Estimation, Evaluation, and Selection of Actuarial Models
Estimation, Evaluation, and Selection of Actuarial Models
Estimation, Evaluation, and Selection of Actuarial Models
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58 CHAPTER 3. SAMPLING PROPERTIES OF ESTIMATORS<br />
Changing the signs <strong>and</strong> inverting produces the same values as in (3.4). This is a feature <strong>of</strong> the<br />
lognormal distribution that need not hold for other models. ¤<br />
Sometimes it is not even possible to take the derivative. In that case an approximate second<br />
derivative can be used. A reasonable approximation is<br />
∂ 2 f(θ) . 1 = [f(θ + h i e i /2+h j e j /2) − f(θ + h i e i /2 − h j e j /2)<br />
∂θ i ∂θ j h i h j<br />
−f(θ − h i e i /2+h j e j /2) + f(θ − h i e i /2 − h j e j /2)]<br />
where e i is a vector with all zeroes except for a one in the ith position <strong>and</strong> h i = θ i /10 v where v is<br />
one-third the number <strong>of</strong> significant digits used in calculations.<br />
Example 3.32 Repeat the previous example, using approximate derivatives.<br />
Assume that there are 15 significant digits being used. Then h 1 = 6.1379/10 5 <strong>and</strong> h 2 =<br />
1.3894/10 5 . Reasonably close values are 0.00006 <strong>and</strong> 0.00001. The first approximation is<br />
∂ 2 l<br />
∂µ 2 . =<br />
l(6.13796, 1.3894) − 2l(6.1379, 1.3894) + l(6.13784, 1.3894)<br />
(0.00006) 2<br />
=<br />
−157.713893081982 − 2(−157.713893049683) + (−157.713893054682)<br />
(0.00006) 2<br />
= −10.3604.<br />
The other two approximations are<br />
∂ 2 l/∂σ∂µ = . 0.0003<br />
∂ 2 l/∂σ 2 . = −20.7208.<br />
We see that here the approximation works very well. ¤<br />
For grouped data, the process works the same way. In Loss <strong>Models</strong> on pages 59 <strong>and</strong> 66 it is<br />
noted that the information can be obtained using only first partial derivatives. These still may<br />
need to be numerically evaluated.<br />
Exercise 67 Determine 95% confidence intervals for the parameters <strong>of</strong> exponential <strong>and</strong> gamma<br />
models for Data Set B. The likelihood function <strong>and</strong> maximum likelihood estimates were determined<br />
in Example 2.32.<br />
Exercise 68 Let X have a uniform distribution on the interval from 0 to θ. Show that the maximum<br />
likelihood estimator is ˆθ =max(X 1 ,...,X n ). Use Examples 3.7 <strong>and</strong> 3.10 to show that this<br />
estimator is asymptotically unbiased <strong>and</strong> to obtain its variance. Show that Theorem 3.29 yields a<br />
negative estimate <strong>of</strong> the variance <strong>and</strong> that item (ii) in the conditions does not hold.<br />
The information matrix provides a method for assessing the quality <strong>of</strong> the maximum likelihood<br />
estimators <strong>of</strong> a distribution’s parameters. However, we are <strong>of</strong>ten more interested in a quantity that