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Appendix MARS AND D&M PYRAMID ... - Souls of Distortion

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<strong>Appendix</strong> to “The D&M Pyramid – the Sibling <strong>of</strong> the Great Pyramid <strong>of</strong> Giza?” 2<br />

A3. Mars radii and intrinsic units <strong>of</strong> measure<br />

The basic linear measures <strong>of</strong> Mars are as follows [6]<br />

Equatorial radius<br />

Polar radius<br />

R E = 3402.5 km;<br />

R = 3377.4 km.<br />

P<br />

Comment A2. Find the intrinsic units <strong>of</strong> linear measure for Mars by analogy with the geographical mile.<br />

A3.1. The lengths <strong>of</strong> 1° and 1’ <strong>of</strong> Equator<br />

2πRE<br />

Λ E = = 59.38483 (km /degree);<br />

360°<br />

ΛE λ E = 10 3<br />

60 × = 989.7471 (m/arc min).<br />

A3.2. Find the length <strong>of</strong> 1° <strong>of</strong> the latitudinal circle for the latitude <strong>of</strong> the D&M.<br />

Consider a cross-section <strong>of</strong> Mars as ellipse with semi-axes a = R and b = R (Fig. A1).<br />

R P<br />

ψr<br />

R ψ<br />

E<br />

P<br />

ψ<br />

R E<br />

Fig. A1. Radius r ψ <strong>of</strong> the latitudinal circle for the D&M pyramid<br />

2<br />

2<br />

2<br />

2<br />

The radius-vector R ψ for D&M makes Rψ<br />

= ( RE<br />

cosψ<br />

) + ( RP<br />

sinψ<br />

) = 3391 .871 , where ψ = 40.65°<br />

is its latitude (See A4). Then, the radius r ψ <strong>of</strong> its latitudinal circle is equal to r ψ = R ψ cos ( ψ )<br />

= 3391.871× cos 40. 65 = 2573.423 (km) and the lengths <strong>of</strong> 1° and 1’ <strong>of</strong> D&M latitudinal circle make<br />

2πr<br />

ψ<br />

Λ D = = 44.9147 (km /degree);<br />

360°<br />

Λ<br />

λ D =<br />

D 10 3<br />

60 × = 748.578 (m/arc min).<br />

A3.3. Find the average length <strong>of</strong> 1° <strong>of</strong> meridian.<br />

The following approximation gives the length <strong>of</strong> ellipse with half-axes a and b<br />

64 − 3λ<br />

a − b<br />

L ≈ π(<br />

a + b ) , λ = .<br />

2<br />

64 − 16λ<br />

a + b<br />

64 − 3λ<br />

Hence, for Mars we obtain λ = 0. 003702 , L ≈ π( 3402.5 + 3377.4 ) = 21 299. 757 (km), and<br />

2<br />

64 − 16λ<br />

the average length <strong>of</strong> 1° and 1’ <strong>of</strong> Meridian make<br />

ΛM<br />

L<br />

= 360°<br />

Λ<br />

M<br />

λM = × 10<br />

60<br />

4<br />

= 59.16599 (km/degree);<br />

3<br />

= 986 (m/arc min).<br />

4

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