11.01.2014 Views

Final Exam - Kalamazoo College

Final Exam - Kalamazoo College

Final Exam - Kalamazoo College

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

Math 320, Real Analysis I<br />

<strong>Final</strong> <strong>Exam</strong><br />

Part III: Taylor Series and Lagrange’s Remainder Theorem<br />

These questions are worth 10 points each, for a total of 30 points.<br />

Let f be infinitely differentiable on the interval (−R, R). Define a n = f (n) (0)<br />

n!<br />

let<br />

S N (x) = a 0 + a 1 x + a 2 x 2 + · · · + a N x N .<br />

for each n, and<br />

The polynomial S N (x) is a partial sum of the Taylor series expansion for the function f(x). Define<br />

E N (x) = f(x) − S N (x)<br />

which represents the error between f and the partial sum S N . Clearly proving S N (x) → f(x) is<br />

equivalent to showing E N (x) → 0.<br />

1. Explain why the error function E N (x) = f(x) − S N (x) satisfies<br />

for all n = 0, 1, 2, . . . , N.<br />

E (n)<br />

N (0) = 0<br />

2. Assume x > 0 and consider the functions E N (x) and x N+1 on the interval [0, x]. Show that<br />

there exists a point x 1 ∈ (0, x) such that<br />

E N (x)<br />

x N+1 = E′ N (x 1)<br />

(N + 1)x N 1<br />

3. Prove Lagrange’s Remainder Theorem, which states:<br />

Let f be infinitely differentiable on (−R, R), define a n = f (n) (0)/n!, and let<br />

S N (x) = a 0 + a 1 x + a 2 x 2 + · · · + a N x N .<br />

Given x ≠ 0, there exists a point c satisfying |c| < |x| where the error function<br />

E N (x) = f(x) − S N (x) satisfies<br />

.<br />

E N (x) = f (N+1) (c)<br />

(N + 1)!<br />

x N+1 .<br />

Part IV: Arzelà-Ascoli Theorem<br />

Question 1 is worth 5 points while the remaining questions are 10 points each, so this section is<br />

worth a total of 45 points.<br />

Recall the Bolzano-Weierstrass Theorem (Theorem 2.5.5) states that every bounded sequence<br />

of real numbers has a convergent subsequence. An analogous statement for bounded sequences<br />

of functions is not true in general. (See Part I, Problem 4.) Under stronger hypotheses,<br />

however, we can derive a Bolzano-Weierstrass Theorem for sequences of functions. First, we make<br />

the following definition:<br />

A sequence of functions (f n ) defined on a set E ⊆ R is called equicontinuous if for every<br />

ε > 0 there exists a δ > 0 such that<br />

for all n ∈ N and |x − y| < δ in E.<br />

|f n (x) − f n (y)| < ε

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!