Estimation, Evaluation, and Selection of Actuarial Models
Estimation, Evaluation, and Selection of Actuarial Models
Estimation, Evaluation, and Selection of Actuarial Models
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46 CHAPTER 3. SAMPLING PROPERTIES OF ESTIMATORS<br />
Suppose the value <strong>of</strong> x is between the boundaries c j−1 <strong>and</strong> c j .LetY be the number <strong>of</strong> observations<br />
at or below c j−1 <strong>and</strong> let Z be the number <strong>of</strong> observations above c j−1 <strong>and</strong> at or below c j .<br />
Then<br />
S n (x) =1− Y (c j − c j−1 )+Z(x − c j−1 )<br />
n(c j − c j−1 )<br />
<strong>and</strong><br />
E[S n (x)] = 1 − n[1 − S(c j−1)](c j − c j−1 )+n[S(c j−1 ) − S(c j )](x − c j−1 )<br />
n(c j − c j−1 )<br />
= S(c j−1 ) c j − x<br />
+ S(c j ) x − c j−1<br />
.<br />
c j − c j−1 c j − c j−1<br />
This estimator is biased (although it is an unbiased estimator <strong>of</strong> the true interpolated value). The<br />
variance is<br />
Var[S n (x)] = (c j − c j−1 ) 2 Var(Y )+(x − c j−1 ) 2 Var(Z)+2(c j − c j−1 )(x − c j−1 )Cov(Y,Z)<br />
[n(c j − c j−1 )] 2<br />
where Var(Y )=nS(c j−1 )[1 − S(c j−1 )], Var(Z) =n[S(c j−1 ) − S(c j )][1 − S(c j−1 )+S(c j )], <strong>and</strong><br />
Cov(Y,Z) =−n[1 − S(c j−1 )][S(c j−1 ) − S(c j )]. For the density estimate,<br />
f n (x) =<br />
Z<br />
n(c j − c j−1 )<br />
<strong>and</strong><br />
E[f n (x)] = S(c j−1) − S(c j )<br />
c j − c j−1<br />
which is biased for the true density function. The variance is<br />
Var[f n (x)] = [S(c j−1) − S(c j )][1 − S(c j−1 )+S(c j )]<br />
n(c j − c j−1 ) 2 .<br />
¤<br />
Example 3.20 For Data Set C estimate S(10,000), f(10,000) <strong>and</strong> the variance <strong>of</strong> your estimators.<br />
The point estimates are<br />
99(17,500 − 7,500) + 42(10,000 − 7,500)<br />
S 227 (10, 000) = 1 − =0.51762<br />
227(17,500 − 7,500)<br />
42<br />
f 227 (10,000) =<br />
227(17,500 − 7,500) =0.000018502.<br />
The estimated variances are<br />
<strong>and</strong><br />
dVar[S 227 (10,000)] =<br />
99<br />
10,0002<br />
227 227 128<br />
42<br />
+2,5002<br />
227 227 185<br />
99<br />
− 2(10,000)(2,500)<br />
227 227<br />
42<br />
227(10,000) 2 =0.00094713<br />
42 185<br />
227 227<br />
dVar[f 227 (10,000)] =<br />
227(10,000) 2 =6.6427 × 10−12 .