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Partial Differential Equations - Modelling and ... - ResearchGate

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32 Yu.A. Kuznetsov<br />

3 Mixed Finite Element Method<br />

Let ∂ 0 E k,s be the part of the boundary ∂E k,s of a<br />

⋂<br />

polyhedral subcell E k,s<br />

belonging to the interior of E k , i.e. ∂ 0 E k,s = ∂E k,s Ek , s = 1,n k , k = 1,n.<br />

On ∂ 0 E k,s we define a set of t k,s non-overlapping flat polygons γ k,s,j which<br />

satisfies the following two conditions:<br />

1. ∂ 0 E k,s = ⋃ t k,s<br />

j=1 ¯γ k,s,j,<br />

2. each γ k,s,j belongs to ∂ 0 E k,s ′ for some s ′ ≠ s, s ′ ≤ n k ,<br />

where t k,s is a positive integer, s = 1,n k , k = 1,n.<br />

Examples of the partitionings of ∂ 0 E k,s into polygons γ k,s,j are given in<br />

Figures 3 <strong>and</strong> 4. In Figure 3, the interface ∂ 0 E k,1 = ∂ 0 E k,2 between E k,1<br />

<strong>and</strong> E k,2 consists of γ k,1 <strong>and</strong> γ k,2 . In Figure 4, ∂ 0 E k,1 consists of γ k,1,1 = γ 1 ,<br />

γ k,1,2 = γ 2 ,<strong>and</strong>γ k,1,3 = γ 3 ,<strong>and</strong>∂ 0 E k,2 consists of γ k,2,1 = γ 3 , γ k,2,2 = γ 4 ,<strong>and</strong><br />

γ k,2,3 = γ 5 . Finally, ∂ 0 E k,3 consists of γ k,3,1 = γ 1 , γ k,3,2 = γ 2 , γ k,3,3 = γ 4 ,<strong>and</strong><br />

γ k,3,4 = γ 5 .<br />

Let T h,k,s = {e k,s,i } be conforming tetrahedral partitionings of E k,s ,<br />

s = 1,n k , k = 1,n. The conformity of a tetrahedral partitioning (tetrahedral<br />

mesh) means that any two different intersecting closed tetrahedrons in<br />

T h,k,s have either a common vertex, or a common edge, or a common face.<br />

The boundaries ∂E k,s of E k,s are unions of polygons in {Γ k,i } <strong>and</strong> in<br />

{γ k,s,j }, s = 1,n k , k = 1,n. We assume that each of the tetrahedral meshes<br />

T h,k,s is also conforming with respect to the boundaries of polygons in {Γ k,i }<br />

<strong>and</strong> in {γ k,s,j } belonging to ∂E k,s , i.e. these boundaries belong to the union of<br />

E<br />

k, 1<br />

γ<br />

1<br />

γ<br />

2<br />

E<br />

k, 3<br />

γ<br />

3<br />

γ<br />

4<br />

E<br />

k, 2<br />

γ<br />

5<br />

Fig. 4. An example of partitionings ∂ 0E k,s into segments γ k,j,s , j = 1,t k , s = 1, 3

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