Application Note AN-1077 - International Rectifier
Application Note AN-1077 - International Rectifier
Application Note AN-1077 - International Rectifier
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<strong>Application</strong> <strong>Note</strong> <strong>AN</strong>-<strong>1077</strong><br />
VOLTAGE FEEDBACK LOOP<br />
vˆ<br />
o<br />
VIN<br />
îchg<br />
r =<br />
RL<br />
C O<br />
RL<br />
d<br />
POWER STAGE<br />
G(s)<br />
VO<br />
Figure 11 - Small Signal low frequency model<br />
for the boost power stage<br />
OCC Modulator<br />
H3(s)<br />
vm<br />
VREF<br />
ERROR<br />
AMPLIFIER<br />
H2(s)<br />
VFB<br />
Figure 10 - Voltage Loop<br />
Output Divider<br />
H1(s)<br />
The open loop gain is given by the product:<br />
T<br />
1 2<br />
⋅<br />
3<br />
( s ) = G( s ) ⋅ H ( s ) ⋅ H ( s ) H ( s ) (25)<br />
OUTPUT DIVIDER: ( s )<br />
H 1<br />
The output divider scales the output voltage to be<br />
compared with the reference voltage in the error amplifier.<br />
Therefore:<br />
V<br />
OUT<br />
( RFB<br />
1<br />
+ RFB2<br />
+ RFB3)<br />
VREF<br />
= (26)<br />
R<br />
V<br />
H ( s ) =<br />
FB3<br />
REF<br />
1<br />
(27)<br />
Vo<br />
This stage simply attenuates the output voltage<br />
signal, by a fixed amount:<br />
H = 0.<br />
018 = 34.<br />
8dB<br />
1<br />
−<br />
POWER STAGE: H ( s ) ⋅G(<br />
s )<br />
The low frequency small signal equivalent circuit<br />
for the boost power stage is shown in Figure 11. An<br />
explanation of this model can be found in [7][8].<br />
3<br />
Definitions:<br />
R<br />
L<br />
: Load Resistance<br />
C<br />
O : Output (bulk) capacitor<br />
vˆ<br />
m<br />
: Modulation Voltage – this is the output of the Voltage<br />
Error Amplifier<br />
G<br />
DC<br />
: DC gain of the current amplifier – it is set internally<br />
the IC at 2.5V/V<br />
V : Peak value of input voltage (i.e. ⋅ 2<br />
in<br />
V )<br />
inRMS max<br />
For a constant power load the actual RL is negative.<br />
This is the typical case when the PFC load is a<br />
DC-DC stage: if the input voltage of that stage is reduced<br />
it will react by increasing the current, in order to<br />
maintain the output power constant.<br />
In this case R L will cancel with r and will yield:<br />
vˆ<br />
o<br />
1<br />
= (28)<br />
î sC<br />
chg<br />
When a purely resistive load is present we have:<br />
vˆ<br />
î<br />
o<br />
chg<br />
o<br />
RL<br />
/ 2<br />
= (29)<br />
RL<br />
1+<br />
sCo<br />
2<br />
We will not consider the resistive load case here,<br />
since in the majority of cases the PFC load is the input<br />
of another DC-DC converter.<br />
<strong>International</strong> <strong>Rectifier</strong> Technical Assistance Center: USA ++1 310 252 7105 Europe ++44 (0)208 645 8015 12 of 18