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Chapter 9 Radical Functions

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Homework 9.3<br />

SSM: Intermediate Algebra<br />

73. a. ( )<br />

( )<br />

2 100 200<br />

f 100 = = ≈ 2.49<br />

32.2 32.2<br />

It takes roughly 2.49 seconds for an object<br />

to fall 100 feet.<br />

b. ( )<br />

( )<br />

2 1483 2966<br />

f 1483 = = ≈ 9.6<br />

32.2 32.2<br />

The parachutist was in freefall for roughly<br />

9.6 seconds. This is an underestimate<br />

because the chute would slow down his<br />

descent.<br />

c. f is an increasing function. This makes sense<br />

because the higher an object is, the longer it<br />

should take to fall to the ground.<br />

b.<br />

c.<br />

d.<br />

k<br />

n<br />

1/ k 1/ n<br />

x x = x ⋅ x<br />

3 4<br />

= x<br />

= x<br />

= x<br />

=<br />

1 1<br />

+<br />

k n<br />

n k<br />

+<br />

n⋅k<br />

n⋅k<br />

n+<br />

k<br />

n⋅k<br />

n⋅ k n+<br />

k<br />

x<br />

x x → k = 3, n = 4<br />

3⋅ 4 3+<br />

4 12 7<br />

3 4<br />

x x = x = x<br />

The results are the same.<br />

5⋅ 7 5+<br />

7 35 12<br />

x x = x = x<br />

5 7<br />

75.<br />

3<br />

1/ 2<br />

1 1 3 2 1<br />

− −<br />

2 3 6 6 6 6<br />

x x x x<br />

x x<br />

= = = = =<br />

1/ 3<br />

x x<br />

77. Begin by letting the two expressions be denoted<br />

by W and Y. We know the following from the<br />

problem statement:<br />

79. a.<br />

W + Y = 9 x + 7<br />

W − Y = x + 3<br />

Adding the two equations together will eliminate<br />

the Y terms and yield:<br />

2W = 9 x + 7 + x + 3<br />

2W<br />

= 10 x + 10<br />

W = 5 x + 5<br />

Plug this into one of the original equations:<br />

5 x + 5 + Y = 9 x + 7<br />

Y = 9 x + 7 − 5 x − 5<br />

Y = 4 x + 2<br />

Thus, the two expressions are 5 x + 5 and<br />

4 x + 2 .<br />

3 4<br />

1/ 3 1/ 4<br />

x x = x ⋅ x<br />

= x<br />

= x<br />

= x<br />

=<br />

1 1<br />

+<br />

3 4<br />

4 3<br />

+<br />

12 12<br />

7 /12<br />

12 7<br />

x<br />

81. Answers will vary. See Key Points.<br />

Homework 9.3<br />

1.<br />

3.<br />

5.<br />

2 2 3<br />

= ⋅<br />

3 3 3<br />

=<br />

=<br />

2 3<br />

( 3) 2<br />

2 3<br />

3<br />

8 8 x<br />

= ⋅<br />

x x x<br />

=<br />

8<br />

x<br />

( x ) 2<br />

8 x<br />

=<br />

x<br />

3 3 5x<br />

= ⋅<br />

5x 5x 5x<br />

=<br />

3 5x<br />

( 5x<br />

) 2<br />

3 5x<br />

=<br />

5x<br />

280

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