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MV design guide - Schneider Electric

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Design rules<br />

Short-circuit currents<br />

Here is the solution<br />

to the problem with the<br />

calculation method<br />

Solving the exercise<br />

c Determining the various short-circuit currents<br />

The three sources which could supply power to the short-circuit are<br />

the two transformers and the alternator.<br />

We are supposing that there can be no feedback of power through<br />

D4, D5, D6 and D7.<br />

In the case of a short-circuit upstream of a circuit breaker (D1, D2,<br />

D3, D4, D5, D6, D7), this then has the short-circuit current flow<br />

through it supplied by T1, T2 and G1.<br />

c Equivalent diagram<br />

Each component comprises a resistance and an inductance.<br />

We have to calculate the values for each component.<br />

The network can be shown as follows:<br />

Zr = network impedance<br />

Za = alternator impedance different<br />

according to state<br />

(transient or subtransient)<br />

Z15 = transformer<br />

impedance 15 <strong>MV</strong>A<br />

Z20 = transformer<br />

impedance<br />

20 <strong>MV</strong>A<br />

busbars<br />

Experience shows that the resistance is generally low compared with,<br />

reactance, so we can therefore deduce that the reactance is equal to<br />

the impedance (X = Z).<br />

c To determine the short-circuit power, we have to calculate the<br />

various values of resistances and inductances,<br />

then separately calculate the arithmetic sum:<br />

Rt = R<br />

Xt = X<br />

c Knowing Rt and Xt, we can deduce the value of Zt by applying the<br />

equation:<br />

Z =<br />

( ∑R 2 + ∑X 2 )<br />

N.B.: Since R is negligible compared with X, we can say that Z = X.<br />

<strong>Schneider</strong> <strong>Electric</strong><br />

Merlin Gerin <strong>MV</strong> <strong>design</strong> <strong>guide</strong><br />

19

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