Lecture 2 Piecewise-linear optimization
Lecture 2 Piecewise-linear optimization
Lecture 2 Piecewise-linear optimization
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sufficiency: suppose A satisfies the nullspace condition<br />
• let ˆx be k-sparse with support I (i.e., with P Iˆx = ˆx); define y = Aˆx<br />
• consider any feasible x (i.e., satisfying Ax = y), different from ˆx<br />
• define z = x− ˆx; this is a nonzero vector in nullspace(A)<br />
‖x‖ 1 = ‖ˆx+z‖ 1<br />
≥ ‖ˆx+z −P I z‖ 1 −‖P I z‖ 1<br />
= ∑ k∈I<br />
|ˆx k |+ ∑ k∉I<br />
|z k |−‖P I z‖ 1<br />
= ‖ˆx‖ 1 +‖z‖ 1 −2‖P I z‖ 1<br />
> ‖ˆx‖ 1<br />
(line 2 is the triangle inequality; the last line is the nullspace condition)<br />
therefore ˆx = argmin Ax=y ‖x‖ 1<br />
<strong>Piecewise</strong>-<strong>linear</strong> <strong>optimization</strong> 2–18