On some properties of a differential operator on the polydisk
On some properties of a differential operator on the polydisk
On some properties of a differential operator on the polydisk
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PROPERTIES OF DIFFERENTIAL OPERATOR ON THE POLYDISK 75<br />
Theorem 2.7. Let 0 < p < ∞, α > −1, s ∈ N, f ∈ H(U n ). If γ > α+2 − 1 for<br />
p<br />
p ≤ 1 and γ > α+1 + 1 (1 − 1 ) for p > 1, v = sp + αn − γpn + n − 1, <strong>the</strong>n<br />
p n p<br />
∫<br />
|D γ f(z)| p (1 − |z| 2 ) α dm 2n (z)<br />
U<br />
∫ n 1 ∫<br />
≤ C |R s f(w)| p (1 − |w| 2 ) v dm n (ξ)d|w| ,<br />
0 T n<br />
where w = |w|ξ.<br />
Pro<str<strong>on</strong>g>of</str<strong>on</strong>g>. Let f ∈ H(U n ), p ≤ 1. Then (see [14])<br />
M 1 (f, τ 2 ) ≤ C(1 − τ) n(1−1/p) M p (f, τ), τ ∈ (0, 1). (2.6)<br />
Using (2.6) and <strong>the</strong> fact that M p (f, r) is increasing as a functi<strong>on</strong> <str<strong>on</strong>g>of</str<strong>on</strong>g> r (see [5]) we<br />
easily get<br />
( ∫ 1<br />
) p<br />
|f(w)|(1 − |w|)<br />
∫T t dm n (ξ)d|w|<br />
n<br />
≤ C<br />
0<br />
∫ 1 ∫T n<br />
0<br />
|f(w)| p (1 − |w|) tp+(n+1)(p−1) dm n (ξ)d|w|, (2.7)<br />
where t > n(1−p) − 1, f ∈ H(U n ), p ≤ 1. By <strong>the</strong> Cauchy formula,<br />
p<br />
∫<br />
∣ |D γ f ρ (z 1 , · · · , z n )| p ≤ C<br />
f ρ (ξ 1 , · · · , ξ n )dm n (ξ) ∣∣∣<br />
p<br />
∣<br />
, ρ ∈ (0, 1).<br />
T n (1 − ξz) γ+1<br />
Using (1.2) or (2.4), (2.5) for large s and (2.7) we obtain<br />
∫<br />
∣ f ρ (ξ 1 , · · · , ξ n )dm n (ξ) ∣∣∣<br />
p<br />
∣ ∏ n<br />
T n k=1 (1 − ξ kz k ) γ+1<br />
( ∫ 1 ∫<br />
)<br />
|R s f ρ (w)|(1 − |w|) s−1 p<br />
dm n (ξ)d|w|<br />
≤ C<br />
0 T |1 − wz| n γ+1<br />
∫ 1<br />
|R<br />
≤ C<br />
∫T s f ρ (w)| p (1 − |w|) (s−1)p (1 − |w|) (n+1)(p−1)<br />
dm<br />
|1 − wz| n (γ+1)p n (ξ)d|w|. (2.8)<br />
0<br />
Therefore, from (2.6)-(2.8) and using Fubini’s <strong>the</strong>orem we have<br />
∫<br />
|D γ f ρ (z)| p (1 − |z| 2 ) α dm 2n (z)<br />
U n ∫ 1 ∫<br />
|R<br />
≤ C<br />
∫U s f ρ (w)| p (1 − |w|) sp+n(p−1)−1 dm n (ξ)d|w|<br />
(1 − |z| 2 ) α dm n 0 T |1 − wz| n (γ+1)p 2n (z)<br />
∫ 1 ∫<br />
(1 − |z|<br />
≤ C<br />
0<br />
∫T 2 ) α dm 2n (z)<br />
|R s f n U |1 − wz| n (γ+1)p ρ (w)| p (1 − |w|) sp+n(p−1)−1 dm n (ξ)d|w|.<br />
Using <strong>the</strong> following estimate<br />
∫<br />
(1 − |z|) t dm 2n (z)<br />
∏ n<br />
k=1 |1 − z kw k | ≤ C<br />
∏ t 1 n<br />
k=1 (1 − |w k|) , t > −1, t t 1 > t + 2,<br />
1−t−2<br />
U n