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Chapter 3: THE FRIEDMANN MODELS

Chapter 3: THE FRIEDMANN MODELS

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3.6.1 General solutions for R(τ)<br />

Before looking at general solutions to the Friedmann equation, it is useful to look at<br />

the asymptotic behaviour of models with general Ω. Setting Λ = 0, we may develop<br />

the Friedmann equation, using the relations between curvature and Ω (equation 3.27)<br />

and between R and z, as follows:<br />

(3.42)<br />

Thus<br />

R&<br />

R&<br />

R<br />

2<br />

2<br />

2<br />

0<br />

8π<br />

GρR<br />

kc<br />

= −<br />

3 R A<br />

3 2<br />

8π<br />

Gρ0R0<br />

= −( Ω −1)<br />

H<br />

3 R<br />

2 R0<br />

= H0<br />

Ω0<br />

−( Ω −1)<br />

H<br />

R<br />

2<br />

= H Ω ( 1+ z)<br />

− Ω + 1<br />

0<br />

2<br />

0 0<br />

2<br />

0 0<br />

2<br />

0 0<br />

(3.43)<br />

R&<br />

R<br />

2<br />

2<br />

= H ( 1 +Ω z)<br />

2 0<br />

0<br />

0<br />

Hence, if Ω 0 < 1, we can see that the Universe has had roughly constant & R (i.e. has<br />

had undecelerated expansion) since the epoch corresponding to (1+z) ~ Ω 0<br />

-1. At<br />

earlier times, & R behaves as for an Ω = 1 Universe (though, note, with a different H<br />

than the Ω 0 = 1 Universe that would have the same H 0 today).<br />

We can see this also by looking at Ω(z), which may be calculated as follows: From<br />

(3.43) we have<br />

2 2 2<br />

H = H ( 1+ z) ( 1+<br />

Ω z)<br />

0<br />

0<br />

Substituting this expression for H(z) into the definition of Ω and knowing ρ(R), we<br />

get<br />

Ω =<br />

=<br />

8πGρ<br />

2 2<br />

3H<br />

( 1+ z) ( 1+<br />

Ω z)<br />

0<br />

8πGρ<br />

( 1+<br />

z)<br />

0<br />

2<br />

3H<br />

( 1+<br />

Ω z)<br />

0<br />

0<br />

0<br />

Thus<br />

(3.44) Ω Ω ( 1 + z)<br />

=<br />

0<br />

( 1 + Ω z)<br />

0

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