MV design guide - Schneider Electric
MV design guide - Schneider Electric
MV design guide - Schneider Electric
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Design rules<br />
Short-circuit currents<br />
Here is the solution<br />
to the problem with the<br />
calculation method<br />
Solving the exercise<br />
c Determining the various short-circuit currents<br />
The three sources which could supply power to the short-circuit are<br />
the two transformers and the alternator.<br />
We are supposing that there can be no feedback of power through<br />
D4, D5, D6 and D7.<br />
In the case of a short-circuit upstream of a circuit breaker (D1, D2,<br />
D3, D4, D5, D6, D7), this then has the short-circuit current flow<br />
through it supplied by T1, T2 and G1.<br />
c Equivalent diagram<br />
Each component comprises a resistance and an inductance.<br />
We have to calculate the values for each component.<br />
The network can be shown as follows:<br />
Zr = network impedance<br />
Za = alternator impedance different<br />
according to state<br />
(transient or subtransient)<br />
Z15 = transformer<br />
impedance 15 <strong>MV</strong>A<br />
Z20 = transformer<br />
impedance<br />
20 <strong>MV</strong>A<br />
busbars<br />
Experience shows that the resistance is generally low compared with,<br />
reactance, so we can therefore deduce that the reactance is equal to<br />
the impedance (X = Z).<br />
c To determine the short-circuit power, we have to calculate the<br />
various values of resistances and inductances,<br />
then separately calculate the arithmetic sum:<br />
Rt = R<br />
Xt = X<br />
c Knowing Rt and Xt, we can deduce the value of Zt by applying the<br />
equation:<br />
Z =<br />
( ∑R 2 + ∑X 2 )<br />
N.B.: Since R is negligible compared with X, we can say that Z = X.<br />
<strong>Schneider</strong> <strong>Electric</strong><br />
Merlin Gerin <strong>MV</strong> <strong>design</strong> <strong>guide</strong><br />
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