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Equivariant Embeddings of Algebraic Groups

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that Γ(X, [I 2 , (1, 1)]) GL 2<br />

= {ε} and that the biequivariant resolution <strong>of</strong> X is β (X,[I2 ,(1,1)]) : G → X<br />

given by g ↦→ [g, (1, 1)].<br />

Second, while the cone Γ G is canonical, the morphism β (X,x0 ) : X G → X is only defined<br />

up to right translation, which corresponds to a different choice <strong>of</strong> base point x ∈ X as follows:<br />

r h (β (X,x0 )) = β (X,h·x0 ) : X G → X. This is true because the identification <strong>of</strong> k[X] with a subalgebra<br />

<strong>of</strong> k[G] is determined by the selection <strong>of</strong> a base point and changing the base point corresponds to<br />

right translation <strong>of</strong> the subalgebra in k[G] by Corollary 3. Then the morphism β (X,h·x0 ) : X G → X<br />

is defined by the inclusion <strong>of</strong> A Γ(X,h·x0 ) = r h (A Γ(X,x0 )) ⊂ A Γ G, from which it is clear that β (X,h·x0 ) =<br />

r h (β (X,x0 )).<br />

Proposition 11 (Universal Property <strong>of</strong> Biequivariant Resolutions). Suppose X is a left-<br />

G-equivariant affine G-embedding, x 0 ∈ X is a base point, Y is any (G × G)-equivariant affine<br />

G-embedding, and ϕ : Y → X is a left-G-equivariant morphism. Then there is a unique (G × G)-<br />

equivariant morphism ϕ (XG ,x 0 ) : Y → X G such that ϕ = β (X,x0 )◦ϕ (XG ,x 0 ). That is, the biequivariant<br />

resolution <strong>of</strong> X satisfies the following diagram:<br />

Y <br />

<br />

<br />

<br />

∀ ϕ<br />

X<br />

∃! ϕ (XG ,x 0 ) β (X,x0 )<br />

X G<br />

If x 1 = h · x 0 is another base point for X, then β (X,x1 ) = r h (β (X,x0 )) and ϕ (XG ,x 1 ) = r h −1(ϕ (XG ,x 0 )).<br />

Pro<strong>of</strong>. Let X be an affine G-embedding and identify k[X] with the left-invariant subalgebra A Γ(X,x0 )<br />

<strong>of</strong> k[G] by selecting a base point x 0 ∈ X. Suppose that Y is a (G × G)-equivariant affine G-<br />

embedding and that ϕ : Y → X is a left-G-equivariant morphism from Y to X. By equivariance,<br />

there is a unique element y 0 ∈ Y such that ϕ(y 0 ) = x 0 , since ϕ| ΩY<br />

: Ω Y → Ω X is an isomorphism<br />

with Ω Y<br />

∼ = ΩX ∼ = G. Then the cone Γ(Y, y0 ) is G-stable by Proposition 10 and is a subset <strong>of</strong><br />

Γ(X, x 0 ) by Proposition 9. Using y 0 , identify k[Y ] with the (G × G)-invariant subalgebra A Γ(Y,y0 )<br />

<strong>of</strong> k[G]. By Corollary 3, A Γ(Y,h·y0 ) = r h (A Γ(Y,y0 )) = A Γ(Y,y0 ), for all h ∈ G, so the algebra A Γ(Y,y0 ) is<br />

independent <strong>of</strong> the choice <strong>of</strong> base point. Hence it is the only subalgebra <strong>of</strong> k[G] which is isomorphic<br />

to k[Y ] as a (G × G)-algebra by Theorem 12.<br />

65

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