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Equivariant Embeddings of Algebraic Groups

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As x 0 is not zero, Ξ V,x0 (R) is a nonempty subset <strong>of</strong> X ∗ (R) for each torus R <strong>of</strong> G. Furthermore,<br />

if R 1 ⊂ R 2 is an inclusion <strong>of</strong> tori <strong>of</strong> G, then the eigendecomposition <strong>of</strong> x 0 with respect to R 2 is<br />

also the eigendecomposition with respect to R 1 whose weights are the restrictions <strong>of</strong> characters<br />

χ ∈ Ξ V,x0 (R 2 ) to R 1 , so the restriction property is true. Hence Ξ V,x0<br />

is a state.<br />

Let x 0 = ∑ v i be the eigendecomposition <strong>of</strong> x 0 with respect to a one-parameter subgroup γ <strong>of</strong><br />

G. Then γ(t)·x 0 = ∑ t i v i , where each v i ≠ 0 and i runs through a finite nonempty set I <strong>of</strong> integers,<br />

since X ∗ (G m ) ∼ = Z. Suppose R is a torus such that γ ∈ X ∗ (R). Then I = {〈χ, γ〉 : χ ∈ Ξ V,x0 (R)}<br />

by the definition <strong>of</strong> a state.<br />

As µ(Ξ V,x0 , γ) = min I, lim t→0 γ(t) · x 0 exists in V if and only if<br />

µ(Ξ V,x0 , γ) ≥ 0. Thus Γ(X, x 0 ) = Γ(V, x 0 ) = {γ ∈ X ∗ (G) : µ(Ξ V,x0 , γ) ≥ 0}.<br />

It may be shown that Ξ V,x0 is a bounded, admissible state. First <strong>of</strong> all, for any torus R and any<br />

vector v ∈ V , the set Ξ V,v (R) is contained in the set <strong>of</strong> R-weights <strong>of</strong> V , which is finite. Furthermore,<br />

observe that ∑ g · v χ is the eigendecomposition <strong>of</strong> g · x 0 with respect to R whenever ∑ v χ is the<br />

eigendecomposition <strong>of</strong> x 0 with respect to T = g −1 Rg, so<br />

Ξ V,g·x0 (R) = g ! (Ξ V,x0 (g −1 Rg)) = g ∗ Ξ V,x0 (R) (3.14)<br />

for all g ∈ G k . Thus, the union ⋃ g∈G k<br />

g ∗ Ξ V,x0 (R) is contained in the finite set <strong>of</strong> R-weights <strong>of</strong><br />

V , and hence is finite. Therefore, Ξ V,x0<br />

is bounded. Now let γ be any one-parameter subgroup<br />

<strong>of</strong> G. Let p be a k-point <strong>of</strong> P (γ) = {g ∈ G : γ(t)gγ(t −1 ) ∈ G k[[t]] }, the parabolic subgroup <strong>of</strong> G<br />

associated to γ. As P (γ) = P (p·γ ·p −1 ), it will be enough to prove that µ(Ξ V,x0 , γ) ≤ µ(Ξ V,x0 , p·γ ·<br />

p −1 ). We may think <strong>of</strong> µ(Ξ V,x0 , γ) as the largest integer n such that lim t→0 t −n γ(t)x 0 exists in V .<br />

Then lim t→0 t −n pγ(t)p −1 x 0 = p −1<br />

0 = lim t→0 t −n p(γ(t)p −1 γ(t −1 ))γ(t)x 0 = p[lim t→0 γ(t)p −1 γ(t −1 )] ·<br />

[lim t→0 t −n γ(t)x 0 ], which exists in V by Lemma 8. Therefore, µ(Ξ V,x0 , p · γ · p −1 ) is at least n, so<br />

Ξ V,x0<br />

is admissible, as claimed.<br />

To define Υ Y X,x 0<br />

, we use part 2 <strong>of</strong> Lemma 7, which says that there is an equivariant morphism<br />

f : X → W , for some G-representation W , such that Y = f −1 (0). Set Υ Y X,x 0<br />

equal to the<br />

state <strong>of</strong> the point f(x 0 ) in the vector space W , defined by (3.13) above. Therefore, Υ Y X,x 0<br />

is a<br />

bounded admissible state. Moreover, γ ∈ Γ(X, x 0 ) implies that γ ∈ Γ(W, f(x 0 )), so lim t→0 γ(t)x 0<br />

is contained in Y if and only if γ ∈ Γ(X, x 0 ) and lim t→0 γ(t)f(x 0 ) = 0 in W . Let f(x 0 ) = ∑ w i<br />

be the eigendecomposition <strong>of</strong> f(x 0 ) with respect to the action <strong>of</strong> γ, where the w i ≠ 0 and the sum<br />

50

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