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Simple analytical models of glacier-climate interactions - by Prof. J ...

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Problem ice-sheet pr<strong>of</strong>ile (P 2)<br />

For the steady-state radial velocity we now have:<br />

d (r H U r ) = b R r2<br />

R<br />

d r → U r =<br />

b R<br />

3 R H-1 r 2 (P 2.1)<br />

This can be combined again with the expression for the vertical mean ice velcocity in the<br />

case <strong>of</strong> simple shearing flow:<br />

U r = - A* H n+1 d H<br />

d r<br />

n<br />

(P 2.2)<br />

We get<br />

1+2/n<br />

H<br />

dH<br />

dr<br />

= -<br />

1/n<br />

b R<br />

3 R A*<br />

r 2/n (P 2.3)<br />

Integration with respect to r yields<br />

n<br />

2n+2 H 2+2/n - H 0<br />

2+2/n = - n<br />

n+2<br />

1/n<br />

b R<br />

3 R A*<br />

r 1+2/n , (P 2.4)<br />

or<br />

H 2+2/n - H 0<br />

2+2/n = - 2n+2<br />

n+2<br />

1/n<br />

b R<br />

3 R A*<br />

r 1+2/n . (P 2.5)<br />

Next we have to apply a boundary condition, namely H = 0 at r = R. This leads to a<br />

relation between the ice thickness in the centre and the ice-sheet radius:<br />

H 0<br />

2+2/n = 2n+2<br />

n+2<br />

1/n<br />

b R<br />

3 R A*<br />

R 1+2/n . (P 2.6)<br />

The final solution then becomes<br />

H(r) = 2n+2<br />

n+2<br />

n/(2n+2)<br />

b R /(3 R A*) 1/(2n+2) R 1+2/n - r 1+2/n n/(2n+2) . (P 2.7)<br />

For n=3 we have:<br />

29

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