Which Alice?
Which Alice?
Which Alice?
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Solutions to the Puzzles<br />
and that A is the spy; if Mr. Anthony answered negatively, then the<br />
friend would have been unable to know which of Cases 1b, 2a, 2b<br />
held, and could not have known whether A or B was the spy. So the<br />
only way that the first friend could have solved the problem is that<br />
Mr. Anthony answered affirmatively and that Case la holds.<br />
As to the second friend, if Mr. Anthony answered him affirmatively,<br />
then this friend would have known that Case 2a must hold<br />
and that A is the spy, but if Mr. Anthony answered him negatively,<br />
then the second friend couldn't have solved the problem. And so<br />
the only way the second friend could have solved the problem is<br />
that Case 2a holds and that Mr. Anthony answered him affirmatively.<br />
Now it cannot be that Case la and Case 2a both hold, and<br />
therefore Mr. Anthony could not have given an affirmative answer<br />
to both his friends, and so it is impossible that both friends were<br />
able to solve the problem. Therefore neither friend solved the<br />
problem (since we are given that either both did or neither did),<br />
and so Mr. Anthony did not answer either question affirmatively.<br />
This rules out Case la and Case 2a, so B must be the spy.<br />
Chapter 6<br />
THE FIRST QUESTION <strong>Alice</strong> made the mistake of writing<br />
eleven thousand eleven hundred and eleven as 11,111—which is<br />
wrong! 11,111 is eleven thousand, one hundred and eleven! To see<br />
the correct way of writing eleven thousand eleven hundred and<br />
eleven, add them up like this:<br />
So, eleven thousand eleven hundred and eleven is 12,111—which<br />
is exactly divisible by 3.