Direct Torque Control with Space Vector Modulation (DTC-SVM) of ...
Direct Torque Control with Space Vector Modulation (DTC-SVM) of ...
Direct Torque Control with Space Vector Modulation (DTC-SVM) of ...
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Sensorless Speed <strong>Direct</strong> <strong>Torque</strong> <strong>Control</strong> <strong>with</strong> <strong>Space</strong> <strong>Vector</strong> <strong>Modulation</strong> (<strong>DTC</strong>-<strong>SVM</strong>)<br />
The first part <strong>of</strong> the equation represents a LP filter. The second part realizes a feedback,<br />
which is used to compensate the error in the output. The block diagram <strong>of</strong> new<br />
integration algorithm <strong>with</strong> saturation block is shown in see Fig. 6.11.<br />
I sA<br />
ABC<br />
Is<br />
α<br />
I sB<br />
αβ<br />
Is<br />
β<br />
R s<br />
ωc<br />
s +ω<br />
c<br />
Y lim<br />
− lim<br />
lim<br />
U sA<br />
U sB<br />
ABC<br />
αβ<br />
U<br />
s α<br />
U<br />
s β<br />
R s<br />
Es<br />
α<br />
Es<br />
β<br />
1<br />
s + ω c<br />
1<br />
s + ω c<br />
Ψ α _ comp<br />
Ψ s α<br />
Ψ sβ<br />
Ψ s<br />
θ Ψs<br />
Ψ<br />
s β _ comp<br />
ωc<br />
s +ω<br />
c<br />
Y lim<br />
− lim<br />
lim<br />
Figure 6.11. Full block diagram <strong>of</strong> voltage model based estimator <strong>with</strong> saturation block on the<br />
α,<br />
β components.<br />
The main task <strong>of</strong> saturation block is to stop the integration when the output signal<br />
Ψ<br />
sα<br />
or<br />
Ψ<br />
sβ<br />
exceed the reference value <strong>of</strong> stator flux amplitude. Please note that if the<br />
compensation signal is set to zero, the improved integrator represents a first-order LPfilter.<br />
If the compensation signal<br />
integrator operates as a pure integrator.<br />
Ψ or Ψ<br />
β _<br />
is not zero the improved<br />
sα<br />
_ comp<br />
s<br />
comp<br />
Discrete time implementation <strong>of</strong> the improved integrator becomes:<br />
ω<br />
zΨ ( z) =Ψ ( z) + ( U − R I ) T + ( Ψ ( z) −Ψ ( z))<br />
(6.16)<br />
c<br />
sα sα sα s sα s sα _lim<br />
sα<br />
Ts<br />
ω<br />
zΨ ( z) =Ψ ( z) + ( U − R I ) T + ( Ψ ( z) −Ψ ( z))<br />
(6.17)<br />
c<br />
sβ sβ sβ s sβ s sβ _lim<br />
sβ<br />
Ts<br />
The output <strong>of</strong> saturation block can be described as:<br />
⎧Ψ<br />
sαβ<br />
( z) if (Ψ<br />
sαβ(z))=lim<br />
sαβ<br />
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