Linear Algebra Exercises-n-Answers.pdf
Linear Algebra Exercises-n-Answers.pdf
Linear Algebra Exercises-n-Answers.pdf
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152 <strong>Linear</strong> <strong>Algebra</strong>, by Hefferon<br />
> 0,0,0,.5,0,0;<br />
> 0,0,0,0,.5,1];<br />
octave:2> B100=B**100<br />
B100 =<br />
1.00000 0.80000 0.60000 0.40000 0.20000 0.00000<br />
0.00000 0.00000 0.00000 0.00000 0.00000 0.00000<br />
0.00000 0.00000 0.00000 0.00000 0.00000 0.00000<br />
0.00000 0.00000 0.00000 0.00000 0.00000 0.00000<br />
0.00000 0.00000 0.00000 0.00000 0.00000 0.00000<br />
0.00000 0.20000 0.40000 0.60000 0.80000 1.00000<br />
octave:3> B100*[0;1;0;0;0;0]<br />
octave:4> B100*[0;1;0;0;0;0]<br />
octave:5> B100*[0;0;0;1;0;0]<br />
octave:6> B100*[0;1;0;0;0;0]<br />
yields these outputs.<br />
2 (a) From these equations<br />
starting with: $1 $2 $3 $4<br />
s 0 (100)<br />
s 1 (100)<br />
s 2 (100)<br />
s 3 (100)<br />
s 4 (100)<br />
s 5 (100)<br />
0.80000<br />
0.00000<br />
0.00000<br />
0.00000<br />
0.00000<br />
0.20000<br />
0.60000<br />
0.00000<br />
0.00000<br />
0.00000<br />
0.00000<br />
0.40000<br />
0.40000<br />
0.00000<br />
0.00000<br />
0.00000<br />
0.00000<br />
0.60000<br />
0.20000<br />
0.00000<br />
0.00000<br />
0.00000<br />
0.00000<br />
0.80000<br />
(1/6)s 1 (n) + 0s 2 (n) + 0s 3 (n) + 0s 4 (n) + 0s 5 (n) + 0s 6 (n) = s 1 (n + 1)<br />
(1/6)s 1 (n) + (2/6)s 2 (n) + 0s 3 (n) + 0s 4 (n) + 0s 5 (n) + 0s 6 (n) = s 2 (n + 1)<br />
(1/6)s 1 (n) + (1/6)s 2 (n) + (3/6)s 3 (n) + 0s 4 (n) + 0s 5 (n) + 0s 6 (n) = s 3 (n + 1)<br />
(1/6)s 1 (n) + (1/6)s 2 (n) + (1/6)s 3 (n) + (4/6)s 4 (n) + 0s 5 (n) + 0s 6 (n) = s 4 (n + 1)<br />
(1/6)s 1 (n) + (1/6)s 2 (n) + (1/6)s 3 (n) + (1/6)s 4 (n) + (5/6)s 5 (n) + 0s 6 (n) = s 5 (n + 1)<br />
(1/6)s 1 (n) + (1/6)s 2 (n) + (1/6)s 3 (n) + (1/6)s 4 (n) + (1/6)s 5 (n) + (6/6)s 6 (n) = s 6 (n + 1)<br />
We get this transition matrix.<br />
⎛<br />
⎞<br />
1/6 0 0 0 0 0<br />
1/6 2/6 0 0 0 0<br />
1/6 1/6 3/6 0 0 0<br />
⎜1/6 1/6 1/6 4/6 0 0<br />
⎟<br />
⎝1/6 1/6 1/6 1/6 5/6 0 ⎠<br />
1/6 1/6 1/6 1/6 1/6 6/6<br />
(b) This is the Octave session, with outputs edited out and condensed into the table at the end.<br />
octave:1> F=[1/6, 0, 0, 0, 0, 0;<br />
> 1/6, 2/6, 0, 0, 0, 0;<br />
> 1/6, 1/6, 3/6, 0, 0, 0;<br />
> 1/6, 1/6, 1/6, 4/6, 0, 0;<br />
> 1/6, 1/6, 1/6, 1/6, 5/6, 0;<br />
> 1/6, 1/6, 1/6, 1/6, 1/6, 6/6];<br />
octave:2> v0=[1;0;0;0;0;0]<br />
octave:3> v1=F*v0<br />
octave:4> v2=F*v1<br />
octave:5> v3=F*v2<br />
octave:6> v4=F*v3<br />
octave:7> v5=F*v4<br />
These are the results.<br />
1 2 3 4 5<br />
1<br />
0<br />
0<br />
0<br />
0<br />
0<br />
0.16667<br />
0.16667<br />
0.16667<br />
0.16667<br />
0.16667<br />
0.16667<br />
0.027778<br />
0.083333<br />
0.138889<br />
0.194444<br />
0.250000<br />
0.305556<br />
0.0046296<br />
0.0324074<br />
0.0879630<br />
0.1712963<br />
0.2824074<br />
0.4212963<br />
0.00077160<br />
0.01157407<br />
0.05015432<br />
0.13503086<br />
0.28472222<br />
0.51774691<br />
0.00012860<br />
0.00398663<br />
0.02713477<br />
0.10043724<br />
0.27019033<br />
0.59812243