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TRIGONOMETRY

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<strong>TRIGONOMETRY</strong><br />

1) Use your calculator to find the value of x between 0 o and 90 o such that cos x = 1 2 .<br />

Hence, by using a sketch graph of y = cos x, or otherwise, find ALL 4 angles in the range 360 to 360 <br />

which have a COSine of 1 2 .<br />

2) i) By examining the symmetries of the graphs of y = sin x, y = cos x and y = tan x, determine if each of<br />

the following properties are true for any angle . Answer true or false for each statement.<br />

a) sin (180 ) = sin , b) cos (180 ) = cos , c) tan (180 ) = tan ,<br />

d) sin (180 + ) = sin , e) cos (180 + ) = cos , f) tan (180 + ) = tan ,<br />

g) sin (360 ) = sin , h) cos (360 ) = cos , i) tan (360 ) = tan ,<br />

j) sin (90 + ) = sin (90 ), k) cos (90 + ) = cos (90 ), l) tan ( ) = tan .<br />

ii) For each of the false properties in i), adjust the statement to give a true property; e.g. re-write b) to<br />

give: cos (180 ) = cos .<br />

3) Using your calculator and a sketch of the appropriate graph, find all values of x, where 0 x 360 , such<br />

that:<br />

a) sin x = 0 7 , b) sin x = 0 25 , c) sin x = 0<br />

4 ,<br />

d) cos x = 0 7 , e) cos x = 0 25 , f) cos x = 0<br />

4 ,<br />

g) tan x = 0 7 , h) tan x = 2 5 , i) tan x = 0<br />

4 .<br />

4) Find the 2 values of x between 0 o and 360 o satisfying sin x = 1 2 .<br />

Deduce that x = 15 o is one solution to the equation sin(2x) = 1 2 and find the other solution which is less<br />

than 180 o .<br />

5) Sketch the graph of y = sin x for x between 0 o and 360 o . {Include the x-coordinates x = 0, 90, 180, 270<br />

and 360.}<br />

On the same diagram, sketch the graph of y = sin (x + 90) for x between 0 o and 360 o .<br />

Describe the transformation which maps the graph of y = sin x onto the graph of y = sin (x + 90).<br />

6) Sketch the graph of y = cos x for x between 0 o and 360 o . {Include the x-coordinates x = 0, 90, 180, 270<br />

and 360.}<br />

On the same diagram, sketch the graph of y = cos (x 30) for x between 0 o and 360 o .<br />

Describe the transformation which maps the graph of y = cos x onto the graph of y = cos (x 30).<br />

7) Sketch the graph of y = tan x for x between 0 o and 360 o . {Include the x-coordinates x = 0, 90, 180, 270<br />

and 360.}<br />

On the same diagram, sketch the graph of y = tan (x + 60) for x between 0 o and 360 o .<br />

Describe the transformation which maps the graph of y = tan x onto the graph of y = tan (x + 60).<br />

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8) Sketch, on the same axes, the graphs of y = cos x and y = cos 3x for x between 0 and 360. Mark clearly<br />

the points where the graphs cross the axes.<br />

State the period of the function y = cos 3x.<br />

x<br />

9) Sketch, on the same axes, the graphs of y = sin x and y = sin ( )<br />

2<br />

the points where the graphs cross the axes.<br />

x<br />

State the period of the function y = sin ( ).<br />

2<br />

for x between 0 and 720. Sketch clearly<br />

10) By considering the graph of y = tan x, or otherwise, express the following in terms of tan x.<br />

a) tan (180 + x), b) tan (180 x), c) tan (360 x).<br />

11) The trigonometric function y = sin 2x has a period of 180.<br />

Find the value of the constant k such that the function y = sin kx has a period of 90.<br />

12) Find the value of the constant k such that the function y = tan kx has a period of 90.<br />

13) Find the value of the constant k such that the function y = cos kx has a period of 45.<br />

14) Due to tidal forces, the depth, D metres, of water in a harbour is given by D = 8 + 6sin 30t, where t is<br />

time in hours after midnight.<br />

i) State the maximum and minimum depths of water in the harbour at any time.<br />

ii) How many hours elapse between instances when the water in the harbour is at its maximum<br />

depth?<br />

iii) What is the earliest time after midnight that the depth of water in the harbour is 12 metres? Give<br />

your answer to the nearest minute. {Take care when converting hours to minutes!}<br />

15) The formula P = 250 125cos 9t is used to model the number of birds in a certain remote colony<br />

during the course of a year. P represents the number of birds, t represents time in weeks since the<br />

beginning of the year.<br />

i) State the period of this function.<br />

ii) Find the greatest number of birds predicted by this model and the smallest corresponding value<br />

of t.<br />

iii) What is the earliest time, from the beginning of the year, when there are 300 birds in the colony?<br />

16) Due to tidal forces, the depth, D metres, of water in a harbour is given by D = 10 + 5cos 30t, where t is<br />

time in hours after midnight.<br />

i) State the maximum and minimum depths of water in the harbour at any time.<br />

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ii) How many hours elapse between instances when the water in the harbour is at its maximum<br />

depth?<br />

iii) What is the earliest time after midnight that the depth of water in the harbour is 12 metres? Give<br />

your answer to the nearest minute. {Take care when converting hours to minutes!}<br />

17) The depth, D metres, of water in a harbour is given by D = a + bcos 30t, where t is time in hours after<br />

midnight.<br />

Find the values of a and b such that the maximum depth is 12 metres and the minimum depth is 8<br />

metres.<br />

18) Find the areas of the following triangles.<br />

12 m<br />

a) b)<br />

102 <br />

8 cm<br />

7 m<br />

52 <br />

10 cm<br />

c)<br />

7 m<br />

d)<br />

4 m<br />

D<br />

12 cm<br />

30 <br />

E<br />

8 cm<br />

9 m<br />

F<br />

19) Find the area of the following triangle.<br />

40 60 <br />

80 m<br />

20) An equilateral triangle has area 25 cm 2 , find the length of a side.<br />

10 cm<br />

21) BCDEF is a regular hexagon of side 10 cm. Find its’ area.<br />

A<br />

B<br />

{Hint: from the centre of the hexagon, construct 6<br />

identical, equilateral triangles !}<br />

F<br />

10 cm<br />

C<br />

22) Find the area of a regular pentagon of side 10 cm.<br />

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E<br />

D


23) Without using a calculator, write down the exact values of the following trigonometric ratios.<br />

a) sin 135 o , b) cos 240 o , c) tan 330 o , d) cos 120 o ,<br />

e) tan 45 o , f) sin 300 o , g) sin 300 o , h) cos 150 o .<br />

24) Solve, without using a calculator, the following equations for x between 0 o and 360 o .<br />

a) cos x = 21<br />

, b) tan x = 3 , c) sin x = 1<br />

2<br />

, d) tan x = 1<br />

3<br />

,<br />

e) sin x = 21<br />

, f) cos x = 21<br />

, g) tan x = 1, h) sin x = 3 2<br />

.<br />

25) Find all 4 solutions of the equation 3tan x + 1 = 0 for 360 o x 360 o .<br />

26) Given that sin A is negative and that cos A is positive, state, with a reason, whether the angle A is acute,<br />

obtuse or reflex. {Hint graphs!}<br />

27) Given that sin135<br />

0<br />

1<br />

= , find, without a calculator, the value of cos 135 o .<br />

2<br />

28) Given that A is the obtuse angle such that sin A = 1 , find the values of cos A and tan A, expressing your<br />

3<br />

answers in surd form.<br />

29) Given that A is acute and that tan A = 3 , find the values of<br />

4<br />

i) sin A, ii) cos A.<br />

{Hint: consider the right angled triangle }<br />

3<br />

A<br />

4<br />

30) Given that A is not a reflex angle and that cos A = 13<br />

5 . Find the value of tan A, giving your answer as<br />

an exact fraction. {Hint: find sin A first.}<br />

31) For each of the following equations, find the principal and secondary solutions and hence find all<br />

solutions between 0 o and 360 o .<br />

a) sin x = 0 7 , b) sin x = 0 25 , c) sin x = 0<br />

4 ,<br />

d) cos x = 0 7 , e) cos x = 0 25 , f) cos x = 0<br />

4 ,<br />

g) tan x = 0 7 , h) tan x = 2 5 , i) tan x = 0<br />

4 .<br />

0 0<br />

32) Find all values of such that 180 180 , where:<br />

a) 13sin = 5,<br />

b) 5 tan = 2,<br />

c) sec = 2 .<br />

{Hint for c) rearrange to get cos = ......... etc.}<br />

33) Solve the equation 2cos x = 3 for 180 o x 180 o .<br />

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34) Solve the equation tan x = 2 for 0 x 360 o .<br />

35) Solve the following equations for x between 0 o and 360 o .<br />

1<br />

a) 5sin 2x = 4, b) 13cos 2x = 5, c) 9tan 2x = 7, d) 10 cos x = 7,<br />

1<br />

1<br />

e) 8sin x = 1,<br />

f) 8tan x = 15,<br />

g) 25cos 3x = 7, h) 7tan x = 24.<br />

2<br />

2<br />

2<br />

1<br />

3<br />

36) Solve the following equations for x between 0 o and 180 o .<br />

1<br />

a) 3 + 5sin 2x = 6, b) 11 + 7cos x = 8.<br />

37) Solve the equation ( 10 )<br />

0<br />

1<br />

0 0<br />

cos + = for 180 180 .<br />

2<br />

+ 10 0 with y etc.}<br />

{Hint replace ( )<br />

2<br />

38) Solve the following equations for x between 0 o and 360 o .<br />

a) sin x = cos x, b) 3sin x + 4cos x = 0,<br />

c) sin x 2 cos x = 0.<br />

1<br />

39) Solve the equation cos 2 = , for 0 360 0 .<br />

4<br />

2<br />

40) Solve the equation 4sin 1= 0 , for 0 360 0 .<br />

41) Solve the following equations for x between 0 o and 360 o .<br />

2<br />

a) 3cos<br />

x cos x 2 = 0, b) tan 2 x tan x 6 = 0, c) tan 2 x 2tan x = 1.<br />

42) Solve the equation sin 2 3cos 2 = 0, for between 0 o and 360 o .<br />

{Hint: divide by cos 2 to put the equation in terms of tan 2 etc.}<br />

2 2<br />

43) Factorise, and hence solve the equation cos sin = 0, for 0 360 0 .<br />

Miscellaneous questions.<br />

44) Solve the following equations for x between 0 o and 360 o .<br />

2<br />

a) 3 sin x 2 cos x 2 = 0, b) 15cos 2 x = 13 + sin x, c) 10sin 2 x 5cos 2 x + 2 = 4sin x,<br />

d) sin x = tan x, e) 5sin (2x) = cos (2x).<br />

45) Find all values of such that 180 o < < 180 o and 2tan 3 =<br />

2 .<br />

tan<br />

46) Find all values of , for 0 0 360<br />

0 , which satisfy the equation 3sin<br />

2 cos<br />

2 = 2.<br />

2<br />

47) Use the quadratic formula to solve the equation 3z<br />

5z<br />

1 = 0, giving your answers to 4 decimal<br />

places.<br />

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2<br />

Hence show that the solutions to 3sin<br />

5sin<br />

1 = 0 are given by sin = 01805 and thus<br />

solve this equation for between 0 o and 360 o .<br />

48) Given that A is the obtuse angle such that sin A = 5 , find the value of cos A as an exact fraction.<br />

13<br />

49) The diagram shows four points A, B, C, D on horizontal ground,<br />

with AB = 500 m, AD = 600 m, CD = 250 m, angle CAB = 54 o and angle ABC = 75 o .<br />

Calculate the length of AC, giving your answer correct to the nearest metre.<br />

Hence show that angle ADC = 83 o correct to the nearest degree.<br />

600 m<br />

D<br />

250 m<br />

C<br />

{Hint: SINe & COSine rules!}<br />

A<br />

54 o<br />

500 m 75 o B<br />

50) In triangle ABC, angle A = 42 o , AB = 6 cm and BC = 45<br />

cm. Calculate the 2 possible values of angle C.<br />

51) It is given that 0 o < < 360 o . State the two values of for which tan has the same value tan( 30 o ) .<br />

52) The diagram shows a triangle ABC in which angle C = 30 o , BC = x cm and AC = (x + 2) cm.<br />

Given that the area of triangle ABC is 12 cm 2 ,<br />

calculate the value of x.<br />

B<br />

x cm<br />

A<br />

(x +2) cm<br />

30 o C<br />

53) Solve the equation 2sin 2 (2x) + sin (2x) 1 = 0 for x between 0 and 360. {Hint: factorise!}<br />

54) Sketch the graph of y = cos x o , for values of x from 0 to 360.<br />

Sketch, on the same diagram, the graph of y = cos (x 90) o .<br />

Use your diagram to solve the equation cos x o = cos (x 90) o for values of x between 0 and 360.<br />

Indicate clearly on your diagram how the solutions relate to the graphs.<br />

State how many values of x satisfying the equation cos (8x) o = cos (8x 90) o lie between 0<br />

and 360.<br />

(You should explain your reasoning briefly, but no further detailed working or sketching is necessary.)<br />

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55) Sketch the graph of y = sin x o , for values of x from 0 to 360.<br />

Sketch, on the same diagram, the graph of y = sin (x + 90) o .<br />

Use your diagram to solve the equation sin x o = sin (x + 90) o for values of x between 0 and 360.<br />

Indicate clearly on your diagram how the solutions relate to the graphs.<br />

State how many values of x satisfying the equation sin (12x) o = sin (12x + 90) o lie between 0<br />

and 360.<br />

(You should explain your reasoning briefly, but no further detailed working or sketching is necessary.)<br />

56) Given that sin = 5<br />

3 , and that angle is obtuse, find, without using a calculator, the exact values of<br />

cos and tan .<br />

57) Due to tidal forces, the depth, D metres, of water in a harbour is given by D = 4 + 3cos 30t, where t is<br />

time in hours after midnight.<br />

i) State the maximum and minimum depths of water in the harbour at any time.<br />

ii) How many hours elapse between instances when the water in the harbour is at its maximum<br />

depth?<br />

iii) What is the earliest time after midnight that the depth of water in the harbour is 3 metres? Give<br />

your answer to the nearest minute. {Take care when converting hours to minutes!}<br />

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ANSWERS<br />

1) x = 60 , 300 , 60 , 300 .<br />

2) i) a) true, b) false, c) false, d) false, e) false, f) true, g) false, h) true, i) false, j) true, k) false, l) true.<br />

ii) {Each false property simply requires a ‘minus’ symbol on the right-hand side!}<br />

3) a) x = 444 , 1356 , b) x = 145 , 1655 , c) x = 3364 , 2036 , d) x = 456 , 3144 , e) x = 755 ,<br />

2845 , f) x = 1136 , 2464 , g) x = 35 , 215 , h) x = 682 , 2482 , i) x = 3382 , 1582 .<br />

4) x = 30 or 150 .<br />

x = 75 .<br />

5) A translation along the negative x-axis of 90 units.<br />

6) A translation along the positive x-axis of 30 units.<br />

7) A translation along the negative x-axis of 60 units.<br />

8) 120 units.<br />

9) 720 units.<br />

10) a) tan x, b) tan x, c) tan x.<br />

11) k = 4.<br />

12) k = 2.<br />

13) k = 8.<br />

14) i) Maximum = 14 metres, minimum = 2 metres, ii) 12 hours, iii) 1:24 a.m.<br />

15) i) 40 weeks, ii) 375 birds when t = 30, iii) t = 12.61979761 weeks OR approximately 12 weeks 4 days.<br />

16) i) Maximum = 15 metres, minimum = 5 metres, ii) 12 hours, iii) 1:33 a.m.<br />

17) a = 10, b = 2.<br />

18) a) 315 cm 2 , b) 411 m 2 , c) 134 m 2 , d) 471 cm 2 .<br />

19) 18083 m 2 .<br />

20) 76 cm.<br />

21) 2598 cm 2 .<br />

22) 1720 cm 2 .<br />

23) a) 1<br />

, b) <br />

2 21<br />

, c) 1<br />

3<br />

, d) 21<br />

, e) 1, f) 3 2<br />

, g) 3 2<br />

, h) 3 2<br />

.<br />

24) a) x = 60 o or 300 o , b) x = 60 o or 240 o , c) x = 45 o or 135 o , d) x = 30 o or 210 o , e) x = 210 o or 330 o ,<br />

f) x = 120 o or 240 o , g) x = 135 o or 315 o , h) x = 240 o or 300 o .<br />

25) x = 210 o or 30 o or 150 o or 330 o .<br />

26) Reflex.<br />

27) 1 2 .<br />

28) cos A = 8<br />

3<br />

2 2<br />

{which equals <br />

3 }, tan A = 1 .<br />

8<br />

29) i) 3 5 , ii) 4 5 .<br />

12<br />

30) . 5<br />

31) a) x = 44 4 0 or x = 135 6 0 , b) x = 14 5 0 or x = 165 5 0 , c) x = 203 6 0 or x = 336 4 0 ,<br />

d) x = 45 6 0 or x = 314 4 0 , e) x = 755 0 or x = 284 5 0 , f) x = 113 6 0 or x = 246 4 0 ,<br />

g) x = 35 0 or x = 215 0 , h) x = 68 2 0 or x = 248 2 0 , i) x = 158 2 0 or x = 338 2 0 .<br />

32) a) =<br />

0<br />

22 6 or = 1574 <br />

, b) =<br />

0<br />

21 8 or = 1582<br />

, c) = 60 0 or = 60<br />

.<br />

33) x = 30 o or 30 o .<br />

34) x = 63.4 o or 243.4 o .<br />

0 0 0 0<br />

0 0 0 0<br />

35) a) x = 266 , 634 , 2066 , 2434<br />

, b) x = 337 , 1463 , 2137 , 3263<br />

,<br />

0<br />

c) x = 189 ,<br />

0<br />

1089 ,<br />

0<br />

1989 ,<br />

0<br />

2889<br />

, d) x = 268 9 0 , e) No solutions, f) x = 236 1 0 ,<br />

g) x = 246 , 95 4 0 , 144 6 0 , 215 4 0 , 264 6 0 , 335 4<br />

0 , h) x = 318 8 0 .<br />

36) a) x = 184 , 716<br />

, b) No solutions between 0 o and 180 o .<br />

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0 0<br />

37) x = 130 , 110 .<br />

38) a) x = 45 o , 225 o , b) x = 1269 0 , 3069<br />

0 , c) x = 634 0 , 2434<br />

0 .<br />

0 0 0 0<br />

39) = 60 , 120 , 240 , 300 .<br />

0 0 0 0<br />

40) = 30 , 150 , 210 , 330 .<br />

41) a) x = 0 0 , 360 0 , 1318<br />

0 , 228 2<br />

0<br />

0 0 0 0<br />

, b) x = 71 6 , 1166 , 2516<br />

, 2966<br />

,<br />

c) x = 67.5 o , 157.5 o , 247.5 o , 337.5 o .<br />

42) x = 30 o , 120 o , 210 o , 300 o .<br />

0 0 0 0<br />

43) = 45 , 225 , 135 , 315 .<br />

44) a) x = 705 0 , 180 0 , 289 5<br />

0 , b) x = 19.5 o , 160.5 o , 203.6 o , 336.4 o , c) x = 36.9 o , 143.1 o , 199.5 o , 340.5,<br />

d) x = 0, 180 o , 360 o , e) x = 5.7 o , 95.7 o , 185.7 o , 275.7 o .<br />

45) = 116.6 o , 26.6 o , 63.4 o , 153.4 o .<br />

46) = 60 o , 120 o , 240 o , 300 o .<br />

0 0<br />

47) z = 18471 or 01805. = 1904 , 3496<br />

.<br />

48) 12<br />

13 .<br />

49) AC = 621 to the nearest metre.<br />

50) C = 631 0 or 1169 0 .<br />

51) = 150 0 or 330 0 .<br />

52) x = 6.<br />

53) x = 15 o , 75 o , 135 o , 195 o , 255 o , 315 o .<br />

54) x = 45 o or x = 225 o .<br />

55) x = 45 o or x = 225 o .<br />

56) cos = 5<br />

4 , tan = 4<br />

3 .<br />

57) i) Maximum = 7 metres, minimum = 1 metre, ii) 12 hours, iii) 3:39 a.m.<br />

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