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Which Alice?

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Solutions to the Puzzles<br />

and that A is the spy; if Mr. Anthony answered negatively, then the<br />

friend would have been unable to know which of Cases 1b, 2a, 2b<br />

held, and could not have known whether A or B was the spy. So the<br />

only way that the first friend could have solved the problem is that<br />

Mr. Anthony answered affirmatively and that Case la holds.<br />

As to the second friend, if Mr. Anthony answered him affirmatively,<br />

then this friend would have known that Case 2a must hold<br />

and that A is the spy, but if Mr. Anthony answered him negatively,<br />

then the second friend couldn't have solved the problem. And so<br />

the only way the second friend could have solved the problem is<br />

that Case 2a holds and that Mr. Anthony answered him affirmatively.<br />

Now it cannot be that Case la and Case 2a both hold, and<br />

therefore Mr. Anthony could not have given an affirmative answer<br />

to both his friends, and so it is impossible that both friends were<br />

able to solve the problem. Therefore neither friend solved the<br />

problem (since we are given that either both did or neither did),<br />

and so Mr. Anthony did not answer either question affirmatively.<br />

This rules out Case la and Case 2a, so B must be the spy.<br />

Chapter 6<br />

THE FIRST QUESTION <strong>Alice</strong> made the mistake of writing<br />

eleven thousand eleven hundred and eleven as 11,111—which is<br />

wrong! 11,111 is eleven thousand, one hundred and eleven! To see<br />

the correct way of writing eleven thousand eleven hundred and<br />

eleven, add them up like this:<br />

So, eleven thousand eleven hundred and eleven is 12,111—which<br />

is exactly divisible by 3.

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