Chapter 9 Radical Functions
Chapter 9 Radical Functions
Chapter 9 Radical Functions
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Homework 9.3<br />
SSM: Intermediate Algebra<br />
73. a. ( )<br />
( )<br />
2 100 200<br />
f 100 = = ≈ 2.49<br />
32.2 32.2<br />
It takes roughly 2.49 seconds for an object<br />
to fall 100 feet.<br />
b. ( )<br />
( )<br />
2 1483 2966<br />
f 1483 = = ≈ 9.6<br />
32.2 32.2<br />
The parachutist was in freefall for roughly<br />
9.6 seconds. This is an underestimate<br />
because the chute would slow down his<br />
descent.<br />
c. f is an increasing function. This makes sense<br />
because the higher an object is, the longer it<br />
should take to fall to the ground.<br />
b.<br />
c.<br />
d.<br />
k<br />
n<br />
1/ k 1/ n<br />
x x = x ⋅ x<br />
3 4<br />
= x<br />
= x<br />
= x<br />
=<br />
1 1<br />
+<br />
k n<br />
n k<br />
+<br />
n⋅k<br />
n⋅k<br />
n+<br />
k<br />
n⋅k<br />
n⋅ k n+<br />
k<br />
x<br />
x x → k = 3, n = 4<br />
3⋅ 4 3+<br />
4 12 7<br />
3 4<br />
x x = x = x<br />
The results are the same.<br />
5⋅ 7 5+<br />
7 35 12<br />
x x = x = x<br />
5 7<br />
75.<br />
3<br />
1/ 2<br />
1 1 3 2 1<br />
− −<br />
2 3 6 6 6 6<br />
x x x x<br />
x x<br />
= = = = =<br />
1/ 3<br />
x x<br />
77. Begin by letting the two expressions be denoted<br />
by W and Y. We know the following from the<br />
problem statement:<br />
79. a.<br />
W + Y = 9 x + 7<br />
W − Y = x + 3<br />
Adding the two equations together will eliminate<br />
the Y terms and yield:<br />
2W = 9 x + 7 + x + 3<br />
2W<br />
= 10 x + 10<br />
W = 5 x + 5<br />
Plug this into one of the original equations:<br />
5 x + 5 + Y = 9 x + 7<br />
Y = 9 x + 7 − 5 x − 5<br />
Y = 4 x + 2<br />
Thus, the two expressions are 5 x + 5 and<br />
4 x + 2 .<br />
3 4<br />
1/ 3 1/ 4<br />
x x = x ⋅ x<br />
= x<br />
= x<br />
= x<br />
=<br />
1 1<br />
+<br />
3 4<br />
4 3<br />
+<br />
12 12<br />
7 /12<br />
12 7<br />
x<br />
81. Answers will vary. See Key Points.<br />
Homework 9.3<br />
1.<br />
3.<br />
5.<br />
2 2 3<br />
= ⋅<br />
3 3 3<br />
=<br />
=<br />
2 3<br />
( 3) 2<br />
2 3<br />
3<br />
8 8 x<br />
= ⋅<br />
x x x<br />
=<br />
8<br />
x<br />
( x ) 2<br />
8 x<br />
=<br />
x<br />
3 3 5x<br />
= ⋅<br />
5x 5x 5x<br />
=<br />
3 5x<br />
( 5x<br />
) 2<br />
3 5x<br />
=<br />
5x<br />
280