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Nitrating Methyl Benzoate: Electrophilic Aromatic ... - Franklin College

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<strong>Nitrating</strong> <strong>Methyl</strong> <strong>Benzoate</strong>: <strong>Electrophilic</strong> <strong>Aromatic</strong> Substitution<br />

Part 5 – Melting Points and Infrared Spectrum<br />

Prepare a melting point capillary of the recrystallized product and take its melting point. Also, perform an infrared<br />

spectrum on the recrystallized product. Do this by adding 100 mg KBR to approximately 1mg of the recrystallized<br />

product. Mix the two using a mortar and pestle, being sure to grind the two compounds into a fine powder. Place some<br />

of this mixture in a microcup, making sure the surface is smooth. Then place the pellet in the infrared spectrometer<br />

and obtain an infrared spectrum of the product.<br />

Part 5 – Clean Up<br />

Place all waste materials in their appropriate waste containers.<br />

Data and Calculations:<br />

Mass methyl benzoate used: 0.554 g<br />

Mass recrystallized crystals: 0.413 g<br />

Percent Yield: 56.42%<br />

Melting Point recrystallized product: 77.5 - 80°C<br />

Literature Value: 78 - 80°C<br />

Finding Limiting Reagent<br />

HNO3 (0.5 mL HNO3) (1.5027 g HNO3) (1 mol HNO3) (1 mol methyl nitrobenzoate) (181.3 g methyl nitrobenzoate)<br />

(1 mL HNO3) (63.01 g HNO3) (1 mol HNO3) (1 mol methyl nitrobenzoate)<br />

= 2.159 g methyl nitrobenzoate<br />

H2SO4 (0.6 mL H2SO4) (1.841 g H2SO4) (1 mol H2SO4) (1 mol methyl nitrobenzoate) (181.3 g methyl nitrobenzoate)<br />

(1 mL H2SO4) (98.08 g H2SO4) (1 mol H2SO4) (1 mol methyl nitrobenzoate)<br />

= 2.039 g methyl nitrobenzoate<br />

<strong>Methyl</strong> <strong>Benzoate</strong> (0.554 g methyl benzoate) (1 mol methyl benzoate) (1 mol methyl nitrobenzoate) (181.13 g methyl nitrobenzoate)<br />

(136.15 g methyl benzoate) (1 mol methyl benzoate) (1 mol methyl nitrobenzoate)<br />

= 0.732 g methyl nitrobenzoate<br />

The limiting reagent for this electrophilic aromatic substitution reaction is methyl benzoate. It yields the least amount of<br />

methyl nitrobenzoate in this reaction, and therefore is the limiting reagent.<br />

Theoretical Yield<br />

(0.554 g methyl benzoate) (1 mol methyl benzoate) (1 mol methyl nitrobenzoate) (181.13 g methyl nitrobenzoate)<br />

(136.15 g methyl benzoate) (1 mol methyl benzoate) (1 mol methyl nitrobenzoate)<br />

= 0.732 g methyl nitrobenzoate<br />

Percent Yield<br />

For recrystallized product (mass of recrystallized methyl nitrobenzoate) (0.413 g methyl nitrobenzoate) x (100) =<br />

(theoretical yield) (0.732 g methyl nitrobenzoate)<br />

=56.42% yield

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