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Estimation, Evaluation, and Selection of Actuarial Models

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101<br />

f(x)<br />

1<br />

0.9<br />

0.8<br />

0.7<br />

0.6<br />

0.5<br />

0.4<br />

0.3<br />

0.2<br />

0.1<br />

0<br />

0 1 2 3 4 5 6<br />

x<br />

Triangular kernel for Exercise 13<br />

This is clearly not satisfactory. The gamma kernel is not available because there would be<br />

positive probability at values greater than 5. Your author tried to solve this by using the beta<br />

distribution (see LMA). With θ knowntobe5,themean(tobesetequaltoy) is5a/(a + b). In<br />

order to have some smoothing control <strong>and</strong> to determine parameter values, the sum a + b was fixed.<br />

In the following graph, a value <strong>of</strong> 50 was used for the sum. The kernel is<br />

k y (x) =<br />

Γ(50)<br />

³ x<br />

´10y ³<br />

1 − x ´50−10y−1 1<br />

Γ(10y)Γ(50 − 10y) 5 5 x , 0

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