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Lectures notes for 2010 - KTH

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Bandwidth-Delay Product<br />

How large should the window be <strong>for</strong> optimal throughput?<br />

Calculate the capacity of the pipe as:<br />

• capacity(bits) = bandwidth(bits/sec) * RTT(sec)<br />

• This is the size the receiver advertised window should have <strong>for</strong> optimal<br />

throughput.<br />

Example:<br />

T1 connection across the US:<br />

capacity = 1.544Mbit/s * 60ms = 11,580 bytes<br />

Gigabit connection across the US:<br />

capacity = 1Gbit/s * 60ms = 7,500,000 bytes!<br />

However, the window size field is only 16 bits ⇒ maximum value of 65535 bytes<br />

For Long Fat Pipes we can use the window scale option to allow much larger<br />

window sizes.<br />

Maguire TCP header continued 5: 22 of 77<br />

maguire@kth.se <strong>2010</strong>.03.21 Internetworking/Internetteknik

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