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Lab #9<br />

Hooke’s Law and the<br />

Physics 111 Simple Pendulum Name:<br />

I. Hooke’s Law: F = k Δx<br />

= k x − x ) = k(<br />

x − )<br />

spring<br />

(<br />

0<br />

x unstretche d<br />

A. The drawing shows a stationary mass hanging from a hypothetical<br />

spring with linear behavior governed by Hooke’s Law.<br />

ceiling<br />

x 0<br />

x<br />

[4 pts] Draw the free body diagram for<br />

the mass. Correctly <strong>lab</strong>el all forces on<br />

your free body diagram.<br />

Δx=17cm<br />

[4 pts] If the mass of the block is 250g, find the spring constant of the spring in units of<br />

Newtons/cm.<br />

B. The brass spring at your table exhibits the full range of spring behavior, including non-linear<br />

behavior. You’re going to use the computer interfaces to investigate this behavior.<br />

The spring at your table is called a “zero-length” spring. These springs have a tension on them<br />

even with no stretch. This is an example of non-linear behavior.<br />

x 0<br />

<br />

For this part of the <strong>lab</strong>, do the following:<br />

Start with the spring on the table with no tension on it.<br />

T<br />

<br />

<br />

<br />

<br />

<br />

<br />

“Zero” the force probe with it touching nothing.<br />

On the table, use chalk to mark the initial position x 0 of the end of the spring. Then, mark<br />

every 4.0cm beyond that to at least 50cm.<br />

Use the force probe to pull the spring out to various lengths Δx.<br />

Hold these in place for a couple of seconds so the computers can record the spring force.<br />

Stretch the springs out until you reach Δx~48cm.<br />

Use your data to fill out the table on the next page. NOTE: The units of the spring constant<br />

“k” will be Newtons/cm. You should only have 2 significant figures for “k.”<br />

Hooke’s Law & the Simple Pendulum HW–1


Lab #9<br />

Hooke’s Law and the<br />

Physics 111 Simple Pendulum Name:<br />

Stretch Δx(cm)<br />

x 1 = 0.0<br />

Force (N)<br />

F 1 = 0.0 N<br />

x 2 = 4.0 F 2 = k=(F 2 –F 1 )/(x 2 –x 1 )=<br />

x 3 = 8.0 F 3 = k=(F 3 –F 2 )/(x 3 –x 2 )=<br />

12<br />

16<br />

20<br />

24<br />

28<br />

32<br />

36<br />

40<br />

44<br />

48<br />

Data Table [15 pts]<br />

Spring constant k=ΔF/Δx (N/cm)<br />

(2 significant figures)<br />

[6 pts] On the graph provided to the<br />

right, plot your values for F and Δx.<br />

F (Newtons)<br />

These “zero length” springs have some<br />

initial tension built into them so their<br />

“resting state” is contracted. Once you<br />

get these springs stretched out just a<br />

little way, they act like traditional<br />

springs with a spring constant.<br />

[2 pts] What trend do you notice with<br />

your graph?<br />

0<br />

0<br />

Δx (cm)<br />

[2 pts] Approximately how far do you have to stretch<br />

the spring until it behaves like the traditional springs<br />

discussed in class?<br />

[2 pts] What value does the spring constant settle into?<br />

Hooke’s Law & the Simple Pendulum--2


Lab #9<br />

Hooke’s Law and the<br />

Physics 111 Simple Pendulum Name:<br />

II. The simple pendulum—simple harmonic motion example<br />

Set the photogate timers on “pend” and the timing accuracy (on their undersides) to “1ms.”<br />

Put a 100g mass on your string. Make the length of your string L=1.0 meter.<br />

A. [8 pts] Use the initial amplitudes listed below and determine the period of oscillation for each.<br />

Keep your length and mass constant.<br />

Amplitude A<br />

very small (~5cm)<br />

small (~10cm)<br />

medium (~15cm)<br />

large (~20cm)<br />

very large (~25cm)<br />

Period T (sec)<br />

Does the amplitude affect the period of oscillation of a pendulum? yes no (circle one)<br />

B. [8 pts] Use the masses listed below and determine the period of oscillation for each.<br />

Mass m<br />

50g<br />

100g<br />

200g<br />

500g<br />

Period T (sec)<br />

Does the mass on the pendulum affect the period of oscillation of a pendulum? yes no<br />

C. [8 pts] Use the string lengths listed below and determine the period of oscillation for each.<br />

For each of these,<br />

pay attention to<br />

large differences<br />

only.<br />

Length L<br />

40 cm<br />

60 cm<br />

80 cm<br />

100 cm<br />

120 cm<br />

Period T (sec)<br />

Does the length affect the period of oscillation of a pendulum? yes<br />

no<br />

As you have seen, not all of the variables of mass m, string length L and amplitude A come into play<br />

with the period of a pendulum. Oddly enough, the variables that you might suspect “surely would”<br />

determine the period of the pendulum have no effect. Thus, any equation that describes a simple<br />

pendulum should reflect that some variables matter while others don’t.<br />

Hooke’s Law & the Simple Pendulum--3


Lab #9<br />

Hooke’s Law and the<br />

Physics 111 Simple Pendulum Name:<br />

The period T and length L of a simple pendulum are related by the equation<br />

2<br />

2 4π L<br />

T = .<br />

g<br />

Here, g is the gravitational acceleration at the location of the pendulum. This assumes the oscillations<br />

have settled down into a consistent rhythm, and the amplitude of the oscillations is not too large. (The<br />

phrase “amplitude…not too large” means not more than about 20 0 away from the vertical.)<br />

[8 pts] Use your data with the various lengths on the previous page to calculate g for all 5 cases. Show<br />

your work for all 5 cases below. Your answers should have 3 significant figures.<br />

L=<br />

L=<br />

L=<br />

L=<br />

L=<br />

T=<br />

T=<br />

T=<br />

T=<br />

T=<br />

If any of your calculations indicate problems with the data, it is legitimate to throw out that point.<br />

[3 pts] Take the average of your values above for g: g = .<br />

[3 pts] How does your average value compare to the value of g=9.8 m/s 2 we so often use in class?<br />

Hooke’s Law & the Simple Pendulum--4

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