THE UNIFORMLY ACCELERATING WORLDLINE 125<br />

frame in which it is computed. The boost parameter of the reference frame itself<br />

just cancels out.<br />

What about measuring time? Well, as we have discussed, the ‘natural’ measure<br />

of time al<strong>on</strong>g a worldline is the proper time. The proper time is again<br />

independent of any choice of reference frame.<br />

OK, so how does this relate to our above discussi<strong>on</strong>? Let’s again think about<br />

computing the proper accelerati<strong>on</strong> α(E) at some event E using the momentarily<br />

co-moving inertial frame. We have<br />

α(E) = dv E<br />

dt E<br />

. (5.2)<br />

What we want to do is to write dv E <strong>and</strong> dt E in terms of the boost parameter<br />

(θ) <strong>and</strong> the proper time (τ).<br />

Let’s start with the time part. Recall that the proper time τ al<strong>on</strong>g the rocket’s<br />

worldline is just the time that is measured by a clock <strong>on</strong> the rocket. Thus,<br />

the questi<strong>on</strong> is just “How would a small time interval dτ measured by this<br />

clock (at event E) compare to the corresp<strong>on</strong>ding time interval dt E measured<br />

in the momentarily co-moving inertial frame?” But we are interested <strong>on</strong>ly in<br />

the infinitesimal time around event E where there is negligible relative velocity<br />

between these two clocks. Clocks with no relative velocity measure time intervals<br />

in exactly the same way. So, we have dt E = dτ.<br />

Now let’s work in the boost parameter, using dθ to replace the dv E in equati<strong>on</strong><br />

(5.1). Recall that the boost parameter θ is just a functi<strong>on</strong> of the velocity v/c =<br />

tanhθ. So, let’s try to compute dv E /dt E using the chain rule. You can use the<br />

definiti<strong>on</strong> of tanh to check that<br />

Thus, we have<br />

dv<br />

dθ =<br />

dv<br />

dτ = dv dθ<br />

dθ dτ =<br />

c<br />

cosh 2 θ .<br />

c<br />

cosh 2 θ<br />

dθ<br />

dτ . (5.3)<br />

Finally, note that at event E, the boost parameter θ of the rocket relative to<br />

the momentarily co-moving inertial frame is zero. So, if we want dvE<br />

dτ<br />

we should<br />

substitute θ = 0 into the above equati<strong>on</strong> 1 :<br />

In other words,<br />

α = dv E<br />

dτ =<br />

c<br />

dθ<br />

cosh 2 ∣<br />

θ θ=0 dτ = cdθ dτ . (5.4)<br />

dθ<br />

dτ<br />

= α/c. (5.5)<br />

1 Note that this means that our chain rule calculati<strong>on</strong> (5.3) has in fact shown that, for small<br />

velocities, we have approximately θ ≈ v/c. This may make you feel even better about using<br />

boost parameters as a measure of velocity.

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