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Estimation, Evaluation, and Selection of Actuarial Models

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34 CHAPTER 2. MODEL ESTIMATION<br />

where x j is one <strong>of</strong> the observed values, p(x j |θ) is the probability <strong>of</strong> observing x j ,<strong>and</strong>n j is the<br />

number <strong>of</strong> times x j was observed in the sample. For a Poisson distribution<br />

L(λ) =<br />

∞Y<br />

µ e −λ λ x nx ∞Y e −nxλ λ xnx<br />

=<br />

x!<br />

x! nx<br />

x=0<br />

x=0<br />

l(λ) =<br />

∞X<br />

∞X<br />

[−n x λ + xn x ln λ − n x ln x!] = −nλ + n¯x ln λ − n x ln x!<br />

x=0<br />

l 0 (λ) = −n + n¯x/λ =0, ˆλ =¯x.<br />

For a binomial distribution<br />

mY<br />

·µ m m−x¸nx mY<br />

L(q) =<br />

q x (1 − q) =<br />

x<br />

l(q) =<br />

l 0 (q) =<br />

x=0<br />

x=0<br />

m! n x<br />

q xn x<br />

(1 − q) (m−x)n x<br />

x! n x (m − x)! n x<br />

mX<br />

[n x ln m!+xn x ln q +(m − x)n x ln(1 − q) − n x ln x! − n x ln(m − x)!]<br />

x=0<br />

mX<br />

x=0<br />

xn x<br />

q<br />

− (m − x)n x<br />

1 − q<br />

= n¯x<br />

q<br />

−<br />

mn − n¯x<br />

1 − q<br />

=0, ˆq =¯x/m.<br />

For this problem, ¯x =[81, 714(0) + 11, 306(1) + 1, 618(2) + 250(3) + 40(4) + 7(5)]/94, 935 = 0.16313.<br />

Therefore ˆλ =0.16313 <strong>and</strong> ˆq =0.16313/8 =0.02039. ¤<br />

Exercise 32 Repeat the previous example, but this time assume that the actual values for the 7<br />

drivers who have 5 or more accidents are unknown.<br />

Exercise 33 (*) Lives are observed in order to estimate q 35 . Ten lives are first observed at age<br />

35.4 <strong>and</strong> six die prior to age 36 while the other four survive to age 36. An additional twenty lives<br />

are first observed at age 35 <strong>and</strong> eight die prior to age 36 with the other twelve surviving to age 36.<br />

Determine the maximum likelihood estimate <strong>of</strong> q 35 given that the time to death from age 35 has<br />

density function f(t) =w, 0 ≤ t ≤ 1 with f(t) unspecified for t>1.<br />

Exercise 34 (*) The model has hazard rate function h(t) =λ 1 , 0 ≤ t

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