23.02.2014 Views

MV design guide - Schneider Electric

MV design guide - Schneider Electric

MV design guide - Schneider Electric

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

Design rules<br />

Short-circuit currents<br />

Transformer<br />

In order to determine the short-circuit current across the terminals<br />

of a transformer, we need to know the short-circuit voltage (Usc %).<br />

c Usc % is defined in the following way:<br />

The short-circuit current depends on<br />

the type of equipment installed on<br />

the network (transformers,<br />

generators, motors, lines, etc).<br />

potentiometer<br />

U : 0 to Usc<br />

V<br />

primary<br />

secondary<br />

A<br />

I : 0 to Ir<br />

Example:<br />

c Transformer 20 <strong>MV</strong>A<br />

c Voltage 10 kV<br />

c Usc = 10 %<br />

c Upstream power: infinite<br />

Ir =<br />

Sr 20 000<br />

= = 1 150 A<br />

e U no-load e•10<br />

Isc =<br />

Ir<br />

=<br />

1 150<br />

= 11 500 A = 11.5 kA<br />

Usc 10÷100<br />

1 the voltage transformer is not powered: U = 0<br />

2 place the secondary in short-circuit<br />

3 gradually increase voltage U at the primary up to the rated current Ir in<br />

the transformer secondary circuit.<br />

The value U read across the primary is then equal to Usc<br />

c The short-circuit current, expressed in kA, is given by the following<br />

equation:<br />

Ir<br />

Isc =<br />

Usc<br />

<strong>Schneider</strong> <strong>Electric</strong><br />

Merlin Gerin <strong>MV</strong> <strong>design</strong> <strong>guide</strong><br />

13

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!