Estimation, Evaluation, and Selection of Actuarial Models
Estimation, Evaluation, and Selection of Actuarial Models
Estimation, Evaluation, and Selection of Actuarial Models
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5.3. THE GENERALIZED LINEAR MODEL 93<br />
<strong>and</strong> the additional parameters must not depend on the mean. Let z be a vector <strong>of</strong> covariates for<br />
an individual, let β be a vector <strong>of</strong> coefficients, <strong>and</strong> let η(µ) <strong>and</strong> c(y) be functions. The generalized<br />
linear model then states that the r<strong>and</strong>om variable, X, has as its distribution function<br />
where µ is such that η(µ) =c(β T z).<br />
F (x|θ, β) =F (x|µ, θ)<br />
The model indicates that the mean <strong>of</strong> an individual observation is related to the covariates<br />
through a particular set <strong>of</strong> functions. Normally, these functions do not involve parameters, but<br />
instead are used to provide a good fit or to ensure that only legitimate values <strong>of</strong> µ are encountered.<br />
Example 5.11 Demonstrate that the ordinary linear regression model is a special case <strong>of</strong> the generalized<br />
linear model.<br />
For ordinary linear regression, X has a normal distribution with µ = µ <strong>and</strong> θ = σ. Bothη <strong>and</strong><br />
c are the identity function, resulting in µ = β T z. ¤<br />
The model presented here is more general than the one usually used. Usually, only a few<br />
distributions are allowed to be used for X. The reason is that for these distributions, people have<br />
been able to develop the full set <strong>of</strong> regression tools, such as residual analysis. Because such analyses<br />
are covered in a different part <strong>of</strong> Part 4, that restriction is not needed here.<br />
For many <strong>of</strong> the distributions we have been using, the mean is not a parameter. However, it<br />
could be. For example, we could parameterize the Pareto distribution by setting µ = θ/(α − 1) or<br />
equivalently, replacing θ with µ(α − 1). The distribution function is now<br />
· µ(α − 1)<br />
¸α<br />
F (x|µ, α) =1−<br />
, µ > 0, α > 1.<br />
µ(α − 1) + x<br />
Note the restriction on α in the parameter space.