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Section 3.5 Exponential and Logarithmic Models 241<br />
Section 3.5<br />
Exponential and Logarithmic Models<br />
■<br />
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■<br />
You should be able to solve compound interest problems.<br />
1.<br />
2.<br />
A P 1 r n nt<br />
A Pe rt<br />
You should be able to solve growth and decay problems.<br />
(a) Exponential growth if b > 0 and y ae bx .<br />
(b) Exponential decay if b > 0 and y ae bx .<br />
You should be able to use the Gaussian model<br />
y ae xb2 c .<br />
You should be able to use the logistics growth model<br />
a<br />
y <br />
1 be .<br />
xcd<br />
You should be able to use the logarithmic models<br />
y lnax b and y log 10 ax b.<br />
Vocabulary Check<br />
1. (a) iv (b) i (c) vi (d) iii (e) vii (f) ii (g) v<br />
2. Normally 3. Sigmoidal 4. Bell-shaped, mean<br />
1. y 2e x4 2. y 6e x4<br />
3.<br />
This is an exponential<br />
growth model.<br />
Matches graph (c).<br />
This is an exponential decay<br />
model.<br />
Matches graph (e).<br />
y 6 log 10 x 2<br />
This is a logarithmic model,<br />
and contains 1, 6.<br />
Matches graph (b).<br />
© Houghton Mifflin Company. All rights reserved.<br />
4. y 3e x22 5 5. y lnx 1<br />
6.<br />
4<br />
y <br />
1 e 2x<br />
Gaussian model<br />
This is a logarithmic model.<br />
Logistics model<br />
Matches (a).<br />
Matches graph (d).<br />
Matches (f ).<br />
7. Since A 10,000e 0.035t , the time to double is<br />
8. Since A 2000e 0.015t , the time to double is<br />
given by<br />
given by<br />
20,000 10,000e 0.035t<br />
2 e 0.035t<br />
ln 2 0.035t<br />
t ln 2 19.8 years.<br />
0.035<br />
Amount after 10 years:<br />
A 10,000e 0.03510 $14,190.68<br />
4000 2000e 0.015t<br />
2 e 0.015t<br />
ln 2 0.015t<br />
t ln 2 46.2 years.<br />
0.015<br />
Amount after 10 years:<br />
A 2000e 0.01510 $2323.67