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Simple analytical models of glacier-climate interactions - by Prof. J ...

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6. Including feedback between <strong>glacier</strong> length and ice thickness<br />

In the analysis <strong>of</strong> section 3 we made thickness a function <strong>of</strong> the bed slope, but not <strong>of</strong> the<br />

<strong>glacier</strong> length. This is an obvious shortcoming. A more advanced analysis can be made<br />

<strong>by</strong> using the relation:<br />

H m =<br />

1/2<br />

µ L<br />

, (6.1)<br />

1+ ν s<br />

where µ and ν are positive constants. Actually, eq. (6.1) fits rather well results form a<br />

numerical <strong>glacier</strong> model in which s and L are systematically varied (Oerlemans, 2001).<br />

Note that for s = 0 eq. (6.1) reduces to the relation between ice thickness and <strong>glacier</strong>s<br />

length for a perfectly plastic ice sheet on a flat bed (section 2). In the simple model, the<br />

expression for L was:<br />

L = 2 (H m + b 0 - E)<br />

s<br />

. (6.2)<br />

By substituting eq. (6.1) we obtain (E ' = E -b 0 ):<br />

L = 2 s<br />

1/2<br />

µ L<br />

- E ' . (6.3)<br />

1 + ν s<br />

This quadratic equation is most conveniently solved <strong>by</strong> setting N = L 1/2 . We then have<br />

N 2 -<br />

2 µ 1/2<br />

s (1 + ν s) 1/2<br />

N + 2 E '<br />

s<br />

= 0 . (6.4)<br />

The determinant is<br />

Det =<br />

4 µ<br />

s 2 (1 + ν s)<br />

- 8 E '<br />

s<br />

. (6.5)<br />

Real solutions exist only when Det ≥ 0. The first term is always positive. Therefore a real<br />

solution exists even for small positive values <strong>of</strong> E ', that is, when the equilibrium line is<br />

higher than the highest part <strong>of</strong> the bed at x = 0, but below the <strong>glacier</strong> surface. This<br />

nonlinearity, <strong>of</strong> course, reflects the HMB-feedback. The solution for L reads<br />

L =<br />

µ 1/2<br />

s (1 + ν s) 1/2 ± µ<br />

s 2 (1 + ν s)<br />

- 2 E '<br />

s<br />

1/2<br />

2<br />

. (6.6)<br />

20

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