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REV Atomic and Nuclear

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<strong>Atomic</strong> Physics<br />

<strong>and</strong><br />

Quantum Effects<br />

A photon is a particle of light. It has no mass, but can<br />

transfer energy to <strong>and</strong> from electrons.<br />

To determine the energy of a photon: E = hf<br />

To determine the momentum of a photon: p = h<br />

λ<br />

To determine the wavelength of a photon:<br />

start with E = hf, then use v = fλ<br />

1


E = 0 eV<br />

E3 = ­6 eV<br />

E2 = ­7 eV<br />

E1 = ­10 eV<br />

<strong>Atomic</strong> Energy Levels<br />

E1 is called the ground state<br />

E = 0 eV<br />

E3 = ­6 eV<br />

E2 = ­7 eV<br />

E1 = ­10 eV<br />

Electrons in an atoms can have<br />

only certain amounts of<br />

energy. To move up levels an<br />

electron must absorb an exact<br />

amount of energy from a<br />

photon <strong>and</strong> to drop down an<br />

energy level, the electron emits<br />

a photon with a specific<br />

amount of energy.<br />

How can an electron get<br />

from the ground state to<br />

level 3?<br />

It could either absorb 4 eV<br />

from a single photon OR it<br />

could first absorb 3 eV from<br />

one photon <strong>and</strong> then 1 eV<br />

from a second photon.<br />

What if an electron absorbs 10 eV of energy? It leaves the<br />

atom. This is called ionization energy.<br />

2


The Photoelectric Effect<br />

Light energy striking a metal surface can cause the metal to<br />

eject one of its electrons, but only if the frequency of the<br />

incident light is above a certain value.<br />

The minimum frequency of light needed is called the cutoff<br />

frequency.<br />

The metal surface is described by its work function (φ).<br />

Work function (φ) is calculated by (φ) = hfo<br />

The Photoelectric Effect<br />

of the<br />

electrons<br />

KEmax = E ­ φ<br />

Energy of the<br />

incident photons<br />

Work Function<br />

of the metal<br />

remember, Ephoton = hf <strong>and</strong> φ = hfo<br />

KEmax = hf ­ hfo<br />

3


Stopping Potential<br />

KEmax = qVo<br />

if KEmax is expressed in eV, then stopping potential is that<br />

same value expressed in Volts <strong>and</strong> vice versa.<br />

From here, we can calculate the velocity of the ejected<br />

electrons: KEmax = 1/2mv 2<br />

mass of electron<br />

de Broglie Wavelength (Matter Waves)<br />

λ = h<br />

mv<br />

Compton Scattering<br />

Photons collide with electrons, transferring some energy<br />

to the electron, electron now has velocity (KE), photon<br />

loses energy, thus is wavelength is lengthened.<br />

4


Three Types of Subatomic Particles:<br />

(1) Alpha α 2 protons & 2 neutrons stuck together<br />

(2) Beta β + or β ­<br />

(3) Gamma γ a photon<br />

The Three Decay Processes:<br />

either + or ­ electron<br />

(1) Alpha emits one alpha particle, mass number drops<br />

by 4, charge drops by 2<br />

4<br />

2α<br />

(2) Beta Decay either an electron or positron is emitted.<br />

No change in mass, charge either increases or<br />

decreases by 1.<br />

e + 0<br />

+1<br />

e ­ 0<br />

­1<br />

(3) Gamma a photon is emitted which results in no<br />

change in outward appearance. Emitted photon has KE,<br />

where did it come from? Change in mass during the<br />

decay process.<br />

5


15<br />

8 O decays via B + emission. Which of the<br />

following is the resulting nucleus?<br />

a)<br />

b)<br />

c)<br />

15<br />

9 F<br />

16<br />

8 O<br />

15<br />

7<br />

N<br />

d)<br />

e)<br />

16<br />

9<br />

16<br />

7 N<br />

F<br />

6


Identify the missing particle in the nuclear reaction below:<br />

13<br />

6 C + ( ? )<br />

a) electron<br />

b) proton<br />

c) deuteron<br />

d) positron<br />

e) gamma photon<br />

13<br />

7 N + n<br />

Mass Defect<br />

Think about each of the decay processes; in each process,<br />

a particle is ejected (really, really fast). The remaining<br />

nucleus has to recoil to conserve momentum. Now, both<br />

particles are moving. Originally, there was no KE, now<br />

there's a bunch. Where did it come from?<br />

Before the decay, there was more mass than after. During<br />

the decay some of the mass was converted into energy.<br />

E = Δmc 2<br />

7


from your h<strong>and</strong>out in class:<br />

10

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