1 Kenneth R. Laker, University of Pennsylvania, updated 15Jan09
1 Kenneth R. Laker, University of Pennsylvania, updated 15Jan09 1 Kenneth R. Laker, University of Pennsylvania, updated 15Jan09
Gate Level Schematic of One-Bit Full Adder Circuit 33 AB⋅CA⋅B ABC⋅CARRYOUT A⋅B⋅C ABC ⋅CARRYOUT Kenneth R. Laker, University of Pennsylvania, updated 15Jan09
Show SUMOUT=A⋅B⋅C ABC ⋅CARRYOUT = A + B + C 34 CARRYOUT= AB⋅C A⋅B= A⋅CB⋅CA⋅B Using DeMorgan's Theorem CARRYOUT= A⋅CB⋅C A⋅B= A⋅C⋅B⋅C⋅ A⋅B = A⋅C⋅ B⋅C ⋅ A⋅B= AC⋅ BC⋅ AB = A⋅BA⋅CC⋅BC⋅ AB = A⋅BA⋅C A⋅B⋅CA⋅C A⋅B A⋅B⋅CB⋅CB⋅C = A⋅B A⋅C A⋅B⋅CB⋅C SUMOUT=A⋅B⋅C ABC ⋅CARRYOUT = A⋅B⋅C ABC ⋅ A⋅B A⋅CA⋅B⋅CB⋅C = A⋅B⋅CA⋅B⋅CA⋅B⋅C A⋅B⋅C Kenneth R. Laker, University of Pennsylvania, updated 15Jan09
- Page 1 and 2: Kenneth R. Laker, University of Pen
- Page 3 and 4: Kenneth R. Laker, University of Pen
- Page 5 and 6: “ Moore's Law” Impact on Micro-
- Page 7 and 8: Moore's Law and More 7 Kenneth R. L
- Page 9 and 10: 9 DPE -> Digital Processing Engine
- Page 11 and 12: 11 Digital CMOS Basics Kenneth R. L
- Page 13 and 14: 13 Kenneth R. Laker, University of
- Page 15 and 16: Ideal nMOS and pMOS Characteristics
- Page 17 and 18: Ideal CMOS Inverter 17 Inverter Tru
- Page 19 and 20: Two-Input CMOS NOR Gate 19 DeMorgan
- Page 21 and 22: 21 F = A⋅BC⋅D Combing the N-Hal
- Page 23 and 24: 23 Some VLSI Fundamentals Kenneth R
- Page 25 and 26: Typical Digital VLSI Design Abstrac
- Page 27 and 28: 27 Goal of All VLSI Design Enterpri
- Page 29 and 30: VLSI Design Cycle 29 Kenneth R. Lak
- Page 31 and 32: Bit-Sliced Data Path Control Bit N
- Page 33: 32 A B Two-Input Exclusive OR Gate
- Page 37 and 38: Initial Layout of One-Bit Full Adde
- Page 39: Simulated Performance of One-Bit Fu
Show<br />
SUMOUT=A⋅B⋅C ABC ⋅CARRYOUT = A + B + C<br />
34<br />
CARRYOUT= AB⋅C A⋅B= A⋅CB⋅CA⋅B<br />
Using DeMorgan's Theorem<br />
CARRYOUT= A⋅CB⋅C A⋅B= A⋅C⋅B⋅C⋅ A⋅B<br />
= A⋅C⋅ B⋅C ⋅ A⋅B= AC⋅ BC⋅ AB<br />
= A⋅BA⋅CC⋅BC⋅ AB<br />
= A⋅BA⋅C A⋅B⋅CA⋅C A⋅B A⋅B⋅CB⋅CB⋅C<br />
= A⋅B A⋅C A⋅B⋅CB⋅C<br />
SUMOUT=A⋅B⋅C ABC ⋅CARRYOUT<br />
= A⋅B⋅C ABC ⋅ A⋅B A⋅CA⋅B⋅CB⋅C<br />
= A⋅B⋅CA⋅B⋅CA⋅B⋅C A⋅B⋅C<br />
<strong>Kenneth</strong> R. <strong>Laker</strong>, <strong>University</strong> <strong>of</strong> <strong>Pennsylvania</strong>, <strong>updated</strong> <strong>15Jan09</strong>
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