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Estimation, Evaluation, and Selection of Actuarial Models

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125<br />

x F (x) compare to max difference<br />

0.1 0.174 0, 0.2 0.174<br />

0.2 0.306 0.2, 0.4 0.106<br />

0.5 0.556 0.4, 0.6 0.156<br />

1.0 0.750 0.6, 0.8 0.150<br />

1.3 0.811 0.8, 1 0.189<br />

The test statistic is the maximum from the final column, 0.189.<br />

Exercise 81 For Data Set B truncated at 50, the test statistic is 0.1631 which is less than the<br />

critical value <strong>of</strong> 2.492 <strong>and</strong> the null hypothesis is not rejected. For Data Set B censored at 1,000,<br />

the test statistic is 0.1712 <strong>and</strong> the null hypothesis is again not rejected.<br />

Exercise 82 The calculations for Data Set B truncated at 50 are in the following table:<br />

Range ˆp Expected Observed χ 2<br />

50—150 0.1599 3.038 3 0.0005<br />

150—250 0.1181 2.244 3 0.2545<br />

250—500 0.2064 3.922 4 0.0015<br />

500—1,000 0.2299 4.368 4 0.0310<br />

1,000—2,000 0.1842 3.500 3 0.0713<br />

2,000—∞ 0.1015 1.928 2 0.0027<br />

The sum is 0.3615. With three degrees <strong>of</strong> freedom, the critical value is 7.8147 <strong>and</strong> the Weibull<br />

model is not rejected. The p-value is 0.9481.<br />

The calculations for Data Set B censored at 1,000 are in the following table:<br />

Range ˆp Expected Observed χ 2<br />

0—150 0.1886 3.772 4 0.0138<br />

150—250 0.1055 2.110 3 0.3754<br />

250—500 0.2076 4.151 4 0.0055<br />

500—1,000 0.2500 4.999 4 0.1997<br />

1,000—∞ 0.2484 4.968 5 0.0002<br />

The sum is 0.5947. With two degrees <strong>of</strong> freedom, the critical value is 5.9915 <strong>and</strong> the Weibull model<br />

is not rejected. The p-value is 0.7428.<br />

The calculations for Data Set C are in the following table:<br />

Range ˆp Expected Observed χ 2<br />

7,500—17,500 0.3299 42.230 42 0.0013<br />

17,500—32,500 0.2273 29.096 29 0.0003<br />

32,500—67,500 0.2178 27.878 28 0.0005<br />

67,500—125,000 0.1226 15.690 17 0.1094<br />

125,000—300,000 0.0818 10.472 9 0.2070<br />

300,000—∞ 0.0206 2.632 3 0.0513<br />

The sum is 0.3698. With three degrees <strong>of</strong> freedom, the critical value is 7.8147 <strong>and</strong> the Weibull<br />

model is not rejected. The p-value is 0.9464.<br />

Exercise 83 The calculations are in the following table:

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