Estimation, Evaluation, and Selection of Actuarial Models
Estimation, Evaluation, and Selection of Actuarial Models
Estimation, Evaluation, and Selection of Actuarial Models
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3.2. MEASURES OF QUALITY 39<br />
1 2 3 5 2 3 4 6<br />
3 4 5 7 5 6 7 9<br />
Combining the common values, the sample mean, usually denoted ¯X, has the following probability<br />
distribution.<br />
x p ¯X(x)<br />
1 1/16<br />
2 2/16<br />
3 3/16<br />
4 2/16<br />
5 3/16<br />
6 2/16<br />
7 2/16<br />
9 1/16<br />
The expected value <strong>of</strong> the estimator is<br />
E( ¯X) = [1(1) + 2(2) + 3(3) + 4(2) + 5(3) + 6(2) + 7(2) + 9(1)]/16 = 4.5<br />
<strong>and</strong> so the sample mean is an unbiased estimator <strong>of</strong> the population mean for this example. ¤<br />
Example 3.5 For Example 3.2 determine the bias <strong>of</strong> the sample mean <strong>and</strong> the sample median as<br />
estimators <strong>of</strong> the population mean.<br />
Thesamplemeanis ¯X =(X 1 + X 2 + X 3 )/3 where each X j represents one <strong>of</strong> the observations<br />
from the exponential population. Its expected value is<br />
µ <br />
E( ¯X)<br />
X1 + X 2 + X 3<br />
=E<br />
= 1 3<br />
3 [E(X 1)+E(X 2 )+E(X 3 )] = 1 (θ + θ + θ) =θ<br />
3<br />
<strong>and</strong> therefore the sample mean is an unbiased estimator <strong>of</strong> the population mean.<br />
Investigating the sample median is a bit more difficult. The distribution function <strong>of</strong> the middle<br />
<strong>of</strong> three observations can be found as follows, using Y as the r<strong>and</strong>om variable <strong>of</strong> interest <strong>and</strong> X as<br />
the r<strong>and</strong>om variable for an observation from the population.<br />
F Y (y) = Pr(Y ≤ y) =Pr(X 1 ,X 2 ,X 3 ≤ y)+Pr(X 1 ,X 2 ≤ y,X 3 >y)<br />
+Pr(X 1 ,X 3 ≤ y,X 2 >y)+Pr(X 2 ,X 3 ≤ y, X 1 >y)<br />
= F X (y) 3 +3F X (y) 2 [1 − F X (y)]<br />
= [1− e −y/θ ] 3 +3[1− e −y/θ ] 2 e −y/θ .<br />
The density function is<br />
f Y (y) =F 0 Y (y) = 6 θ<br />
³e −2y/θ − e −3y/θ´<br />
.<br />
The expected value <strong>of</strong> this estimator is<br />
E(Y |θ) =<br />
Z ∞<br />
0<br />
= 5θ<br />
6 .<br />
y 6 θ<br />
³e −2y/θ − e −3y/θ´<br />
dy