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Application Note AN-1077 - International Rectifier

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<strong>Application</strong> <strong>Note</strong> <strong>AN</strong>-<strong>1077</strong><br />

VOLTAGE FEEDBACK LOOP<br />

vˆ<br />

o<br />

VIN<br />

îchg<br />

r =<br />

RL<br />

C O<br />

RL<br />

d<br />

POWER STAGE<br />

G(s)<br />

VO<br />

Figure 11 - Small Signal low frequency model<br />

for the boost power stage<br />

OCC Modulator<br />

H3(s)<br />

vm<br />

VREF<br />

ERROR<br />

AMPLIFIER<br />

H2(s)<br />

VFB<br />

Figure 10 - Voltage Loop<br />

Output Divider<br />

H1(s)<br />

The open loop gain is given by the product:<br />

T<br />

1 2<br />

⋅<br />

3<br />

( s ) = G( s ) ⋅ H ( s ) ⋅ H ( s ) H ( s ) (25)<br />

OUTPUT DIVIDER: ( s )<br />

H 1<br />

The output divider scales the output voltage to be<br />

compared with the reference voltage in the error amplifier.<br />

Therefore:<br />

V<br />

OUT<br />

( RFB<br />

1<br />

+ RFB2<br />

+ RFB3)<br />

VREF<br />

= (26)<br />

R<br />

V<br />

H ( s ) =<br />

FB3<br />

REF<br />

1<br />

(27)<br />

Vo<br />

This stage simply attenuates the output voltage<br />

signal, by a fixed amount:<br />

H = 0.<br />

018 = 34.<br />

8dB<br />

1<br />

−<br />

POWER STAGE: H ( s ) ⋅G(<br />

s )<br />

The low frequency small signal equivalent circuit<br />

for the boost power stage is shown in Figure 11. An<br />

explanation of this model can be found in [7][8].<br />

3<br />

Definitions:<br />

R<br />

L<br />

: Load Resistance<br />

C<br />

O : Output (bulk) capacitor<br />

vˆ<br />

m<br />

: Modulation Voltage – this is the output of the Voltage<br />

Error Amplifier<br />

G<br />

DC<br />

: DC gain of the current amplifier – it is set internally<br />

the IC at 2.5V/V<br />

V : Peak value of input voltage (i.e. ⋅ 2<br />

in<br />

V )<br />

inRMS max<br />

For a constant power load the actual RL is negative.<br />

This is the typical case when the PFC load is a<br />

DC-DC stage: if the input voltage of that stage is reduced<br />

it will react by increasing the current, in order to<br />

maintain the output power constant.<br />

In this case R L will cancel with r and will yield:<br />

vˆ<br />

o<br />

1<br />

= (28)<br />

î sC<br />

chg<br />

When a purely resistive load is present we have:<br />

vˆ<br />

î<br />

o<br />

chg<br />

o<br />

RL<br />

/ 2<br />

= (29)<br />

RL<br />

1+<br />

sCo<br />

2<br />

We will not consider the resistive load case here,<br />

since in the majority of cases the PFC load is the input<br />

of another DC-DC converter.<br />

<strong>International</strong> <strong>Rectifier</strong> Technical Assistance Center: USA ++1 310 252 7105 Europe ++44 (0)208 645 8015 12 of 18

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