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Chapter 9 Radical Functions

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Homework 9.5<br />

SSM: Intermediate Algebra<br />

31.<br />

2 + x = x + 12<br />

( 2 + x ) = ( x + 12)<br />

2 2<br />

4 + 4 x + x = x + 12<br />

35.<br />

x −<br />

2x<br />

= −1<br />

2x<br />

= x + 1<br />

( 2x<br />

) = ( x + 1)<br />

2 2<br />

4 x = 8<br />

2x = x + 2 x + 1<br />

33.<br />

( x )<br />

x = 2<br />

2<br />

2<br />

= 2<br />

x = 4<br />

Check x = 4<br />

?<br />

( ) ( )<br />

2 + 4 = 4 + 12<br />

4 = 4 true<br />

The solution is 4.<br />

x − 1 = 5 − x<br />

( x − 1) = ( 5 − x )<br />

2 2<br />

x − 2 x + 1 = 5 − x<br />

2<br />

2<br />

2x<br />

− 4 = 2<br />

x − 2 =<br />

x<br />

2<br />

( x − 2) = ( x )<br />

x − 4x + 4 = x<br />

x<br />

− 5x<br />

+ 4 = 0<br />

( x )( x )<br />

− 4 − 1 = 0<br />

x<br />

x − 4 = 0 or x − 1 = 0<br />

x = 4 or x = 1<br />

Check x = 4<br />

?<br />

( 4) − 1=<br />

5 − ( 4)<br />

1 = 1 true<br />

Check x = 1<br />

?<br />

( 1) − 1=<br />

5 − ( 1)<br />

0 = 2 false<br />

The solution is 4.<br />

?<br />

2<br />

37.<br />

2<br />

2<br />

x − 1 = 2<br />

( x − 1) 2<br />

= ( 2 x ) 2<br />

x − 2x + 1 = 4x<br />

x<br />

− 6x<br />

+ 1 = 0<br />

x<br />

2<br />

( 6) ( 6) 4( 1)( 1)<br />

2( 1)<br />

− − ± − −<br />

x =<br />

=<br />

6 ± 32<br />

2<br />

= 3 ± 2 2<br />

Check 3+ 2 2 ( x ≈ 5.83)<br />

( ) ( ) ?<br />

5.83 − 2 5.83 =−1<br />

?<br />

− 1.00 =−1 true<br />

Check 3 − 2 2 ( x ≈ 0.172)<br />

( ) ( ) ?<br />

0.172 − 2 0.172 =−1<br />

?<br />

− 0.172=−1 false<br />

The solution is 3 + 2 2 .<br />

x + 1 = − x −7<br />

( x + 1) = ( − x −7)<br />

2 2<br />

x + 1 = x + 14 x + 49<br />

14 x = −48<br />

7 x − 24<br />

( 7 x ) = ( −24)<br />

2 2<br />

49x<br />

= 576<br />

576<br />

x =<br />

49<br />

576<br />

x = x ≈ 11.76<br />

49<br />

Check ( )<br />

?<br />

( ) ( )<br />

11.76 + 1 =− 11.76 − 7<br />

?<br />

3.57 =−10.43 false<br />

There are no real solutions.<br />

292

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