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Direct Torque Control with Space Vector Modulation (DTC-SVM) of ...

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Sensorless Speed <strong>Direct</strong> <strong>Torque</strong> <strong>Control</strong> <strong>with</strong> <strong>Space</strong> <strong>Vector</strong> <strong>Modulation</strong> (<strong>DTC</strong>-<strong>SVM</strong>)<br />

The first part <strong>of</strong> the equation represents a LP filter. The second part realizes a feedback,<br />

which is used to compensate the error in the output. The block diagram <strong>of</strong> new<br />

integration algorithm <strong>with</strong> saturation block is shown in see Fig. 6.11.<br />

I sA<br />

ABC<br />

Is<br />

α<br />

I sB<br />

αβ<br />

Is<br />

β<br />

R s<br />

ωc<br />

s +ω<br />

c<br />

Y lim<br />

− lim<br />

lim<br />

U sA<br />

U sB<br />

ABC<br />

αβ<br />

U<br />

s α<br />

U<br />

s β<br />

R s<br />

Es<br />

α<br />

Es<br />

β<br />

1<br />

s + ω c<br />

1<br />

s + ω c<br />

Ψ α _ comp<br />

Ψ s α<br />

Ψ sβ<br />

Ψ s<br />

θ Ψs<br />

Ψ<br />

s β _ comp<br />

ωc<br />

s +ω<br />

c<br />

Y lim<br />

− lim<br />

lim<br />

Figure 6.11. Full block diagram <strong>of</strong> voltage model based estimator <strong>with</strong> saturation block on the<br />

α,<br />

β components.<br />

The main task <strong>of</strong> saturation block is to stop the integration when the output signal<br />

Ψ<br />

sα<br />

or<br />

Ψ<br />

sβ<br />

exceed the reference value <strong>of</strong> stator flux amplitude. Please note that if the<br />

compensation signal is set to zero, the improved integrator represents a first-order LPfilter.<br />

If the compensation signal<br />

integrator operates as a pure integrator.<br />

Ψ or Ψ<br />

β _<br />

is not zero the improved<br />

sα<br />

_ comp<br />

s<br />

comp<br />

Discrete time implementation <strong>of</strong> the improved integrator becomes:<br />

ω<br />

zΨ ( z) =Ψ ( z) + ( U − R I ) T + ( Ψ ( z) −Ψ ( z))<br />

(6.16)<br />

c<br />

sα sα sα s sα s sα _lim<br />

sα<br />

Ts<br />

ω<br />

zΨ ( z) =Ψ ( z) + ( U − R I ) T + ( Ψ ( z) −Ψ ( z))<br />

(6.17)<br />

c<br />

sβ sβ sβ s sβ s sβ _lim<br />

sβ<br />

Ts<br />

The output <strong>of</strong> saturation block can be described as:<br />

⎧Ψ<br />

sαβ<br />

( z) if (Ψ<br />

sαβ(z))=lim<br />

sαβ<br />

131

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