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242 Chapter 3 Exponential and Logarithmic Functions<br />

t 21,<br />

t 12,<br />

9. Since A 7500e rt and A 15,000 when<br />

10. Since A 1000e rt and A 2000 when we<br />

15,000 7500e 21r 2000 1000e 12r<br />

we have the following.<br />

have the following.<br />

2 e 21r<br />

ln 2 21r<br />

r ln 2<br />

21<br />

Amount after 10 years:<br />

0.033 3.3%<br />

A 7500e 0.03310 $10,432.26<br />

2 e 12r<br />

ln 2 12r<br />

r ln 2<br />

12<br />

0.058 5.8%<br />

Amount after 10 years:<br />

A 1000e 0.05810 $1786.04<br />

11. Since A 5000e rt and A 5665.74 when<br />

t 10, we have the following.<br />

5665.74 5000e 10r<br />

5665.74<br />

5000 e10r<br />

ln <br />

5665.74<br />

5000 10r<br />

The time to double is given by<br />

10,000 5000e 0.0125t<br />

2 e 0.0125t<br />

ln 2 0.0125t<br />

r 1 10 ln 5665.74<br />

5000 <br />

0.0125 1.25%<br />

t ln 2 55.5 years.<br />

0.0125<br />

12. Since A 300e rt and A 385.21 when<br />

t 10, we have the following.<br />

385.21 300e 10r<br />

385.21<br />

300 e10r<br />

ln <br />

385.21<br />

300 10r<br />

The time to double is given by<br />

600 300e 0.025t<br />

2 e 0.025t<br />

ln 2 0.025t<br />

r 1 10 ln 385.21<br />

300 <br />

0.025 2.5%<br />

t ln 2 27.7 years.<br />

0.025<br />

13. Since A Pe 0.045t and A 100,000 when t 10,<br />

we have the following.<br />

100,000 Pe 0.04510<br />

100,000<br />

e 0.45 P 63,762.82<br />

The time to double is given by<br />

127,525.64 63,762.82e 0.045t<br />

2 e 0.045t<br />

ln 2 0.045t<br />

t ln 2 15.4 years.<br />

0.045<br />

14. Since A Pe 0.02t and A 2500 when t 10, we<br />

have the following.<br />

2500 Pe 0.0210<br />

2500<br />

P $2046.83<br />

e0.02 The time to double is given by<br />

4093.66 2046.83e 0.02t<br />

2 e 0.02t<br />

ln 2 0.02t<br />

t ln 2 34.7 years.<br />

0.02<br />

© Houghton Mifflin Company. All rights reserved.

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