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Section 3.5 Exponential and Logarithmic Models 241<br />

Section 3.5<br />

Exponential and Logarithmic Models<br />

■<br />

■<br />

■<br />

■<br />

■<br />

You should be able to solve compound interest problems.<br />

1.<br />

2.<br />

A P 1 r n nt<br />

A Pe rt<br />

You should be able to solve growth and decay problems.<br />

(a) Exponential growth if b > 0 and y ae bx .<br />

(b) Exponential decay if b > 0 and y ae bx .<br />

You should be able to use the Gaussian model<br />

y ae xb2 c .<br />

You should be able to use the logistics growth model<br />

a<br />

y <br />

1 be .<br />

xcd<br />

You should be able to use the logarithmic models<br />

y lnax b and y log 10 ax b.<br />

Vocabulary Check<br />

1. (a) iv (b) i (c) vi (d) iii (e) vii (f) ii (g) v<br />

2. Normally 3. Sigmoidal 4. Bell-shaped, mean<br />

1. y 2e x4 2. y 6e x4<br />

3.<br />

This is an exponential<br />

growth model.<br />

Matches graph (c).<br />

This is an exponential decay<br />

model.<br />

Matches graph (e).<br />

y 6 log 10 x 2<br />

This is a logarithmic model,<br />

and contains 1, 6.<br />

Matches graph (b).<br />

© Houghton Mifflin Company. All rights reserved.<br />

4. y 3e x22 5 5. y lnx 1<br />

6.<br />

4<br />

y <br />

1 e 2x<br />

Gaussian model<br />

This is a logarithmic model.<br />

Logistics model<br />

Matches (a).<br />

Matches graph (d).<br />

Matches (f ).<br />

7. Since A 10,000e 0.035t , the time to double is<br />

8. Since A 2000e 0.015t , the time to double is<br />

given by<br />

given by<br />

20,000 10,000e 0.035t<br />

2 e 0.035t<br />

ln 2 0.035t<br />

t ln 2 19.8 years.<br />

0.035<br />

Amount after 10 years:<br />

A 10,000e 0.03510 $14,190.68<br />

4000 2000e 0.015t<br />

2 e 0.015t<br />

ln 2 0.015t<br />

t ln 2 46.2 years.<br />

0.015<br />

Amount after 10 years:<br />

A 2000e 0.01510 $2323.67

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