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Mathematics 30 June 1999 Grade 12 Diploma Exam

Mathematics 30 June 1999 Grade 12 Diploma Exam

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• Algebraically solve the equation 3 x + 2 = 6 x and give the solution, correct to the nearest<br />

hundredth.<br />

A POSSIBLE SOLUTION<br />

3 x + 2 =6 x<br />

log 3 x + 2 = log 6 x<br />

(x + 2)log 3 = x log 6<br />

x log 3 + 2 log 3 = x log 6<br />

2 log 3 = x log 6 – x log 3<br />

2 log 3 = x (log 6 – log 3)<br />

2log3<br />

log6−<br />

log 3<br />

= x<br />

3.17 = x<br />

10

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