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(a) Solving Inequalities Examples; (b) - Beacon Learning Center

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<strong>Solving</strong> <strong>Inequalities</strong> <strong>Examples</strong><br />

1. Joe and Katie are dancers. Suppose you compare their weights.<br />

You can make only one of the following statements.<br />

Joe’s weight is<br />

less than Kate’s<br />

weight.<br />

Joe’s weight is<br />

the same as<br />

Kate’s weight.<br />

Joe’s weight is<br />

greater than Kate’s<br />

weight.<br />

2. Let j stand for Joe’s weight and k stand for Katie’s weight. Then<br />

you can use inequalities and an equation to compare their weights.<br />

j < k J = k j > k<br />

This is an illustration of the trichotomy property<br />

3. Trichotomy Property – For any two real numbers a and b, exactly one of the<br />

following statements is true.<br />

a < b a = b a > b<br />

4.<br />

Addition and Subtraction<br />

Properties for <strong>Inequalities</strong><br />

1. If a > b, then a + c > b + c and a – c > b – c.<br />

2. If a < b, then a + c < b + c and a – c < b – c.<br />

Adding the same number to each side<br />

of an inequality does not change the<br />

truth of the inequality.<br />

5. The following numerical examples may be used to illustrate the Addition and<br />

Subtraction Properties.<br />

5 < 6<br />

5 + 2 < 6 + 2<br />

7 < 8<br />

–6 > –10<br />

–6 – 9 > –10 – 9<br />

–15 > –19<br />

These properties can be used to<br />

solve inequalities. Each solution<br />

set can be graphed on the<br />

number line.<br />

<strong>Solving</strong> <strong>Inequalities</strong> Johnny Wolfe www.<strong>Beacon</strong>LC.org Jay High School Santa Rosa County Florida September 22, 2001


6. Example – Solve 9x + 7 < 8x – 2. Graph the solution set.<br />

9x + 7 < 8x – 2<br />

–8x + 9x + 7 < –8x + 8x – 2<br />

x + 7 < –2<br />

x + 7 + (–7) < –2 + (–7)<br />

x < –9<br />

To check inequalities, first check the boundary point for the variable, and see<br />

if the two sides are equivalent. A true equation should occur if the inequality<br />

sign is replaced by the equals sign. To make sure the direction of the<br />

inequality is correct, check a point on each side of the boundary point.<br />

Check<br />

9(–9) + 7 = 8(–9) – 2<br />

–74 = –74<br />

Choose a point in the solution set.<br />

9(–10) + 7 < 8(–10)<br />

–87 < -80 TRUE<br />

Choose a point outside the<br />

solution set.<br />

9(–8) + 7 < 8(–8)<br />

–65 < –64 FALSE<br />

7. Example – Solve y + 6 > 3. Graph the solution set.<br />

y + 6 > 3<br />

y + 6 – 6 > 3 – 6<br />

y > –3<br />

8. Example – Solve –18 < t – 7. Graph the solution set.<br />

–18 < t – 7<br />

–18 + (7) < t – 7 + (7)<br />

–11 < t<br />

9. Example – Solve 2m + 9 < m + 4. Graph the solution set.<br />

2m + 9 < m + 4<br />

m + 9 < 4<br />

m < – 5<br />

10. We know that 18 > –11 is a true inequality. If you multiply each side of this<br />

inequality by a positive number, the result is a true inequality.<br />

18 > –11<br />

18 (3) > –11(3)<br />

54 > –33 TRUE<br />

What happens if we multiply by a<br />

negative number?<br />

<strong>Solving</strong> <strong>Inequalities</strong> Johnny Wolfe www.<strong>Beacon</strong>LC.org Jay High School Santa Rosa County Florida September 22, 2001


11. Suppose you multiply each side of a true inequality by a negative number.<br />

18 > –11<br />

18(–2) > –11(–2)<br />

–36 > 22 FALSE!<br />

We must reverse the inequality<br />

symbol when we multiply or<br />

divide by a negative number.<br />

12.<br />

Multiplication and Division Properties for <strong>Inequalities</strong><br />

1. If c is positive and a < b, then ac < bc and c<br />

a < c<br />

b .<br />

2. If c is positive and a > b, then ac > bc and c<br />

a > c<br />

b .<br />

3. If c is negative and a < b, then ac > bc and c<br />

a > c<br />

b .<br />

4. If c is negative and a > b, then ac > bc and c<br />

a < c<br />

b .<br />

13. The following examples may be used to illustrate the Multiplication and Division<br />

Properties.<br />

16 > –8<br />

–5 < –2<br />

16 − 8<br />

(–5)( –4) > –2(–4)<br />

<<br />

− 2 − 2<br />

20 > 8<br />

–8 < 4<br />

14. Example – Solve –0.5y < 6. Graph the solution set.<br />

–0.5y < 6<br />

(–2)( –0.5y) > (–2)(6)<br />

y > –12<br />

The solution set can be written {y|y > –12}. It is read the<br />

set of all numbers y such that y is greater than –12.<br />

This notation for solution sets is called<br />

set builder notation.<br />

<strong>Solving</strong> <strong>Inequalities</strong> Johnny Wolfe www.<strong>Beacon</strong>LC.org Jay High School Santa Rosa County Florida September 22, 2001


15. Example – Solve<br />

x −11<br />

− x ≥<br />

3<br />

–3x ≥ x – 11<br />

–4x ≥ – 11<br />

11<br />

x ≤ 4<br />

− x ≥<br />

x −11<br />

. Graph the solution set.<br />

3<br />

11<br />

The solution set can be written {x|x ≤ }. 4<br />

16. The symbols ≠ ,≤,<br />

and ≥ can also be used when comparing numbers. The symbol<br />

≠ means is not equal to. The symbol ≤ means is less than or equal to. The symbol<br />

≥ means is greater than or equal to.<br />

6x ≠ 18 means 6x > 18<br />

or 6x < 18<br />

17. Example – Solve 3x > –27. Graph the solution set.<br />

3x > –27<br />

x > –9<br />

The solution set is {x|x > –9}<br />

18. Example – Solve –3x > 27. Graph the solution set.<br />

–3x > 27<br />

x < –9<br />

The solution set is {x|x < –9}<br />

19. Example – Solve<br />

3y<br />

− + 6 ≥ 3<br />

4<br />

3y<br />

− ≥ –3<br />

4<br />

y ≤ 4<br />

The solution set is {y|y ≤ 4}<br />

3y<br />

− + 6 ≥ 3. Graph the solution set.<br />

4<br />

<strong>Solving</strong> <strong>Inequalities</strong> Johnny Wolfe www.<strong>Beacon</strong>LC.org Jay High School Santa Rosa County Florida September 22, 2001


20. Example – Solve 4a + 16 < –2(a + 4). Graph the solution set.<br />

4a + 16 < –2(a + 4)<br />

4a + 16 < –2a – 8<br />

6a < –24<br />

a < –4<br />

The solution set is {a|a < –4}<br />

21. The absolute value of a number represents its distance from zero on the number<br />

line. You can use this idea to help solve absolute value inequalities.<br />

22. Example – Solve |x| < 3. Graph the solution set.<br />

|x| < 3 means the distance between x<br />

and 0 is less than 3 units. To make |3|<br />

true, you must substitute values for x<br />

that are less than 3 units from 0.<br />

All the numbers between –3 and 3<br />

are less than three units from zero.<br />

The solution set is {x|–3< x < 3}.<br />

23. Example – Solve |x| ≥ 2. Graph the solution set.<br />

To make this true, you must<br />

substitute values for x that are 2<br />

or more units from 0.<br />

The solution set is {x|x ≥ 2 or<br />

x ≤ –2}.<br />

24. Example – Solve |2x – 5| > 9. Graph the solution set.<br />

The inequality |2x – 5| > 9 says that 2x – 5 is more than 9 units from 0.<br />

2x – 5 > 9<br />

2x > 14<br />

x > 7<br />

OR<br />

2x – 5 < –9<br />

2x < –4<br />

x < –2 The solution set is {x|x < –2 or x > 7}<br />

<strong>Solving</strong> <strong>Inequalities</strong> Johnny Wolfe www.<strong>Beacon</strong>LC.org Jay High School Santa Rosa County Florida September 22, 2001


25. Example – Solve |8x| ≤ 24. Graph the solution set.<br />

The inequality |8x| ≤ 24 says that 8x is less than 24 units from 0.<br />

8x ≤ 24<br />

x ≤ 3<br />

AND<br />

8x ≥ –24<br />

x ≥ –3<br />

The solution set is {x|–3 ≤ x ≤ 3}<br />

26. Example – Solve |x + 2| > 5. Graph the solution set.<br />

The inequality |x + 2| > 5 says that x + 2 is more than 5 units from 0.<br />

x + 2 > 5<br />

x > 3<br />

OR<br />

x + 2 < –5<br />

x < –7<br />

The solution set is {x|x >3 or x < –7}<br />

27. Example – Solve |2x + 3| + 4 < 5. Graph the solution set.<br />

First rewrite the inequality by subtracting 4 from each side |2x + 3| < 1<br />

The inequality |2x + 3| < 1 says that 2x + 3 is less than 1 units from 0.<br />

2x + 3 < 1<br />

2x < –2<br />

x < –1<br />

AND<br />

2x + 3 > –1<br />

2x > –4<br />

x > –2 The solution set is {x|–2 < x < –1}<br />

<strong>Solving</strong> <strong>Inequalities</strong> Johnny Wolfe www.<strong>Beacon</strong>LC.org Jay High School Santa Rosa County Florida September 22, 2001


28. Example – Solve |3x – 8| < 19. Graph the solution set.<br />

The inequality |3x – 8| < 19 says that 3x – 8 is less than 19 units from 0.<br />

3x – 8 < 19<br />

3x < 27<br />

x < 9<br />

AND<br />

3x – 8 > –19<br />

3x > –11<br />

11<br />

11<br />

x > − The solution set is {x| − < x < 9}<br />

3<br />

3<br />

29. Some absolute value inequalities have no solutions. For example, |4x – 9| < –7 is<br />

never true. Since the absolute value of a number is always positive or zero, there<br />

is not replacement for x that will make the sentence true. The inequality<br />

|4x – 9| < –7 has no solution. Therefore, its solution set is Ø.<br />

30. Some absolute value inequalities are always true. For example, |10x + 3| > –5 is<br />

always true. Since the absolute value of a number is always positive or zero, any<br />

replacement for x will make the sentence true. The solution set for |10x + 3| > –5<br />

is the set of real numbers.<br />

31. Example – Solve |6x + 2| + 5 > 3. Graph the solution set.<br />

First rewrite the inequality by subtracting 5 from each side<br />

|6x + 2| > –2<br />

The solution is all numbers since<br />

this statement is always true.<br />

<strong>Solving</strong> <strong>Inequalities</strong> Johnny Wolfe www.<strong>Beacon</strong>LC.org Jay High School Santa Rosa County Florida September 22, 2001


32. Example – Solve |6x – 8| + 9 < 3. Graph the solution set.<br />

Rewrite the inequality by subtracting nine from each side<br />

|6x – 8| < –6<br />

There are no solutions since this<br />

statement is always false.<br />

<strong>Solving</strong> <strong>Inequalities</strong> Johnny Wolfe www.<strong>Beacon</strong>LC.org Jay High School Santa Rosa County Florida September 22, 2001


Name:___________________<br />

Date:____________<br />

Class:___________________<br />

Graph the solution set of each inequality.<br />

<strong>Solving</strong> <strong>Inequalities</strong> Worksheet<br />

1. x > –3<br />

2. a ≤ 0<br />

3. p ≥ 4 2<br />

1<br />

4. x < –7.5<br />

5.<br />

5 k ≤ 10<br />

6<br />

6. –3n > 6<br />

Solve each inequality. Graph the solution set.<br />

7. 3x + 7 > 43<br />

8. 7x – 5 ≥ 44<br />

9. 8 – 3x < 44<br />

10. x – 5 < 0.1<br />

12. 3x + 1 < x + 5<br />

13. 0.01x – 2.32 ≥ 0<br />

14.<br />

2 x + 3<br />

5<br />

< 0.03<br />

11. 5(3x + 2) > 7x – 2<br />

State an absolute value inequality for each of the following. Then graph each<br />

inequality.<br />

15. All numbers between –3 and 3.<br />

16. All numbers less than 8 and greater than –8.<br />

17. All numbers greater than 6 or less than –6.<br />

18. All numbers less than or equal to 5, and greater than or equal to –5.<br />

19. x > 3 or x < –3<br />

20. x < 6 and x > –6<br />

21. x ≤ 4 and x ≥ –4<br />

<strong>Solving</strong> <strong>Inequalities</strong> Johnny Wolfe www.<strong>Beacon</strong>LC.org Jay High School Santa Rosa County Florida September 22, 2001


Solve each inequality. Graph each solution set.<br />

22. |x| < 9<br />

23. |x| ≥ 2<br />

24. |x + 1| > 3<br />

25. |3x| < 6<br />

26. |2x| ≥ –64<br />

27. |3x| < –15<br />

28. |6x + 25| + 14 < 6<br />

29. 6 + |3x| > 0<br />

<strong>Solving</strong> <strong>Inequalities</strong> Johnny Wolfe www.<strong>Beacon</strong>LC.org Jay High School Santa Rosa County Florida September 22, 2001


Name:___________________<br />

Date:____________<br />

Class:___________________<br />

<strong>Solving</strong> <strong>Inequalities</strong> Worksheet Key<br />

Graph the solution set of each inequality.<br />

1. x > –3<br />

2. a ≤ 0<br />

3. p ≥ 4 2<br />

1<br />

4. x < –7.5<br />

5.<br />

5 k ≤ 10 k ≤ 12<br />

6<br />

6. –3n > 6 n < –2<br />

Solve each inequality. Graph the solution set.<br />

7. 3x + 7 > 43 3x > 36 x > 12<br />

8. 7x – 5 ≥ 44 7x ≥ 49 x ≥ 7<br />

9. 8 – 3x < 44 – 3x < 36 x > –12<br />

10. x – 5 < 0.1 x < 5.1<br />

<strong>Solving</strong> <strong>Inequalities</strong> Johnny Wolfe www.<strong>Beacon</strong>LC.org Jay High School Santa Rosa County Florida September 22, 2001


11. 5(3x + 2) > 7x – 2 15x + 10 > 7x – 2 8x > –12 x ><br />

1<br />

− 1<br />

2<br />

12. 3x + 1 < x + 5 2x < 4 x < 2<br />

13. 0.01x – 2.32 ≥ 0 0.01x ≥ 2.32 x ≥ 232<br />

14.<br />

2 x + 3<br />

5<br />

< 0.03 2x + 3 < 0.15 2x < –2.85 x < –1.425<br />

State an absolute value inequality for each of the following. Then graph each inequality.<br />

15. All numbers between –3 and 3. |x| < 3<br />

16. All numbers less than 8 and greater than –8. |x| > 8<br />

17. All numbers greater than 6 or less than –6. |x| > 6<br />

18. All numbers less than or equal to 5, and greater than or equal to –5. |x| ≤ 5<br />

19. x > 3 or x < –3 |x| > 3<br />

<strong>Solving</strong> <strong>Inequalities</strong> Johnny Wolfe www.<strong>Beacon</strong>LC.org Jay High School Santa Rosa County Florida September 22, 2001


20. x < 6 and x > –6 |x| < 6<br />

21. x ≤ 4 and x ≥ –4 |x| ≤ 4<br />

Solve each inequality. Graph each solution set.<br />

22. |x| < 9<br />

x < 9 and x > –9<br />

23. |x| ≥ 2<br />

x ≤ –2 or x ≥ 2<br />

24. |x + 1| > 3<br />

x + 1 < –3<br />

x < –4<br />

or<br />

x + 1 > 3<br />

x > 2<br />

25. |3x| < 6<br />

3x > –6<br />

x > –2<br />

and<br />

3x < 6<br />

x < 2<br />

26. |2x| ≥ –64<br />

Since absolute values must be<br />

positive, all numbers work.<br />

27. |3x| < –15<br />

Since absolute values must be<br />

positive, no numbers work Ǿ<br />

28. |6x + 25| + 14 < 6<br />

First rewrite inequality by subtracting 6 from each side.<br />

(6x + 25| < –8<br />

Since absolute values must be positive, no<br />

numbers work Ǿ<br />

<strong>Solving</strong> <strong>Inequalities</strong> Johnny Wolfe www.<strong>Beacon</strong>LC.org Jay High School Santa Rosa County Florida September 22, 2001


29. 6 + |3x| > 0 First rewrite inequality by subtracting 6 from each side.<br />

|3x| > –6<br />

Since absolute values must be positive, all numbers work.<br />

<strong>Solving</strong> <strong>Inequalities</strong> Johnny Wolfe www.<strong>Beacon</strong>LC.org Jay High School Santa Rosa County Florida September 22, 2001


Student Name: __________________<br />

Date: ______________<br />

<strong>Solving</strong> <strong>Inequalities</strong> Checklist<br />

1. On questions 1 thru 6, did the student graph the inequality correctly?<br />

a. Yes (30 points)<br />

b. 5 out of 6 (25 points)<br />

c. 4 out of 6 (20 points)<br />

d. 3 out of 6 (15 points)<br />

e. 2 out of 6 (10 points)<br />

f. 1 out of 6 (5 points)<br />

2. On questions 7 thru 14, did the student solve the inequality correctly?<br />

a. Yes (40 points)<br />

b. 7 out of 8 (35 points)<br />

c. 6 out of 8 (30 points)<br />

d. 5 out of 8 (25 points)<br />

e. 4 out of 8 (20 points)<br />

f. 3 out of 8 (15 points)<br />

g. 2 out of 8 (10 points)<br />

h. 1 out of 8 (5 points)<br />

3. On questions 7 thru 14, did the student graph the inequality correctly?<br />

a. Yes (40 points)<br />

b. 7 out of 8 (35 points)<br />

c. 6 out of 8 (30 points)<br />

d. 5 out of 8 (25 points)<br />

e. 4 out of 8 (20 points)<br />

f. 3 out of 8 (15 points)<br />

g. 2 out of 8 (10 points)<br />

h. 1 out of 8 (5 points)<br />

4. On questions 15 thru 21, did the student state a correct absolute value for each inequality?<br />

a. Yes (35 points)<br />

b. 6 out of 7 (30 points)<br />

c. 5 out of 7 (25 points)<br />

d. 4 out of 7 (20 points)<br />

e. 3 out of 7 (15 points)<br />

f. 2 out of 7 (10 points)<br />

g. 1 out of 7 (5 points)<br />

5. On questions 15 thru 21, did the student graph the inequality correctly?<br />

a. Yes (35 points)<br />

b. 6 out of 7 (30 points)<br />

c. 5 out of 7 (25 points)<br />

d. 4 out of 7 (20 points)<br />

e. 3 out of 7 (15 points)<br />

f. 2 out of 7 (10 points)<br />

g. 1 out of 7 (5 points)<br />

6. On questions 22 thru 29, did the student solve the inequality correctly?<br />

a. Yes (40 points)<br />

b. 7 out of 8 (35 points)<br />

c. 6 out of 8 (30 points)<br />

d. 5 out of 8 (25 points)<br />

e. 4 out of 8 (20 points)<br />

f. 3 out of 8 (15 points)<br />

g. 2 out of 8 (10 points)<br />

h. 1 out of 8 (5 points)<br />

Total Number of Points _________<br />

A 198 points and above<br />

B 176 points and above<br />

Any score below C<br />

needs<br />

remediation!<br />

C 154 points and above<br />

D 132 points and above<br />

F<br />

131 points and below<br />

NOTE: The sole purpose of this checklist is to aide the teacher<br />

in identifying students that need remediation. Students who<br />

meet the “C” criteria are ready for the next level of learning.<br />

<strong>Solving</strong> <strong>Inequalities</strong> Johnny Wolfe www.<strong>Beacon</strong>LC.org Jay High School Santa Rosa County Florida September 22, 2001

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