Estimation, Evaluation, and Selection of Actuarial Models
Estimation, Evaluation, and Selection of Actuarial Models
Estimation, Evaluation, and Selection of Actuarial Models
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5.2. PROPORTIONAL HAZARDS MODELS 87<br />
One consequence <strong>of</strong> this model is that regardless <strong>of</strong> the age, the effect <strong>of</strong> switching from brick to<br />
wood is the same. For two houses <strong>of</strong> age z 1 we have<br />
The effect on the survival function is<br />
·<br />
S wood (x) = exp −<br />
h wood (x) =h 0 (x)e β 1 z 1+β 2 = h brick (x)e β 2.<br />
Z x<br />
= [S brick (x)] exp(β 2 ) .<br />
0<br />
¸ ·<br />
h wood (y)dy =exp −<br />
Z x<br />
0<br />
¸<br />
h brick (y)e β 2dy<br />
¤<br />
The baseline hazard rate function can be estimated using either a parametric model or a datadependent<br />
model. The remainder <strong>of</strong> the model is parametric. In the spirit <strong>of</strong> this Note, we will use<br />
maximum likelihood for estimation <strong>of</strong> β 1 <strong>and</strong> β 2 . We will begin with a fully parametric example.<br />
Example 5.4 For the fire insurance example, consider the following ten payments. All values are<br />
expressed as a percentage <strong>of</strong> the house’s value. Estimate the parameters <strong>of</strong> the Cox proportional<br />
hazards model using maximum likelihood <strong>and</strong> both an exponential <strong>and</strong> a beta distribution for the<br />
baseline hazard rate function. There is no deductible on these policies, but there is a policy limit<br />
(which differs by policy).<br />
z 1 z 2 payment<br />
10 0 70<br />
20 0 22<br />
30 0 90*<br />
40 0 81<br />
50 0 8<br />
10 1 51<br />
20 1 95*<br />
30 1 55<br />
40 1 85*<br />
50 1 93<br />
An asterisk indicates that the payment was made at the policy limit.<br />
In order to construct the likelihood function we need the density <strong>and</strong> survival functions. Let c j be<br />
the Cox multiplier for the jth observation. Then, as noted in the previous example, S j (x) =S 0 (x) c j<br />
,<br />
where S 0 (x) is the baseline distribution. The density function is<br />
For the exponential distribution,<br />
f j (x) = −Sj(x) 0 =−c j S 0 (x) cj−1 S0(x)<br />
0<br />
= c j S 0 (x) cj−1 f 0 (x).<br />
S j (x) =[e −x/θ ] c j<br />
= e −c jx/θ <strong>and</strong> f j (x) =(c j /θ)e −c jx/θ